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Chapter 11: Problem 69

For a given substance, the liquid crystalline phase tends to be more viscous than the liquid phase. Why?

Short Answer

Expert verified
The liquid crystalline phase tends to be more viscous than the liquid phase due to differences in molecular arrangement and interactions. In the liquid phase, molecules are randomly arranged and have weak intermolecular forces, allowing them to slide past each other easily, resulting in low viscosity. In the liquid crystalline phase, molecules are partially ordered and have stronger intermolecular forces due to elongated shape and alignment. This causes greater resistance to flow, making the liquid crystalline phase more viscous than the liquid phase.

Step by step solution

01

Understanding the liquid and liquid crystalline phases

Liquid phase is a state of matter where the substance has a definite volume but no definite shape, so it takes the shape of the container it is placed in. On the other hand, the liquid crystalline phase, also known as mesophase, is a state of matter that exhibits properties between those of crystalline solids and ordinary liquids. Liquid crystals can flow like a liquid but have long-range order like crystals. Their molecules tend to be elongated and partially orient themselves along a preferred direction.
02

Analyzing molecular arrangement

In a liquid phase, molecules are randomly arranged, and they have relatively weak interactions with each other due to their isotropic nature. They can easily move and slide past each other, which allows the liquid to flow freely. In the liquid crystalline phase, the molecules are partially ordered and tend to align in specific directions or planes. This results in a more organized structure than the liquid phase.
03

Understanding molecular interactions

In the liquid crystalline phase, due to the elongated shape of the molecules and their partial alignment, these molecules tend to have stronger intermolecular forces (such as van der Waals forces) between them than those in the liquid phase.
04

Understanding viscosity

Viscosity is a measure of a substance's resistance to flow. It is influenced by factors such as molecular arrangement, intermolecular forces, and temperature. When molecules are randomly arranged and have weak interactions (like in the liquid phase), they slide past each other easily, and their resistance to flow is low, resulting in low viscosity. When molecules are partially ordered and have stronger interactions (like in the liquid crystalline phase), they resist flowing and have difficulty sliding past each other. Their resistance to flow is higher, resulting in higher viscosity.
05

Comparing viscosity of liquid and liquid crystalline phases

Based on the analysis of molecular arrangement and intermolecular interactions, we can conclude that the liquid crystalline phase tends to have more organized molecular arrangements and stronger intermolecular forces than the liquid phase. This leads to a higher resistance to flow, resulting in a more viscous liquid crystalline phase as compared to the liquid phase.

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Most popular questions from this chapter

The vapor pressure of a volatile liquid can be determined by slowly bubbling a known volume of gas through it at a known temperature and pressure. In an experiment, \(5.00 \mathrm{~L}\) of \(\mathrm{N}_{2}\) gas is passed through \(7.2146 \mathrm{~g}\) of liquid benzene, \(\mathrm{C}_{6} \mathrm{H}_{6}\), at \(26.0{ }^{\circ} \mathrm{C}\). The liquid remaining after the experiment weighs \(5.1493 \mathrm{~g}\). Assuming that the gas becomes saturated with benzene vapor and that the total gas volume and temperature remain constant, what is the vapor pressure of the benzene in torr?

Look up and compare the normal boiling points and normal melting points of \(\mathrm{H}_{2} \mathrm{O}\) and \(\mathrm{H}_{2} \mathrm{~S}\). Based on these physical properties, which substance has stronger intermolecular forces? What kinds of intermolecular forces exist for each molecule?

The generic structural formula for a 1 -alkyl-3-methylimidazolium cation is where \(\mathrm{R}\) is a \(-\mathrm{CH}_{2}\left(\mathrm{CH}_{2}\right)_{n} \mathrm{CH}_{3}\) alkyl group. The melting points of the salts that form between the 1 -alkyl-3-methylimidazolium cation and the \(\mathrm{PF}_{6}^{-}\) anion are as follows: \(\mathrm{R}=\mathrm{CH}_{2} \mathrm{CH}_{3}\left(\mathrm{~m} . \mathrm{p} .=60^{\circ} \mathrm{C}\right), \mathrm{R}=\mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{3}\left(\mathrm{m.p.}=40^{\circ} \mathrm{C}\right)\) \(\mathrm{R}=\mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{3}\left(\mathrm{~m} . \mathrm{p} .=10^{\circ} \mathrm{C}\right)\) and \(\mathrm{R}=\mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{3}\left(\mathrm{~m} . \mathrm{p} .=-61^{\circ} \mathrm{C}\right) . \mathrm{Why}\) does the melting point decrease as the length of alkyl group increases?

(a) Explain why surface tension and viscosity decrease with increasing temperature. (b) Why do substances with high surface tensions also tend to have high viscosities?

If \(42.0 \mathrm{~kJ}\) of heat is added to a 32.0 -g sample of liquid methane under 1 atm of pressure at a temperature of \(-170{ }^{\circ} \mathrm{C},\) what are the final state and temperature of the methane once the system equilibrates? Assume no heat is lost to the surroundings. The normal boiling point of methane is \(-161.5^{\circ} \mathrm{C}\). The specific heats of liquid and gaseous methane are 3.48 and \(2.22 \mathrm{~J} / \mathrm{g}-\mathrm{K},\) respectively. [Section 11.4\(]\)
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