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In a sample of any metal, spherical atoms pack closely together, but the space between them means that the density of the sample is less than that of the atoms themselves. Iridium (Ir) is one of the densest elements: 22.56 g/cm3. The atomic mass of Ir is 192.22 amu, and the mass of the nucleus is 192.18 amu. Determine the density (in g/cm3) of (a) an Ir atom and (b) an Ir nucleus. (c) How many Ir atoms placed in a row would extend 1.00 cm [radius of Ir atom = 1.36 脜; the radius of Ir nucleus = 1.5 femtometers (fm); V of a sphere =4.3蟺谤3 ]?

Short Answer

Expert verified
  1. The density of an Ir atom is30.40g/cm3
  2. The density of an Ir nucleus is2.261016g/cm3
  3. The number of Ir atoms is3.68107lratoms

Step by step solution

01

Calculating the density of an Ir atom

The volume of the atom is calculated using the given formula,

V=43r3=43(1.36A11010m1A100cm1m)3V=1.051023cm3

On solving for density,

d=massvolume=192.22amu1.051023cm31g6.0221023amud=30.40g/cm3

02

Calculating the density of an Ir nucleus

On solving the volume of the atom,

V=43蟺谤3=43(1.5fm11015m1fm100cm1m)3V=1.411038cm3

On solving for density,

d=192.18amu1.411038cm31g6.0221023amud=2.261016g/cm3

03

Calculating the number of Ir atoms

For finding the diameter,

diameter=2r=2(1.36A)=2.72A2.72A=2.72A110m1A100cm1m=2.72108cm

Ir atoms in 1 cm would be

12.7108=3.68107lratoms

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