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(a) How is the concept of effective nuclear charge used to simplify the numerous electron-electron repulsions in a manyelectron atom? (b) Which experiences a greater effective nuclear charge in a Be atom, the 1 s electrons or the 2 s electrons? Explain.

Short Answer

Expert verified
The concept of effective nuclear charge (Z_eff) simplifies electron-electron repulsions in many-electron atoms by focusing on the net positive charge experienced by each electron, instead of considering all individual repulsions. In a Beryllium (Be) atom with the electron configuration \(1s^{2}2s^{2}\), the 1s electrons experience a greater effective nuclear charge (Z_eff = 4) compared to the 2s electrons (Z_eff = 2), due to their proximity to the nucleus and the absence of any shielding effect from other electrons. In contrast, the 2s electrons are shielded by the two 1s electrons, reducing the net positive charge they experience.

Step by step solution

01

Define the concept of effective nuclear charge

The effective nuclear charge (Z_eff) is the net positive charge experienced by an electron in a multi-electron atom after taking into account the shielding or screening effect of the other electrons in the atom. It represents an approximation of the actual nuclear charge that an electron feels in the presence of electron-electron repulsions.
02

Explain the importance of effective nuclear charge

In many-electron atoms, electron-electron repulsions occur between all of the electrons. Considering all of these interactions is computationally intensive, and difficult to work with. The concept of effective nuclear charge simplifies this problem by focusing on the net positive charge experienced by each electron, instead of individually considering all the electron-electron repulsions. This allows for a simpler and effective way to tackle complex atomic problems and to understand the behavior of electrons in an atom.
03

Determine the electron configuration of Beryllium

Before comparing the effective nuclear charge felt by the 1s and 2s electrons in a Beryllium atom, we need to know its electron configuration. Beryllium has an atomic number of 4, which means it has 4 protons and 4 electrons. The electron configuration for Beryllium is: \(1s^{2}2s^{2}\), showcasing there are two electrons in both the 1s and 2s orbitals.
04

Calculate the effective nuclear charge for 1s and 2s electrons

To determine which electrons experience a greater effective nuclear charge in Beryllium, we need to consider the shielding effect. Shielding is the phenomenon where inner electrons partially block the pull of the nucleus on outer electrons. For 1s electrons: The actual nuclear charge (Z) is 4, as there are four protons in the nucleus. There are no inner electrons, so the shielding effect (S) is 0. Hence, the effective nuclear charge (\(Z_{eff}\)) is equal to the actual nuclear charge: \(Z_{eff} = Z - S = 4 - 0 = 4\). For 2s electrons: The actual nuclear charge (Z) is still 4, but now there are two inner electrons (1s electrons) causing shielding. For simplicity, let's approximate the shielding effect (S) to be equal to the number of inner electrons: S = 2. Hence, the effective nuclear charge (\(Z_{eff}\)) is: \(Z_{eff} = Z - S = 4 - 2 = 2\).
05

Compare the effective nuclear charges and provide an explanation

The 1s electrons experience an effective nuclear charge of 4, while 2s electrons experience an effective nuclear charge of 2. Therefore, the 1s electrons experience a greater effective nuclear charge in a Beryllium atom. The reason for this difference is that the 1s electrons are closer to the nucleus and do not experience any shielding effect from other electrons, whereas the 2s electrons are shielded by the two 1s electrons, reducing the net positive charge they experience.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electron-Electron Repulsions
The term 'electron-electron repulsions' refers to the forces of repulsion between negatively charged electrons in an atom. When dealing with multiple electrons in an atom, it's important to understand that these electrons repel each other due to their like charges. This can significantly affect an electron's experience of the nuclear charge.

However, factoring in each individual electron's interaction with one another can become immensely complex. To simplify this complexity, scientists introduce the concept of effective nuclear charge (\(Z_{eff}\)). This is a simplified way to assess the net positive charge an electron feels, negating the need to consider all possible interactions with every other electron.

In essence, the calculation of the effective nuclear charge allows us to understand how the electrons in outer shells are influenced by those in the inner shells, thus painting a clearer picture of an electron's behavior within the busy electron 'cloud' of an atom.
Shielding Effect
The shielding effect is a key concept when discussing effective nuclear charge. It describes the reduction in the attractive force between the nucleus and an electron, due to the presence of other electrons in between them. These intervening electrons not only repel each other but also reduce the full impact of the nuclear charge on those electrons that are farther from the nucleus.

To visualize this, imagine the nucleus of an atom as a light source, and the electrons in the inner shells as a series of opaque screens. Electrons in outer shells would only perceive a dimmed light due to the screens in between. Similarly, in an atomic context, inner electrons 'screen' or 'shield' outer electrons from the full force of the nuclear charge.

As a result, when calculating the effective nuclear charge (\(Z_{eff}\)), the shielding effect is represented by subtracting the shielding constant (usually denoted as 'S') from the actual nuclear charge (Z). This simplified model is especially useful when comparing the effective nuclear charges on electrons in different shells, as was depicted in the discussion of beryllium's 1s and 2s electrons.
Beryllium Electron Configuration
Understanding the electron configuration of elements, such as Beryllium, is fundamental when studying the effective nuclear charge. Beryllium, with an atomic number of 4, has the electron configuration of \(1s^{2}2s^{2}\).

This tells us that beryllium has two electrons in the innermost shell (1s) and two in the second shell (2s). Since the 1s electrons are closer to the nucleus, they experience a stronger attraction – full nuclear charge without any shielding. The 2s electrons, however, are not only further away but are also shielded by the 1s electrons, thus experiencing a lesser effective nuclear charge.

The step-by-step comparison of the effective nuclear charge felt by 1s and 2s electrons in Beryllium clearly illustrates the difference in their experiences. Understanding this concept is crucial, especially when exploring properties such as atomic size, ionization energy, and electronegativity, which are greatly influenced by the effective nuclear charge experienced by the outermost electrons.

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Most popular questions from this chapter

Until the early 1960 s the group 8 A elements were called the inert gases; before that they were called the rare gases. The term rare gases was dropped after it was discovered that argon accounts for roughly \(1 \%\) of Earth's atmosphere. (a) Why was the term inert gases dropped? (b) What discovery triggered this change in name? (c) What name is applied to the group now?

Hydrogen is an unusual element because it behaves in some ways like the alkali metal elements and in other ways like nonmetals. Its properties can be explained in part by its electron configuration and by the values for its ionization energy and electron affinity, (a) Explain why the electron affinity of hydrogen is much closer to the values for the alkali elements than for the halogens. (b) Is the following statement true? "Hydrogen has the smallest bonding atomic radius of any element that forms chemical compounds." If not, correct it. If it is, explain in terms of electron configurations. (c) Explain why the ionization energy of hydrogen is closer to the values for the halogens than for the alkali metals. (d) The hydride ion is \(\mathrm{H}\). Write out the process corresponding to the first ionization energy of hydride. (e) How does the process you wrote in part (d) compare to the process for the electron affinity of elemental hydrogen?

When magnesium metal is burned in air (Figure 3.6 ), two products are produced. One is magnesium oxide, \(\mathrm{MgO}\). The other is the product of the reaction of \(\mathrm{Mg}\) with molecular nitrogen, magnesium nitride. When water is added to magnesium nitride, it reacts to form magnesium oxide and ammonia gas. (a) Based on the charge of the nitride ion (Table 2.5 ), predict the formula of magnesium nitride. (b) Write a balanced equation for the reaction of magnesium nitride with water. What is the driving force for this reaction? (c) In an experiment a piece of magnesium ribbon is burned in air in a crucible. The mass of the mixture of \(\mathrm{MgO}\) and magnesium nitride after burning is \(0.470 \mathrm{~g}\). Water is added to the crucible, further reaction occurs, and the crucible is heated to dryness until the final product is \(0.486 \mathrm{~g}\) of \(\mathrm{MgO}\). What was the mass percentage of magnesium nitride in the mixture obtained after the initial burning? (d) Magnesium nitride can also be formed by reaction of the metal with ammonia at high temperature. Write a balanced equation for this reaction. If a 6.3 -g Mg ribbon reacts with \(2.57 \mathrm{~g} \mathrm{NH}_{3}(g)\) and the reaction goes to completion, which component is the limiting reactant? What mass of \(\mathrm{H}_{2}(g)\) is formed in the reaction? (e) The standard enthalpy of formation of solid magnesium nitride is \(-461.08 \mathrm{~kJ} / \mathrm{mol} .\) Calculate the standard enthalpy change for the reaction between magnesium metal and ammonia gas.

Write a balanced equation for the reaction that occurs in each of the following cases: (a) Ozone decomposes to dioxygen. (b) Xenon reacts with fluorine. (Write three different equations.) (c) Sulfur reacts with hydrogen gas. (d) Fluorine reacts with water.

In April \(2010,\) a research team reported that they had made Element 117 . The report has yet to be confirmed. Write out Element 117's ground-state electron configuration, and estimate values for its first ionization energy, electron affinity, atomic size, and common oxidation state based on its position in the periodic table.

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