91Ó°ÊÓ

The overall number of electrons that an atom either gains or loses such as to form a chemical bond with another atom.

Oxidation state of\(O\)is\(( - 2)\)and of\({\rm{H}}\)is\(( + 1)\).

The total charge on the molecule is 0.

Oxida on state of\(I\)is\(x\); find\(x\).

\(0 = x + 6 \cdot ( - 2) + 5 \cdot ( + 1)\)

\(0 = x - 7\)

\(x = + 7\).

The oxidation number of \({\rm{I}}\) in \({{\rm{H}}_5}{\rm{I}}{{\rm{O}}_6}\) is \( + 7\).

b) Oxidation state of\(O\)is\(( - 2)\)and the total charge on the molecule is\(( - 1)\).

\( - 1 = x + 4 \cdot ( - 2)\)

\( - 1 = x - 8\)

\(x = + 7\).

The oxidation number of\({\rm{I}}\)in\({\rm{IO}}_4^ - \)is\( + 7\).

Oxidation state of\(O\)is\(( - 2)\)and the total charge on the molecule is 0.

\(0 = x - 4\)

\(x = + 4\).

The oxidation number of \({\rm{Cl}}\) in \({\rm{Cl}}{{\rm{O}}_2}\) is \( + 4\).

Oxidation state of \({\rm{Cl}}\) is\(( - 1)\)and the total charge on the molecule is \(0\).

\(0 = x + 3 \cdot ( - 1)\)

\(0 = x - 3\)

\(x = 3\).

The oxidation number of \({\rm{I}}\) in \({\rm{IC}}{{\rm{l}}_3}\) is \( + 3\).

e) Oxidation state of atoms in elementary state is zero, therefore, oxidation number of \({\rm{F}}\) in \({F_2}\) is \(0\).