/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q4.89P Balance each of the following re... [FREE SOLUTION] | 91影视

91影视

Balance each of the following redox reactions and classify it as a combination, decomposition, or displacement reaction:

(a)Sb(s)+Cl2(g)SbCl3(s)

(b)AsH3(g)As(s)+H2(g)

(c)Zn(s)+Fe(NO3)2(aq)Zn(NO3)2(aq)+Fe(s)


Short Answer

Expert verified

The classification of the given reactions are:

(a) Combination reaction

(b) Decomposition reaction

(c) Displacement reaction

Step by step solution

01

Write balanced reaction of equation (a)

The given reaction is:

Sbs+Cl2gSbCl3s

The balanced reaction is:

2Sbs+3Cl2g2SbCl3s

The given redox reaction is a combination reaction.

In this reaction,SbandCl2combines and formsSbCl3.

02

Write balanced reaction of equation (b) 

The given reaction is:

AsH3gAss+H2g

The balanced reaction is:

2AsH3g2Ass+3H2g

The given redox reaction is a decomposition reaction.

In this reaction, AsH3 decomposes and forms Asand H2.

03

Write balanced reaction of equation (c)

The given reaction is:

Zns+FeNO32aqZnNO32aq+Fes

The balanced reaction is:

Zns+FeNO32aqZnNO32aq+Fes

The given redox reaction is a displacement reaction.

TheZnatom replaces iron atom from FeNO32 and forms ZnNO32.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Que Complete the following acid-base reactions with balanced molecular, total ionic, and net ionic equations:

(a) Potassium hydroxide(aq) + hydrobromic acid(aq)

(b) Ammonia(aq) + hydrochloric acid(aq)

In the process of pickling, rust is removed from newly produced steel by washing the steel in hydrochloric acid:

(1)6HCl(aq)+Fe2O3(s)2FeCl3(aq)+3H2O(l)

During the process, some iron is lost as well:

(2)2HCl(aq)+Fe(s)FeCl2(aq)+H2(g)

(a) Which reaction, if either, is a redox process? (b) If reaction 2 did not occur and all the HCl were used, how many grams of Fe2O3 could be removed and FeCl3 produced in a 2.50x103-L bath of 3.00 MHCl? (c) If reaction 1 did not occur and all the HCl were used, how many grams of Fe could be lost and FeCl2 produced in a 2.50x103-L bath of 3.00 MHCl? (d) If 0.280 g of Fe is lost per gram of Fe2O3 removed, what is the mass ratio of FeCl2to FeCl3?

Use the oxidation number method to balance the following equations by placing coefficients in the blanks. Identify the reducing and oxidizing agents:

(a)_KOH(aq)+_H2O2(aq)+_Cr(OH)3(s)_K2CrO4(aq)+_H2O(l)(b)_MnO4(aq)+_ClO2(aq)+_H2O(l)_MnO2(s)+_ClO4(aq)+OH(aq)(c)_KMnO4(aq)+_Na2SO3(aq)+_H2O(l)_MnO2(s)+_Na2SO4(aq)+_KOH(aq)(d)_CrO42(aq)+_HSnO2(aq)+_H2O(l)_CrO2(aq)+_HSnO3(aq)+OH(aq)(e)_KMnO4(aq)+_NaNO2(aq)+_H2O(l)_MnO2(s)+_NaNO3(aq)+_KOH(aq)(f)_I(aq)+_O2(g)+_H2O(l)_I2(s)+_OH(aq)

Why the equilibrium state is called 鈥渄ynamic鈥?

Carbon dioxide is removed from the atmosphere of space capsules by reaction with a solid metal hydroxide. The products are water and the metal carbonate.

(a) Calculate the mass of CO2that can be removed by reaction with 3.50 kg of lithium hydroxide.

(b) How many grams of CO2 can be removed by 1.00 g of each of the following: lithium hydroxide, magnesium hydroxide, and aluminum hydroxide?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.