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Chapter 3: Q 61E (page 171)

Question:What volume of a 0.33-M C12H22O11 solution can be diluted to prepare 25 mL of a solution with a concentration of 0.025 M?

Short Answer

Expert verified

The volume of\({C_{12}}{H_{22}}{O_{11}}\)stock solution needs 1.9mL.

Step by step solution

01

Summarize the given data

The number of moles of solute before dilution is equal to the number of moles after dilution.

\({M_1}{V_1} = {M_2}{V_2}\).

Given

\(\begin{array}{c}{M_1} = 0.33M\\{V_2} = 25mL\\{M_2} = 0.025M\end{array}\)

02

Determine the volume of the solution required

Find \({V_1}\), the initial value.

\({V_1} = \frac{{{M_2}{V_2}}}{{{M_1}}}\)

Substitute the values in the formula above.

\(\begin{array}{c}{V_1} = \frac{{\left( {0.025M} \right)25mL}}{{0.33M}}\\ = 1.9mL\end{array}\)

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