91Ó°ÊÓ

The molecular equationreveals the least about the species in solution and is actually somewhat misleading because it shows all the reactants and products as if they were intact undissociated compounds.

The total ionic equation is a much more accurate representation of the reaction because it shows all the soluble ionic substances dissociated into ions.

The net ionic equation is the most useful because it omits the spectator ions and shows the actual chemical change taking place.

(a) Balanced molecular reaction:

$\mathrm{CsOH}\left(\mathrm{aq}\right)+2{\mathrm{HNO}}_3\left(\mathrm{aq}\right)→{\mathrm{CsNO}}_3\left(\mathrm{aq}\right)+{\mathrm{H}}_2\mathrm{O}\left(\mathrm{l}\right)$

Total ionic equation:

${\mathrm{Cs}}^{+}\left(\mathrm{aq}\right)+{\mathrm{OH}}^{-}\left(\mathrm{aq}\right)+{\mathrm{H}}^{+}\left(\mathrm{aq}\right)+{\mathrm{NO}}_3^{-}\left(\mathrm{aq}\right)→{\mathrm{Cs}}^{+}\left(\mathrm{aq}\right)+{\mathrm{NO}}_3^{-}\left(\mathrm{aq}\right)+{\mathrm{H}}_2\mathrm{O}\left(\mathrm{l}\right)$

Net ionic equation:

${\mathrm{H}}^{+}\left(\mathrm{aq}\right)+{\mathrm{OH}}^{-}\left(\mathrm{aq}\right)→{\mathrm{H}}_2\mathrm{O}\left(\mathrm{l}\right)$

(b)

Balanced molecular reaction:

$\mathrm{Ca}{\left(\mathrm{OH}\right)}_2\left(\mathrm{aq}\right)+2{\mathrm{CH}}_3\mathrm{COOH}\left(\mathrm{aq}\right)→{\left({\mathrm{CH}}_3\mathrm{COO}\right)}_2\mathrm{Ca}\left(\mathrm{aq}\right)+2{\mathrm{H}}_2\mathrm{O}\left(\mathrm{l}\right)$

Total ionic equation:

${\mathrm{Ca}}^{+2}\left(\mathrm{aq}\right)+2{\mathrm{OH}}^{-}\left(\mathrm{aq}\right)+2{\mathrm{C}}_2{\mathrm{H}}_3{{\mathrm{O}}_2}^{−}\left(\text{aq}\right)\text{+2}{\mathrm{H}}^{+}\left(\mathrm{aq}\right)+{\mathrm{NO}}_3^{-}\left(\mathrm{aq}\right)→2{\mathrm{C}}_2{\mathrm{H}}_3{{\mathrm{O}}_2}^{−}\left(\text{aq}\right)+{\mathrm{Ca}}^{+2}\left(\mathrm{aq}\right)+2{\mathrm{H}}_2\mathrm{O}\left(\mathrm{l}\right)$

Net ionic equation:

$2{\mathrm{H}}^{+}\left(\mathrm{aq}\right)+2{\mathrm{OH}}^{-}\left(\mathrm{aq}\right)→2{\mathrm{H}}_2\mathrm{O}\left(\mathrm{l}\right)$