Q10.4-59 E Consider a cylinder containing a... [FREE SOLUTION]

Chapter 10: Q10.4-59 E (page 589)

Consider a cylinder containing a mixture of liquid carbon dioxide in equilibrium with gaseous carbon dioxide at an initial pressure of \({\rm{65}}\) atm and a temperature of \({\rm{2}}{{\rm{0}}^{\rm{o}}}{\rm{C}}\). Sketch a plot depicting the change in the cylinder pressure with time as gaseous carbon dioxide is released at constant temperature.

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Definition of liquid

One of the states of matter is the liquid state. Because the particles in a liquid are free to move, it lacks a defined form even while having a defined volume.

Sketching a plot

The reaction

- The temperature is \({20^\circ }{\rm{C}}\)

- The pressure of \({\rm{C}}{{\rm{O}}_{\rm{2}}}\)in a closed cylinder at equilibrium is \({\rm{65\;atm}}\)

Let us sketch a plot with the change in pressure over time, as gaseous \({\rm{C}}{{\rm{O}}_{\rm{2}}}\) is released (the temperature is constant).

In the beginning, the vapour and liquid phases of carbon dioxide are in balance. The pressure is kept at \({\rm{65}}\) atmospheres. The system's pressure drops after the gaseous carbon dioxide is discharged.

Hence, when some gaseous \({\rm{C}}{{\rm{O}}_{\rm{2}}}\)is released, the equilibrium of the system will move to the right, and so some liquid \({\rm{C}}{{\rm{O}}_{\rm{2}}}\)will convert into gas, to maintain the equilibrium pressure of \({\rm{65\;atm}}\)_.So, as long as we have liquid \({\rm{C}}{{\rm{O}}_{\rm{2}}}\),the pressure will be \({\rm{65\;atm}}\)_.As soon as we convert all liquid \({\rm{C}}{{\rm{O}}_{\rm{2}}}\)into gas, the pressure will begin to drop.