/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q4.41P Is the total ionic equation the ... [FREE SOLUTION] | 91影视

91影视

Find study content
Learning Materials

Discover learning materials by subject, university or textbook.

Explanations

Textbooks
All Subjects

Anthropology

Archaeology

Architecture

Art and Design

Bengali

Biology

Business Studies

Greek

Chemistry

Chinese

Combined Science

Computer Science

Economics

Engineering

English

English Literature

Environmental Science

French

Geography

German

History

Hospitality and Tourism

Human Geography

Italian

Japanese

Law

Macroeconomics

Marketing

Math

Media Studies

Medicine

Microeconomics

Music

Nursing

Nutrition and Food Science

Physics

Polish

Politics

Psychology

Religious Studies

Sociology

Spanish

Sports Sciences

Translation

All Subjects

Biology

Business Studies

Chemistry

Combined Science

Computer Science

Economics

English

Environmental Science

Geography

History

Math

Physics

Psychology

Sociology
Features
Features

Discover all of these amazing features with a free account.

Flashcards

91影视 AI

Notes

Study Plans

Study Sets
What鈥檚 new?

Flashcards
Study your flashcards with three learning modes.

Study Sets
All of your learning materials stored in one place.

Notes
Create and edit notes or documents.

Study Plans
Organise your studies and prepare for exams.
91影视
Discover

All the hacks around your studies and career - in one place.

Find a degree

Magazine
Featured

Magazine
Trusted advice for anyone who wants to ace their studies & career.

The largest student job board with the most exciting opportunities.

Verified student deals from top brands.

Discover our mobile app to take your studies anywhere.

Learning Materials

Features

Discover

Chapter 4: Q4.41P (page 180)

Is the total ionic equation the same as the net ionic equation when $S r {(OH)}_{2} (aq)$ and $H_{2} S O_{4} (aq)$ react? Explain.

Short Answer

Expert verified

Answer

Yes, the total ionic equation is the same as the net ionic equation when

$S r {(OH)}_{2} (aq)$ and $H_{2} S O_{4} (aq)$ react.

Step by step solution

01

Determine difference between the total ionic equation and the net ionic equation

A complete ionic equation includes the spectator ions while the net ionic equation shows only the chemical species involved in a reaction.

02

Write the net ionic equation of the reaction

The balanced molecular reaction is: $S r {(O H)}_{2} + H_{2} (S O_{4}) (a q) 鈫� H_{2} O (I) + S r S O_{4} (s)$

The total ionic equation is: $S r^{- 2} (aq) + 2 O H (aq) + 2 H^{+} (aq) 鈫� 2 H_{2} O (I) + S r S O_{4} (s)$

The net ionic equation is:

$S r^{- 2} (aq) + 2 O H (aq) + 2 H^{+} (aq) + S O_{4}^{- 2} 鈫� 2 H_{2} O (I) + S r S O_{4} (s)$

Since no ions are common in both sides of the total ionic equation, thus nothing is canceled out in the reaction.

Hence, the net ionic equation is the same as the total ionic equation.

Unlock Step-by-Step Solutions & Ace Your Exams!

Full Textbook Solutions
Get detailed explanations and key concepts
Unlimited Al creation
Al flashcards, explanations, exams and more...
Ads-free access
To over 500 millions flashcards
Money-back guarantee
We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Sodium peroxide (Na₂O₂) is often used in self-contained breathing devices, such as those used in fire emergencies, because it reacts with exhaled CO₂ to form Na₂CO₃ and O₂. How many liters of respired air can react with 80.0 g of Na₂O₂ if each liter of respired air contains 0.0720 g of CO₂?

Identify the oxidizing and reducing agents in the following:

$(a) 8 H^{+} (a q) + C r_{2} O_{7}^{2 -} (a q) + 3 S O_{3}^{2 -} (a q) 鈫� 2 C r^{3 +} (a q) + 3 S O_{4}^{2 -} (a q) + 4 H_{2} O (l) (b) N O_{3}^{-} (a q) + 4 Z n (s) + 7 O H^{-} (a q) + 6 H_{2} O (l) 鈫� 4 Z n {(O H)}_{4}^{2 -} (a q) + N H_{3} (a q)$

A chemist mixes solid AgCl, CuCl₂, and MgCl₂ in enough water to give a final volume of 50.0 mL.

(a) With ions shown as spheres and solvent molecules omitted for clarity, which of the following best represents the resulting mixture?

(b) If each sphere represents 5.0x10^-3mol of ions, what is the total concentration of dissolved(separated) ions?

(c) What is the total mass of solid?

In the process of pickling, rust is removed from newly produced steel by washing the steel in hydrochloric acid:

$(1) 6 HCl (aq) + {Fe}_{2} O_{3} (s) 鈫� 2 {FeCl}_{3} (aq) + 3 H_{2} O (l)$

During the process, some iron is lost as well:

$(2) 2 HCl (aq) + Fe (s) 鈫� {FeCl}_{2} (aq) + H_{2} (g)$

(a) Which reaction, if either, is a redox process? (b) If reaction 2 did not occur and all the HCl were used, how many grams of Fe₂O₃ could be removed and FeCl₃ produced in a 2.50x10³-L bath of 3.00 MHCl? (c) If reaction 1 did not occur and all the HCl were used, how many grams of Fe could be lost and FeCl₂ produced in a 2.50x10₃-L bath of 3.00 MHCl? (d) If 0.280 g of Fe is lost per gram of Fe₂O₃ removed, what is the mass ratio of FeCl₂to FeCl₃?

Sodium hydroxide is used extensively in acid-base titrations because it is a strong, inexpensive base. A sodium hydroxide solution was standardized by titrating 25.00 mL of 0.1528 M standard hydrochloric acid. The initial buret reading of the sodium hydroxide was 2.24 mL, and the final reading was 39.21 mL. What was the molarity of the base solution?

See all solutions

Recommended explanations on Chemistry Textbooks

Chemistry Branches

Read Explanation

Organic Chemistry

Read Explanation

Ionic and Molecular Compounds

Read Explanation

The Earths Atmosphere

Read Explanation

Kinetics

Read Explanation

Making Measurements

Read Explanation

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.