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Chapter 3: Q.25E (page 129)

Determine which of the following contains the greatest mass of aluminum: 122 g of AlPO4, 266 g of Al2C16, or 225 g of Al2S3.

Short Answer

Expert verified

Greatest mass of Al is in Al2S3 = 81 g.

Step by step solution

01

Determine the number of moles

Given

122 g of AlPO4

266 g of Al2C16

225 g of Al2S3

Molar mass of AlPO4 = 2 x 27 + 16 x 12 = 246 g/mol

Molar mass Al2C16= 27 + 31+ 4 x 16 = 122 g/mol

Molar mass Al2S3= 2 x 27 + 3 x 32 = 150 g/mol

Number of mole of AlPO4 = (122 g) / (122 g/mol) = 1 mol AlPO4

Number of mole of Al2C16 = (266 g)/(246 g/mol) = 1.081 mol of Al2C16

Number of mole of Al2S3 = (225 g)/(150 g/mol) = 1.5 mol of Al2S3

02

Determine the mass

Mass of Al in AlPO4 = 1 mol x 27 g/mol = 27 g

Mass of Al in Al2C16 = 1.081 mol x 54 g/mol = 58.374 g

Mass of Al in Al2S3 = 1.5 mol x 54 g /mol = 81 g

Greatest mass of Al is in Al2S3

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Determine the number of moles of compound and the number of moles of each type of atom in each of the following:

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