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Write electron configurations for the following ions, and determine which have noble-gas configurations: (a) \(\mathrm{Cr}^{3+}\), (b) \(\mathrm{N}^{3-},(\mathrm{c}) \mathrm{Sc}^{3+},(\mathrm{d}) \mathrm{Cu}^{2+}\) (e) \(\mathrm{Tl}^{+}\), (f) \(\mathrm{Au}^{+}\).

Short Answer

Expert verified
The electron configurations for the given ions are: (a) \(\mathrm{Cr}^{3+}\): \(1s虏2s虏2p鈦3s虏3p鈦3d鲁\) (Not a noble-gas configuration) (b) \(\mathrm{N}^{3-}\): \(1s虏2s虏2p鈦禱) (Noble-gas configuration) (c) \(\mathrm{Sc}^{3+}\): \(1s虏2s虏2p鈦3s虏3p鈦禱) (Noble-gas configuration) (d) \(\mathrm{Cu}^{2+}\): \(1s虏2s虏2p鈦3s虏3p鈦3d鹿鈦癨) (Noble-gas configuration) (e) \(\mathrm{Tl}^{+}\): \(1蝉虏2蝉虏2辫鈦3蝉虏3辫鈦4蝉虏3诲鹿鈦4p鈦5s虏4d鹿鈦5p鈦6s虏5d鹿鈦6p鈦礬) (Noble-gas configuration) (f) \(\mathrm{Au}^{+}\): \(1蝉虏2蝉虏2辫鈦3蝉虏3辫鈦4蝉虏3诲鹿鈦4p鈦5s虏4d鹿鈦5p鈦6s鹿4f鹿鈦5d鈦筡) (Not a noble-gas configuration) The ions with noble-gas configurations are: \(\mathrm{N}^{3-}\), \(\mathrm{Sc}^{3+}\), \(\mathrm{Cu}^{2+}\), and \(\mathrm{Tl}^{+}\).

Step by step solution

01

(a) Determine electron configuration for \(\mathrm{Cr}^{3+}\)

First, we need to find the atomic number of Chromium (Cr). From the periodic table, Cr has an atomic number of 24. In its neutral state, it has the same number of electrons; therefore, the electron configuration for Cr is: 1s虏2s虏2p鈦3s虏3p鈦4s虏3d鈦 However, Cr鈦郝 has lost three electrons. When an atom loses electrons, the first electrons to be removed are from the highest energy level, which is 4s in this case. Thus, the electron configuration for Cr鲁鈦 is: 1s虏2s虏2p鈦3s虏3p鈦3d鲁
02

(a) Identify if the electron configuration for \(\mathrm{Cr}^{3+}\) is noble-gas

Comparing this electron configuration with the noble gas configurations, we notice that it is not a noble-gas configuration because it does not end with a full set of 2, 8, 18, 32, etc. electrons in each shell or subshell.
03

(b) Determine the electron configuration for \(\mathrm{N}^{3-}\)

The atomic number of Nitrogen (N) is 7. So, the electron configuration for N is: 1s虏2s虏2p鲁 As the ion is N鲁鈦, it means it has gained three extra electrons (total of 10 electrons). So, the new electron configuration for \(\mathrm{N}^{3-}\) is: 1s虏2s虏2p鈦
04

(b) Identify if the electron configuration for \(\mathrm{N}^{3-}\) is noble-gas

Comparing this electron configuration with the noble gas configurations, we notice that it has a noble-gas configuration, which is the same as Neon (Ne). Perform similar tasks for the given ions:
05

(c) Determine electron configuration for \(\mathrm{Sc}^{3+}\)

1蝉虏2蝉虏2辫鈦3蝉虏3辫鈦4蝉虏3诲鹿
06

(c) Identify if the electron configuration for \(\mathrm{Sc}^{3+}\) is noble-gas

It has a noble-gas configuration, which is the same as Argon (Ar).
07

(d) Determine electron configuration for \(\mathrm{Cu}^{2+}\)

1蝉虏2蝉虏2辫鈦3蝉虏3辫鈦4蝉鹿3诲鹿鈦
08

(d) Identify if the electron configuration for \(\mathrm{Cu}^{2+}\) is noble-gas

It has a noble-gas configuration, which is the same as Argon (Ar).
09

(e) Determine electron configuration for \(\mathrm{Tl}^{+}\)

1蝉虏2蝉虏2辫鈦3蝉虏3辫鈦4蝉虏3诲鹿鈦4p鈦5s虏4d鹿鈦5p鈦6s虏5d鹿鈦6p鈦
10

(e) Identify if the electron configuration for \(\mathrm{Tl}^{+}\) is noble-gas

It has a noble-gas configuration, which is the same as Xenon (Xe).
11

(f) Determine electron configuration for \(\mathrm{Au}^{+}\)

1蝉虏2蝉虏2辫鈦3蝉虏3辫鈦4蝉虏3诲鹿鈦4p鈦5s虏4d鹿鈦5p鈦6s鹿4f鹿鈦5d鈦
12

(f) Identify if the electron configuration for \(\mathrm{Au}^{+}\) is noble-gas

It does not have a noble-gas configuration. So, the ions with noble-gas configurations are: \(\mathrm{N}^{3-}\), \(\mathrm{Sc}^{3+}\), \(\mathrm{Cu}^{2+}\), and \(\mathrm{Tl}^{+}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Noble-Gas Configuration
A noble-gas configuration is an electron arrangement that mirrors the stable structure of a noble gas. These are the gases like Helium, Neon, and Argon, which have full outer electron shells. Having a complete outer shell is associated with maximum stability.

Noble-gas configurations make atoms less reactive. Elements tend to gain or lose electrons to achieve this stable arrangement. For example, when \(\mathrm{N}^{3-}\) gains three electrons, its configuration mimics that of Neon: \(\mathrm{1s}^2 2s^2 2p^6\).

Understanding which ions have noble-gas configurations helps predict their stability and reactivity. In the given exercise, \(\mathrm{N}^{3-}, \mathrm{Sc}^{3+}, \mathrm{Cu}^{2+}, and \mathrm{Tl}^{+}\) all have noble-gas configurations.
Ions
Ions are atoms or molecules that have gained or lost electrons, resulting in a net charge. When an atom gains electrons, it becomes negatively charged and is called an anion. If it loses electrons, it becomes positively charged, known as a cation.

For instance, \(\mathrm{Cr}^{3+}\) is a cation. It originally has 24 electrons, but after losing 3 electrons, it ends up with 21. Understanding ion formation is essential in determining their electron configurations.
  • Anions, like \(\mathrm{N}^{3-}\), gain electrons and often achieve noble-gas configurations.
  • Cations may or may not reach noble-gas configurations, depending on how many electrons are lost.
Periodic Table
The periodic table is a crucial tool for predicting elements' properties, including electron configurations. It arranges elements in increasing atomic numbers and groups with similar properties.

Each element's position tells you about its electron configuration, especially the arrangement of electrons in the outermost shells. For example, Chromium (Cr) in group 6 has its electrons spread over several sub-levels: \(\mathrm{1s^2 2s^2 2p^6 3s^2 3p^6 4s^1 3d^5}\).

Looking at the periodic table allows you to deduce the changes in electron configurations when elements form ions. Reading group numbers can help predict the number of electrons lost or gained for elements to reach a noble-gas configuration.
Electron Configuration Steps
Writing electron configurations involves understanding the order in which electrons fill subshells, based on increasing atomic number. Electrons fill orbitals starting from the lowest energy (1s) and move to higher energies.

Here's a basic layout:
  • 1s is filled first, followed by 2s, 2p, 3s, 3p, 4s, and then 3d.
  • Higher atomic numbers fill electrons in a more complex sequence, but the basic pattern repeats periodically.
For ions, remember:
  • Electrons are added to the lowest available energy level for anions.
  • Electrons are removed from the highest occupied energy level for cations.
Let鈥檚 consider \(\mathrm{Cu}^{2+}\). It loses two electrons, resulting in the configuration \(\mathrm{1s^2 2s^2 2p^6 3s^2 3p^6 3d^{10}}\), which is a noble-gas configuration.

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Most popular questions from this chapter

(a) As described in Section \(7.7,\) the alkali metals react with hydrogen to form hydrides and react with halogens- for example, fluorine to form halides, Compare the roles of hydrogen and the halogen in these reactions. How are the forms of hydrogen and halogen in the products alike? (b) Write balanced equations for the reaction of fluorine with calcium and for the reaction of hydrogen with calcium. What are the similarities among the products of these reactions?

(a) Write the electron configuration for \(\mathrm{Li}\), and estimate the effective nuclear charge experienced by the valence electron. (b) The energy of an electron in a one-electron atom or ion equals \(\left(-2.18 \times 10^{-18} \mathrm{~J}\right)\left(\frac{Z^{2}}{n^{2}}\right)\) where \(Z\) is the nuclear charge and \(n\) is the principal quantum number of the electron. Estimate the first ionization energy of Li. (c) Compare the result of your calculation with the value reported in Table 7.4 and explain the difference. (d) What value of the effective nuclear charge gives the proper value for the ionization energy? Does this agree with your explanation in \((\mathrm{c}) ?\)

Some metal oxides, such as \(\mathrm{Sc}_{2} \mathrm{O}_{3},\) do not react with pure water, but they do react when the solution becomes either acidic or basic. Do you expect \(\mathrm{Sc}_{2} \mathrm{O}_{3}\) to react when the solution becomes acidic or when it becomes basic? Write a balanced chemical equation to support your answer.

In the chemical process called electron transfer, an electron is transferred from one atom or molecule to another. (We will talk about electron transfer extensively in Chapter 20.) A simple electron transfer reaction is $$ \mathrm{A}(g)+\mathrm{A}(g) \longrightarrow \mathrm{A}^{+}(g)+\mathrm{A}^{-}(g) $$ In terms of the ionization energy and electron affinity of atom A, what is the energy change for this reaction? For a representative nonmetal such as chlorine, is this process exothermic? For a representative metal such as sodium, is this process exothermic? [Sections 7.4 and 7.5\(]\)

One way to measure ionization energies is ultraviolet photoelectron spectroscopy (UPS, or just PES), a technique based on the photoelectric effect. coo (Section 6.2 ) In PES, monochromatic light is directed onto a sample, causing electrons to be emitted. The kinetic energy of the emitted electrons is measured. The difference between the energy of the photons and the kinetic energy of the electrons corresponds to the energy needed to remove the electrons (that is, the ionization energy). Suppose that a PES experiment is performed in which mercury vapor is irradiated with ultraviolet light of wavelength \(58.4 \mathrm{nm}\). (a) What is the energy of a photon of this light in eV? (b) Write an equation that shows the process corresponding to the first ionization energy of \(\mathrm{Hg}\). (c) The kinetic energy of the emitted electrons is measured to be \(10.75 \mathrm{eV}\). What is the first ionization energy of Hg in kJ/mol? (d) Using Figure 7.9 , determine which of the halogen elements has a first ionization energy closest to that of mercury.

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