/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 46 True or false: (a) \(\mathrm{C... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

True or false: (a) \(\mathrm{CBr}_{4}\) is more volatile than \(\mathrm{CCl}_{4}\). (b) \(\mathrm{CBr}_{4}\) has a higher boiling point than \(\mathrm{CCl}_{4}\). (c) \(\mathrm{CBr}_{4}\) has weaker intermolecular forces than \(\mathrm{CCl}_{4}\). (d) \(\mathrm{CBr}_{4}\) has a higher vapor pressure at the same temperature than \(\mathrm{CCl}_{4}\)

Short Answer

Expert verified
(a) False (b) True (c) False (d) False

Step by step solution

01

(a) Determine the volatility of \(\mathrm{CBr}_{4}\) and \(\mathrm{CCl}_{4}\)

Volatility is the tendency of a substance to vaporize. Molecules with weaker intermolecular forces tend to be more volatile than those with stronger intermolecular forces. The intermolecular forces present in both \(\mathrm{CBr}_{4}\) and \(\mathrm{CCl}_{4}\) are London dispersion forces, which are determined by the molecular size and polarizability. Since Br atoms are larger and more polarizable than Cl atoms, we can expect the London dispersion forces in \(\mathrm{CBr}_{4}\) to be stronger than those in \(\mathrm{CCl}_{4}\). Hence, \(\mathrm{CBr}_{4}\) would be less volatile than \(\mathrm{CCl}_{4}\). So the statement (a) is false.
02

(b) Compare the boiling points of \(\mathrm{CBr}_{4}\) and \(\mathrm{CCl}_{4}\)

Boiling point is directly related to the intermolecular forces between the molecules. Since we determined that \(\mathrm{CBr}_{4}\) has stronger London dispersion forces than \(\mathrm{CCl}_{4}\) due to the larger size and polarizability of Br atoms, we can infer that \(\mathrm{CBr}_{4}\) has a higher boiling point than \(\mathrm{CCl}_{4}\). So the statement (b) is true.
03

(c) Analyze the intermolecular forces of \(\mathrm{CBr}_{4}\) and \(\mathrm{CCl}_{4}\)

As discussed earlier, the intermolecular forces in both compounds are London dispersion forces, which rely on the molecular size and polarizability. Since Br atoms are larger and more polarizable than Cl atoms, we can infer that \(\mathrm{CBr}_{4}\) has stronger intermolecular forces than \(\mathrm{CCl}_{4}\). So the statement (c) is false.
04

(d) Compare the vapor pressures of \(\mathrm{CBr}_{4}\) and \(\mathrm{CCl}_{4}\) at the same temperature

Vapor pressure is the pressure exerted by a vapor in equilibrium with its condensed phase. It is inversely related to the intermolecular forces of the substance. As we have established that \(\mathrm{CBr}_{4}\) has stronger intermolecular forces than \(\mathrm{CCl}_{4}\), it will have a lower vapor pressure at the same temperature. So the statement (d) is false.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

(a) Silicon is the fundamental component of integrated circuits. Si has the same structure as diamond. Is \(\mathrm{Si}\) a molecular, metallic, ionic, or covalent-network solid? (b) Silica is \(\mathrm{SiO}_{2}\). What type of solid would you expect silica to form?

(a) When you exercise vigorously, you sweat. How does this help your body cool? (b) A flask of water is connected to a vacuum pump. A few moments after the pump is turned on, the water begins to boil. After a few minutes, the water begins to freeze. Explain why these processes occur.

It is possible to change the temperature and pressure of a vessel containing argon gas so that the gas solidifies. (a) What intermolecular forces exist between argon atoms? (b) Is the solid argon a "covalent network solid"? Why or why not?

(a) What atoms must a molecule contain to participate in hydrogen bonding with other molecules of the same kind? (b) Which of the following molecules can form hydrogen bonds with other molecules of the same kind: \(\mathrm{CH}_{3} \mathrm{~F}, \mathrm{CH}_{3} \mathrm{NH}_{2}, \mathrm{CH}_{3} \mathrm{OH}, \mathrm{CH}_{3} \mathrm{Br} ?\)

(a) What is meant by the term polarizability? (b) Which of the following atoms would you expect to be most polarizable: \(\mathrm{N}, \mathrm{P}, \mathrm{As}, \mathrm{Sb}\) ? Explain. (c) Put the following molecules in order of increasing polarizability: \(\mathrm{GeCl}_{4}, \mathrm{CH}_{4}\) \(\mathrm{SiCl}_{4}, \mathrm{SiH}_{4}\), and \(\mathrm{GeBr}_{4}\). (d) Predict the order of boiling points of the substances in part (c).

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.