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Determine the oxidation state of sulfur in each of the following:

(a) \(S{O_3}\)

(b) \(S{O_2}\)

(c) \(SO_3^{2 - }\)

Short Answer

Expert verified

(a) For \({\rm{S}}{{\rm{O}}_3}\), the oxidation number of oxygen is\( - 2\)and for sulfur is\( + 6\).

(b) For \({\rm{S}}{{\rm{O}}_2}\), the oxidation number of oxygen is\( - 2\)and for sulfur is\( + 4\).

(c) For \({\rm{SO}}_3^{2 - }\), the oxidation number of oxygen is\( - 2\)and for sulfur is\( + 4\).

Step by step solution

01

Definition of oxidation state

An oxidation state is classified as a hypothetical charge. It is evaluated by adding the total electrons that are either gained or lost by anatom during bond formation. For a neutral compound, the addition of all oxidation states is zero.

02

Oxidation state of sulfur in each element

In the compounds \({\rm{S}}{{\rm{O}}_3}\) and \({\rm{S}}{{\rm{O}}_2}\), the total sum of the oxidation numbers is zero, while in \({\rm{SO}}_3^{2 - }\), the total sum is \( - 2\).

(a) In \({\rm{S}}{{\rm{O}}_3}\), the oxidation number of oxygen is\( - 2\), so the oxidation number of sulfur is\( + 6\).

(b) In \({\rm{S}}{{\rm{O}}_2}\) the oxidation number of oxygen is\( - 2\), while the oxidation number of sulfur is\( + 4\).

(c) In \({\rm{SO}}_3^{2 - }\) the oxidation number of oxygen is\( - 2\), while the oxidation number of sulfur is\( + 4\).

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