/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 69 (a) What is the empirical formul... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 24: Problem 69

(a) What is the empirical formula of cellulose? (b) What is the monomer that forms the basis of the cellulose polymer? (c) What bond connects the monomer units in cellulose: amide, acid, ether, ester, or alcohol?

Short Answer

Expert verified
(a) The empirical formula of cellulose is \(C_{12}H_{22}O_{11}\). (b) The monomer that forms the basis of the cellulose polymer is glucose. (c) The bond that connects the monomer units in cellulose is an ether bond (specifically, a 尾(1鈫�4) glycosidic linkage).

Step by step solution

01

Determine the empirical formula of cellulose

Cellulose is a polymer made up of repeating glucose units. The empirical formula of glucose is \(C_6H_{12}O_6\). For cellulose, however, we must consider the empirical composition of glucose but lose one molecule of water in the process that occurs when two glucose units are combined (dehydration synthesis). The empirical formula of cellulose can be calculated by subtracting 1 molecule of water from 2 molecules of glucose: 2 x (Glucose) - (Water) = Cellulose 2 x (C_6H_{12}O_6) - H_2O = Cellulose \(C_{12}H_{24}O_{12} - H_2O = C_{12}H_{22}O_{11}\) Thus, the empirical formula of cellulose is \(C_{12}H_{22}O_{11}\).
02

Identify the monomer that forms the basis of the cellulose polymer

Cellulose is a carbohydrate polymer that consists of a repeated single unit, or monomer. In this case, the monomer is glucose, which is a simple sugar or monosaccharide. The glucose units are chemically linked by a specific type of bond, which is addressed in the next step.
03

Determine the bond connecting the monomer units in cellulose

Cellulose is formed when two glucose molecules react and lose a water molecule, creating a new bond between the glucose units. The type of bond formed between the glucose units is known as an ether bond, specifically a 尾(1鈫�4) glycosidic linkage, which is an oxygen atom that connects two carbon atoms, one from each glucose molecule. By following these steps, we can conclude that: (a) The empirical formula of cellulose is \(C_{12}H_{22}O_{11}\). (b) The monomer that forms the basis of the cellulose polymer is glucose. (c) The bond that connects the monomer units in cellulose is an ether bond (specifically, a 尾(1鈫�4) glycosidic linkage).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Draw the condensed structures of the compounds formed from (a) butanoic acid and methanol, ( b) benzoic acid and 2-propanol, (c) propanoic acid and dimethylamine. Name the compound in each case.

Give the general formula for any cyclic alkene, that is, a cyclic hydrocarbon with one double bond.

Write the condensed structural formulas for two alkenes and one alkyne that all have the molecular formula \(\mathrm{C}_{6} \mathrm{H}_{10}\) .

(a) When cyclopropane is treated with HI, 1 -i-iodopropane is formed. A similar type of reaction does not occur with cyclopentane or cyclohexane. Suggest an explanation for cyclopropane's reactivity. (b) Suggest a method of preparing ethylbenzene, starting with benzene and ethylene as the only organic reagents.

(a) Draw the condensed structural formulas for the cis and trans isomers of 2 -pentene. (b) Can cyclopentene exhibit cis-trans isomerism? Explain. (c) Does 1 -pentyne have enantiomers? Explain.
See all solutions

Recommended explanations on Chemistry Textbooks

Kinetics

Read Explanation

Inorganic Chemistry

Read Explanation

Nuclear Chemistry

Read Explanation

Making Measurements

Read Explanation

Ionic and Molecular Compounds

Read Explanation

Chemical Analysis

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.