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How many moles of sucrose, C12H22O11, are in a 25-g sample of sucrose?

Short Answer

Expert verified

No. of moles of sucrose is equal to \(0.073{\rm{ mol}}\)

Step by step solution

01

Determine molecular mass 

To calculate no of moles of sucrose, we have to evaluate the molar mass of sucrose first.

Element

Quantity

Molar mass

(g/mol element)

Subtotal

(g/mol compound)

C

12

12.01

=

144.12

H

22

1.008

=

22.176

O

11

16.00

=

176.00

Molecular mass(g/mol)

=

342.296

02

Determine no of moles

No of moles = \(25{\rm{ g sucrose }} \times {\rm{ }}\frac{{{\rm{mol of sucrose}}}}{{342.296{\rm{ g sucrose}}}} = 0.073{\rm{ mol of sucrose}}\)

Hence, no of moles of sucrose is equal to\(0.073{\rm{ mol}}\)

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