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Write balanced equations for the following reactions: (a) barium oxide with water, (b) iron(II) oxide with perchloric acid, (c) sulfur trioxide with water, (d) carbon dioxide with aqueous sodium hydroxide.

Short Answer

Expert verified
(a) Balanced equation: \(BaO + H_2O \rightarrow Ba(OH)_2\) (b) Balanced equation: \(2FeO + 4HClO_4 \rightarrow 2Fe(ClO_4)_2 + 2H_2O\) (c) Balanced equation: \(SO_3 + H_2O \rightarrow H_2SO_4\) (d) Balanced equation: \(CO_2 + NaOH \rightarrow NaHCO_3\)

Step by step solution

01

(a) Balancing the equation for the reaction of barium oxide with water

Write the unbalanced equation: BaO + H2O -> Ba(OH)2 Now, balance the equation by making sure there are equal numbers of atoms of each element on both sides of the equation. In this case, the equation is already balanced. Balanced equation: BaO + H2O -> Ba(OH)2
02

(b) Balancing the equation for the reaction of iron(II) oxide with perchloric acid

Write the unbalanced equation: FeO + HClO4 -> Fe(ClO4)2 + H2O To balance this equation, adjust the coefficients of the reactants and products. Balanced equation: 2FeO + 4HClO4 -> 2Fe(ClO4)2 + 2H2O
03

(c) Balancing the equation for the reaction of sulfur trioxide with water

Write the unbalanced equation: SO3 + H2O -> H2SO4 Now, balance the equation by making sure there are equal numbers of atoms of each element on both sides of the equation. In this case, the equation is already balanced. Balanced equation: SO3 + H2O -> H2SO4
04

(d) Balancing the equation for the reaction of carbon dioxide with aqueous sodium hydroxide

Write the unbalanced equation: CO2 + NaOH -> NaHCO3 Now, balance the equation by making sure there are equal numbers of atoms of each element on both sides of the equation. In this case, the equation is already balanced. Balanced equation: CO2 + NaOH -> NaHCO3

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Reactions
Chemical reactions are the processes by which substances interact to form new substances with different properties. Each reaction involves the rearrangement of atoms and is governed by the laws of conservation of mass and energy. This means in a chemical reaction, the total mass of the reactants equals the total mass of the products. Reactions are depicted by chemical equations that represent the identities and quantities of the reactants and products involved.

Writing and balancing these equations requires a clear understanding of the reaction specifics, including the physical state of substances, the reaction conditions, and the stoichiometry of the reaction. In balancing equations, it is crucial to ensure that there is an equal number of atoms for each element on both sides of the equation, reflecting the conservation of matter.
Stoichiometry
Stoichiometry is the branch of chemistry that deals with the quantitative relationships between reactants and products in a chemical reaction. It is the mathematical aspect of chemistry that pertains to the mass and mole relationships among reactants and products. Understanding stoichiometry allows chemists to predict the quantities needed to react and the amounts produced. When balancing chemical equations, stoichiometry is key in determining the coefficients that make the number of atoms of each element equal on both sides of the equation. It involves the use of mole ratios, derived from the balanced equation, to calculate the mass, volume, or number of particles of substances involved.
Reaction of Barium Oxide with Water
The reaction of barium oxide with water is an example of a chemical reaction where a base reacts with water to form a hydroxide. This particular type of reaction is synonymous with the behavior of alkaline earth metals. The balanced equation for this reaction is:
\[ BaO + H_2O \rightarrow Ba(OH)_2 \]
This shows that barium oxide (BaO) combines with water (H2O) to form barium hydroxide (Ba(OH)2). In this case, the stoichiometry is straightforward, with a one-to-one-to-one mole ratio among BaO, H2O, and Ba(OH)2 respectively. This reaction is important in understanding how basic oxides interact with water, forming hydroxides as products.
Reaction of Iron(II) Oxide with Perchloric Acid
Iron(II) oxide reacts with perchloric acid to produce iron(II) perchlorate and water. The balancing of this equation involves adjusting the coefficients to obey the law of conservation of mass. The balanced chemical equation is:
\[ 2FeO + 4HClO_4 \rightarrow 2Fe(ClO_4)_2 + 2H_2O \]
This reaction is a type of acid-base reaction, where iron(II) oxide (a basic oxide) neutralizes perchloric acid. Perchlorates are the salts formed when perchloric acid reacts with bases. Stoichiometry is illustrated here by the different coefficients needed for reactants to ensure that the number of each type of atom is conserved across both sides of the equation.
Reaction of Sulfur Trioxide with Water
When sulfur trioxide reacts with water, sulfuric acid is formed. This is a synthesis reaction, which can be represented by the balanced chemical equation seen below:
\[ SO_3 + H_2O \rightarrow H_2SO_4 \]
In this balanced equation, one molecule of sulfur trioxide (SO3) reacts with one molecule of water (H2O) to produce one molecule of sulfuric acid (H2SO4). It’s an exothermic and highly spontaneous reaction that is significant in the industrial production of sulfuric acid. The stoichiometry is shown here by the straightforward one-to-one ratio of reactants to products, indicating that no further adjustment is necessary for balancing the atoms.
Reaction of Carbon Dioxide with Aqueous Sodium Hydroxide
The reaction of carbon dioxide (CO2) with aqueous sodium hydroxide (NaOH) produces sodium bicarbonate (NaHCO3). This chemical equation represents a type of reaction known as a neutralization reaction, which occurs between an acid and a base. The balanced chemical equation for this reaction is:
\[ CO_2 + NaOH \rightarrow NaHCO_3 \]
This equation indicates that one mole of CO2 reacts with one mole of NaOH to produce one mole of NaHCO3. In terms of stoichiometry, this reaction also illustrates a one-to-one-to-one ratio. Understanding this reaction is critical for many environmental and industrial processes, such as carbon capture and sequestration, and the manufacture of baking soda.

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Most popular questions from this chapter

Using only the periodic table, arrange each set of atoms in (b) \(\mathrm{Sn}, \mathrm{Sb}, \mathrm{As} ;(\mathbf{c}) \mathrm{Al},\) order of increasing radius: (a) \(\mathrm{Ba}, \mathrm{Ca}, \mathrm{Na} ;\) Be, Si.

Some ions do not have a corresponding neutral atom that has the same electron configuration. For each of the following ions, identify the neutral atom that has the same number of electrons and determine if this atom has the same electron configuration. If such an atom does not exist, explain why. (b) \(\mathrm{Sc}^{3+}\) (d) \(\mathrm{Zn}^{2+},(\mathrm{e}) \mathrm{Sn}^{4+}\) (a) \(\mathrm{Cl}\) (c) \(\mathrm{Fe}^{2+}\)

Write a balanced equation for the reaction that occurs in each of the following cases: (a) Cesium is added to water. (b) Strontium is added to water. (c) Sodium reacts with oxygen. (d) Calcium reacts with iodine.

Use electron configurations to explain the following observations: (a) The first ionization energy of phosphorus is greater than that of sulfur. (b) The electron affinity of nitrogen is lower (less negative) than those of both carbon and oxygen. (c) The second ionization energy of oxygen is greater than the first ionization energy of fluorine. (d) The third ionization energy of manganese is greater than those of both chromium and iron.

Hydrogen is an unusual element because it behaves in some ways like the alkali metal elements and in other ways like nonmetals. Its properties can be explained in part by its electron configuration and by the values for its ionization energy and electron affinity, (a) Explain why the electron affinity of hydrogen is much closer to the values for the alkali elements than for the halogens. (b) Is the following statement true? "Hydrogen has the smallest bonding atomic radius of any element that forms chemical compounds." If not, correct it. If it is, explain in terms of electron configurations. (c) Explain why the ionization energy of hydrogen is closer to the values for the halogens than for the alkali metals. (d) The hydride ion is \(\mathrm{H}\). Write out the process corresponding to the first ionization energy of hydride. (e) How does the process you wrote in part (d) compare to the process for the electron affinity of elemental hydrogen?

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