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Without doing a numerical calculation, determine which of the following will reduce the free energy change for the reaction, that is, make it less positive or more negative, when the temperature is increased. Explain.

(a) \({{\bf{N}}_{\bf{2}}}{\bf{(g) + 3}}{{\bf{H}}_{\bf{2}}}{\bf{(g)}} \to {\bf{2N}}{{\bf{H}}_{\bf{3}}}{\bf{(g)}}\)

(b) \({\bf{HCl(g) + N}}{{\bf{H}}_{\bf{3}}}{\bf{(g)}} \to {\bf{N}}{{\bf{H}}_{\bf{4}}}{\bf{Cl(s)}}\)

(c) \({\left( {{\bf{N}}{{\bf{H}}_{\bf{4}}}} \right)_{\bf{2}}}{\bf{C}}{{\bf{r}}_{\bf{2}}}{{\bf{O}}_{\bf{7}}}{\bf{(s)}} \to {\bf{C}}{{\bf{r}}_{\bf{2}}}{{\bf{O}}_{\bf{3}}}{\bf{(s) + 4}}{{\bf{H}}_{\bf{2}}}{\bf{O(g) + }}{{\bf{N}}_{\bf{2}}}{\bf{(g)}}\)

(d) \({\bf{2Fe(s) + 3}}{{\bf{O}}_{\bf{2}}}{\bf{(g)}} \to {\bf{F}}{{\bf{e}}_{\bf{2}}}{{\bf{O}}_{\bf{3}}}{\bf{(s)}}\)

Short Answer

Expert verified

Option B is correct answer \({\rm{HCl}}(g) + {\rm{N}}{{\rm{H}}_3}(g) \to {\rm{N}}{{\rm{H}}_4}{\rm{Cl}}(s)\)

Step by step solution

01

Define exothermic reaction and endothermic reaction

The spontaneity of a reaction depends on the releasing or absorption of energy. If the amount of energy releases during the reaction, then the reaction is exothermic reactionwhile the amount of energy absorbed during the reaction then the reaction isendothermic reaction. The value of enthalpy is positive for endothermic reaction while value of enthalpy is negative for exothermic reaction.

02

Reason for correct option.

The given reaction for the production of ammonium chloride is endothermic reaction with value \(64.81\;{\rm{kJ}}\) /mol. The reaction continuously absorbs the heat for the yielding of product. On increasing the temperature, the reaction goes in forward direction toward the product. Thus, the reaction become spontaneous and makes the Gibbs value more negative.

Hence, option (b) is correct.

03

Reason for incorrect option.

The given reaction for the production of ammonia is exothermic reaction with value \( - 46.28\;{\rm{kJ}}/{\rm{mol}}\). The reaction continuously releases the heat for the yielding of product. On increasing the temperature, the reaction goes in reverse direction toward the reactant. Thus, the reaction become non spontaneous and makes the Gibbs value more positive.

The given reaction for the production of alumina chromium is exothermic reaction with value \( - 272.8\;{\rm{kJ}}/{\rm{mol}}\). The reaction continuously releases the heat for the yielding of product. On increasing the temperature, the reaction goes in reverse direction toward the reactant. Thus, the reaction become non spontaneous and makes the Gibbs value more positive.

The given reaction for the production of Iron oxide is exothermic reaction with value \( - 850.72\;{\rm{kJ}}/{\rm{mol}}\). The reaction continuously releases the heat for the yielding of product. On increasing the temperature, the reaction goes in reverse direction toward the reactant. Thus, the reaction become non spontaneous and makes the Gibbs value more positive.

Hence, option (a), (c), (d) are incorrect.

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Most popular questions from this chapter

Predict the sign of the enthalpy change for the following processes. Give a reason for your prediction.

(a) \({\bf{NaN}}{{\bf{O}}_{\bf{3}}}{\bf{(s)}} \to {\bf{N}}{{\bf{a}}^{\bf{ + }}}{\bf{(aq) + N}}{{\bf{O}}_{\bf{3}}}^{\bf{ - }}{\bf{(aq)}}\)

(b) the freezing of liquid water

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