/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 60 Write a chemical formula for eac... [FREE SOLUTION] | 91影视

91影视

Write a chemical formula for each compound or ion, and indicate the oxidation state of the group \(5 \mathrm{~A}\) element in each formula: (a) phosphate ion, (b) arsenous acid, (c) antimony(III) sulfide, (d) calcium dihydrogen phosphate, (e) potassium phosphide, (f) gallium arsenide.

Short Answer

Expert verified
The chemical formulas and oxidation states for the given compounds and ions are: (a) Phosphate ion: \(\text{PO}_{4}^{3-}\) (Phosphorus oxidation state: +5) (b) Arsenous acid: \(\text{H}_{3}\text{AsO}_{3}\) (Arsenic oxidation state: +3) (c) Antimony(III) sulfide: \(\text{Sb}_{2}\text{S}_{3}\) (Antimony oxidation state: +3) (d) Calcium dihydrogen phosphate: \(\text{Ca(H}_{2}\text{PO}_{4})_{2}\) (Phosphorus oxidation state: +5) (e) Potassium phosphide: \(\text{K}_{3}\text{P}\) (Phosphorus oxidation state: -3) (f) Gallium arsenide: \(\text{GaAs}\) (Arsenic oxidation state: -3)

Step by step solution

01

a) Phosphate Ion

Phosphate ion is derived from phosphoric acid (H鈧働O鈧). To find the phosphate ion, we will remove the hydrogen ions from phosphoric acid. The oxidation state of phosphorus in phosphate ion is +5. The chemical formula for phosphate ion is: \[ \text{PO}_{4}^{3-} \]
02

b) Arsenous Acid

Arsenous acid is an acid with the chemical formula H鈧傾sO鈧. The oxidation state of the arsenic (As) in arsenous acid is +3. \[ \text{H}_{3}\text{AsO}_{3} \]
03

c) Antimony(III) Sulfide

Antimony(III) sulfide has antimony in a +3 oxidation state. The valency of sulfur is -2. In order to combine the elements and satisfy their valencies, we have: \[ \text{Sb}_{2}\text{S}_{3} \]
04

d) Calcium Dihydrogen Phosphate

Calcium dihydrogen phosphate is a salt formed from calcium ions (Ca虏鈦) and dihydrogen phosphate ions (H鈧侾O鈧勨伝). The oxidation state of phosphorus in dihydrogen phosphate ion is +5. The chemical formula for calcium dihydrogen phosphate is: \[ \text{Ca(H}_{2}\text{PO}_{4})_{2} \]
05

e) Potassium Phosphide

Potassium phosphide is a compound formed from potassium ions (K鈦) and phosphide ions (P鲁鈦). The oxidation state of phosphorus in potassium phosphide is -3. The chemical formula for potassium phosphide is: \[ \text{K}_{3}\text{P} \]
06

f) Gallium Arsenide

Gallium arsenide is a compound formed from gallium ions (Ga鲁鈦) and arsenide ions (As鲁鈦). The oxidation state of arsenic in gallium arsenide is -3. The chemical formula for gallium arsenide is: \[ \text{GaAs} \]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Formulas
Understanding chemical formulas is essential for students as they represent the composition of a substance. Every chemical formula is like a shorthand notation that tells us which elements are present in a compound and in what proportion. For instance, the formula for water, H2O, indicates that two atoms of hydrogen combine with one atom of oxygen. The numbers in the formula are called subscripts and represent the number of atoms of each element in one molecule of the compound.

When we look at more complex compounds, such as calcium dihydrogen phosphate, the chemical formula becomes Ca(H2PO4)2. This indicates two units of the dihydrogen phosphate ion are attached to a single calcium ion. Learning to read and write these formulas is a foundational skill in chemistry that allows students to communicate complex ideas with great precision.
Phosphate Ion
The phosphate ion, PO43-, is a polyatomic ion with a 3- charge, which means it carries three more electrons than protons. It is derived from phosphoric acid (H3PO4) by the loss of three hydrogen ions (protons), which results in the charge. This ion is a vital part of many biological molecules such as ATP, and it's also present in many fertilizers. The oxidation state of the central phosphorus atom in a phosphate ion is +5, which we can determine by considering the usual -2 oxidation state of oxygen in compounds and counting the number of bonds to oxygen.
Arsenous Acid
Arsenous acid, with the formula H3AsO3, is an example of a compound that contains arsenic in a +3 oxidation state. It's a weaker acid compared to its counterpart arsenic acid (H3AsO4) where arsenic has an oxidation state of +5. In arsenous acid, each arsenic atom is bonded to three oxygen atoms and one additional bond is to a hydrogen atom, which can dissociate in an aqueous solution making it an acid. The ability to determine the oxidation state of an element within a compound like arsenous acid is critical when predicting the reactivity and behavior of the substance in both chemical reactions and biological systems.
Valence of Elements
The valence of an element refers to its ability to combine with other elements. It is related to the number of electrons an atom can lose, gain, or share when it engages in chemical reactions. The valence is typically the same as the oxidation state when dealing with ionic compounds but can differ in covalent compounds. For instance, phosphorus has a valence of +5 in phosphate ion (PO43-), while it is -3 in phosphide ions. Similarly, arsenic exhibits a valence of +3 in compounds like arsenous acid (H3AsO3). Understanding an element's valence is pivotal for predicting the chemical properties of a substance and for writing correct chemical formulas.
Calcium Dihydrogen Phosphate
Calcium dihydrogen phosphate, Ca(H2PO4)2, is an example of a compound that contains both a metallic element (calcium) and a polyatomic ion (dihydrogen phosphate). The formula indicates that one atom of calcium binds with two dihydrogen phosphate ions. The oxidation state of calcium is +2 and for each phosphorus atom in the dihydrogen phosphate ion, it is +5. This compound is commonly found in some fertilizers and is also used as a food additive. The chemical formula can give an insight into the practical uses and the behavior of the compound during various chemical processes.
Gallium Arsenide
Gallium arsenide, GaAs, is a semiconductor material used in the electronics industry, especially in high-speed devices and solar cells. It is made up of gallium and arsenic elements, which have oxidation states of +3 (Ga3+) and -3 (As3-), respectively, when in this compound. This equality allows them to form a 1:1 ratio, which is critical for the structure and electronic properties of gallium arsenide. Understanding the stoichiometry and bonding in such compounds is essential for students who might work with or study advanced electronics and materials science.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

(a) How does the structure of diborane \(\left(\mathrm{B}_{2} \mathrm{H}_{6}\right)\) differ from that of ethane \(\left(\mathrm{C}_{2} \mathrm{H}_{6}\right) ?\) (b) Explain why diborane adopts the geometry that it does. (c) What is the significance of the statement that the hydrogen atoms in diborane are described as "hydridic'?

Write balanced equations for each of the following reactions. (a) When mercury(II) oxide is heated, it decomposes to form \(\mathrm{O}_{2}\) and mercury metal. (b) When copper(II) nitrate is heated strongly, it decomposes to form copper(II) oxide, nitrogen dioxide, and oxygen. (c) Lead(II) sulfide, \(\mathrm{PbS}(s)\), reacts with ozone to form \(\mathrm{PbSO}_{4}(s)\) and \(\mathrm{O}_{2}(g)\). (d) When heated in air, \(\mathrm{ZnS}(s)\) is converted to \(\mathrm{ZnO}\). (e) Potassium peroxide reacts (f) Oxygen with \(\mathrm{CO}_{2}(g)\) to give potassium carbonate and \(\mathrm{O}_{2}\). is converted to ozone in the upper atmosphere.

Consider the elements \(\mathrm{Li}, \mathrm{K}, \mathrm{Cl}, \mathrm{C}, \mathrm{Ne},\) and \(\mathrm{Ar}\). From this list select the element that (a) is most electronegative, (b) has the greatest metallic character, (c) most readily forms a positive ion, (d) has the smallest atomic radius, (e) forms \(\pi\) bonds most readily, (f) has multiple allotropes.

One method proposed for removing \(\mathrm{SO}_{2}\) from the flue gases of power plants involves reaction with aqueous \(\mathrm{H}_{2} \mathrm{~S}\). Elemental sulfur is the product. (a) Write a balanced chemical equation for the reaction. (b) What volume of \(\mathrm{H}_{2} \mathrm{~S}\) at \(27^{\circ} \mathrm{C}\) and 760 torr would be required to remove the \(\mathrm{SO}_{2}\) formed by burning 2.0 tons of coal containing \(3.5 \% \mathrm{~S}\) by mass? (c) What mass of elemental sulfur is produced? Assume that all reactions are \(100 \%\) efficient.

Write the chemical formula for each of the following compounds, and indicate the oxidation state of the group \(6 \mathrm{~A}\) element in each: (a) sulfur tetrachloride, (b) selenium trioxide, (c) sodium thiosulfate, (d) hydrogen sulfide, (e) sulfuric acid, \((\mathbf{f})\) sulfur dioxide, \((\mathrm{g})\) mercury telluride.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.