/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 98 Manganese silicide has the empir... [FREE SOLUTION] | 91影视

91影视

Manganese silicide has the empirical formula MnSi and melts at \(1280^{\circ} \mathrm{C}\). It is insoluble in water but does dissolve in aqueous HF. (a) What type of compound do you expect MnSi to be: metallic, molecular, covalent-network, or ionic? (b) Write a likely balanced chemical equation for the reaction of \(\mathrm{MnSi}\) with concentrated aqueous \(\mathrm{HF}\).

Short Answer

Expert verified
MnSi is a molecular compound. The balanced chemical equation for the reaction of MnSi with concentrated aqueous HF is: MnSi (s) + 6 HF (aq) 鈫 Mn虏鈦 (aq) + 2 F鈦 (aq) + SiF鈧 (g)

Step by step solution

01

Identifying the type of compound MnSi

First, we need to identify the type of compound MnSi is. We're given that it has an empirical formula MnSi, melts at 1280掳C, is insoluble in water, and does dissolve in aqueous HF. Mn (Manganese) is a transition metal while Si (Silicon) is a non-metal. Based on this, we can eliminate metallic (as it would involve metal atoms only) and ionic (which requires a metal and a non-metal with a significant electronegativity difference). Between molecular and covalent-network, covalent-network compounds are usually comprised of non-metallic elements. Since Mn is a transition metal and generally forms metallic bonds with other elements, the compound MnSi should be categorized as molecular.
02

Writing a balanced chemical equation for the reaction of MnSi with concentrated aqueous HF

Next, we need to write a balanced chemical equation for the reaction of MnSi with concentrated aqueous HF. MnSi is able to dissolve in aqueous HF, so we can assume that it reacts with HF to form products. Since Mn is a metal and can form positive ions, it is likely to form Mn(II) ions (Mn虏鈦). Silicon will form SiF鈧 upon reaction with HF: MnSi (s) + 6 HF (aq) 鈫 Mn虏鈦 (aq) + 2 F鈦 (aq) + SiF鈧 (g) Here, we have a balanced chemical equation: 1 MnSi reacts with 6 HF molecules to form 1 Mn虏鈦 ion, 2 F鈦 ions, and 1 SiF鈧 molecule.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Empirical Formula
The empirical formula represents the simplest whole-number ratio of the elements within a compound. It's like a recipe that gives the most basic version without the actual quantity. For instance, the empirical formula of manganese silicide is MnSi, indicating that for every atom of manganese (Mn), there's one atom of silicon (Si). However, it does not tell us how many of these pairs are in a single molecule.

Understanding the empirical formula is crucial because it is the starting point to determine the molecular formula, which shows the actual number of atoms in a molecule. When students tackle exercises involving empirical formulas, they need to be adept at recognizing how to simplify the ratios derived from the atomic or molar masses to their simplest form. By mastering this concept, students ensure that their basic understanding of chemical composition is solid, forming an essential foundation for more complex chemistry topics.
Covalent-Network Compounds
Covalent-network compounds are structures where atoms are bonded covalently in a continuous network extending throughout the material. Unlike discrete molecules, they form large 3D structures, such as diamonds or quartz. These compounds are characterized by high melting points and hardness and are generally poor conductors of electricity.

Manganese silicide, MnSi, based on its properties鈥攈igh melting point and insolubility in water鈥攃ould be mistaken for a covalent-network compound. However, the presence of manganese, a metal, suggests that the bonding in MnSi does not fit the typical covalent-network compounds, which are usually made of non-metal elements. As such, in the exercise improvement advice, it would be beneficial to highlight the distinctions between the different compound types more clearly, to avoid confusion. By exploring why MnSi does not qualify as a covalent-network compound, students gain a deeper understanding of the properties associated with different types of chemical bonding.
Balanced Chemical Equation
A balanced chemical equation is like a detailed accounting equation, but for chemistry. It ensures that the number of atoms for each element is the same on both sides of the reaction, adhering to the Law of Conservation of Mass. In the exercise given, MnSi reacts with aqueous HF to form manganese(II) ions, fluoride ions, and silicon tetrafluoride gas. The equation is balanced by making sure the same number of each type of atom appears on both the reactant and product side.

In the context of the exercise, optimizing the students' comprehension of how to balance equations is vital. By practicing with the coefficients in the equation鈥攍ike putting a '6' in front of HF to ensure there are enough fluorine atoms to balance the products鈥攕tudents enhance their skills in stoichiometry. Learning how to properly balance chemical equations is an essential skill in chemistry that has wide applications, such as predicting the amounts of substances consumed and produced in reactions and understanding reaction stoichiometry.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Explain the following observations: (a) For a given oxidation state, the acid strength of the oxyacid in aqueous solution decreases in the order chlorine \(>\) bromine \(>\) iodine. (b) Hydrofluoric acid cannot be stored in glass bottles. (c) HI cannot be prepared by treating NaI with sulfuric acid. (d) The interhalogen \(\mathrm{ICl}_{3}\) is known, but \(\mathrm{BrCl}_{3}\) is not.

Identify the following hydrides as ionic, metallic, or molecular: (a) \(\mathrm{BaH}_{2},\) (b) \(\mathrm{H}_{2} \mathrm{Te},\) (c) \(\mathrm{TiH}_{1.7}\).

Write a chemical formula for each compound or ion, and indicate the oxidation state of the group \(5 \mathrm{~A}\) element in each formula: (a) phosphate ion, (b) arsenous acid, (c) antimony(III) sulfide, (d) calcium dihydrogen phosphate, (e) potassium phosphide, (f) gallium arsenide.

Explain each of the following observations: (a) At room temperature \(\mathrm{I}_{2}\) is a solid, \(\mathrm{Br}_{2}\) is a liquid, and \(\mathrm{Cl}_{2}\) and \(\mathrm{F}_{2}\) are both gases. (b) \(\mathrm{F}_{2}\) cannot be prepared by electrolytic oxidation of aqueous \(\mathrm{F}^{-}\) solutions. (c) The boiling point of \(\mathrm{HF}\) is much higher than those of the other hydrogen halides. (d) The halogens decrease in oxidizing power in the order \(\mathrm{F}_{2}>\mathrm{Cl}_{2}>\mathrm{Br}_{2}>\mathrm{I}_{2}\)

Write the chemical formula for each of the following compounds, and indicate the oxidation state of nitrogen in each: (a) nitric oxide, (b) hydrazine, (c) potassium cyanide, (d) sodium nitrite, (e) ammonium chloride, (f) lithium nitride.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.