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The mineral galena is composed of lead(II) sulfide and has an average density of7.46 g/cm3.

  1. How many moles of lead(II) sulfide are in 1.00 ft3of galena?
  2. How many lead atoms are in 1.00 dm3of galena?

Short Answer

Expert verified
  1. The Moles of lead(II) sulfide are in 1.00 ft3 of galena is 882.9 mol.
  2. The lead atoms are in 1.00 dm3 of galena is 1.88×1025atoms.

Step by step solution

01

To Calculate how many moles of lead(II) sulfide are in 1.00 ft3 of galena,

The V(galena) are in1 ft3 = 28316.85 cm3

The density of d(galena) is7.46 g/cm3

The moles of lead(II) sulfide m(galena) =d× V

=28316.85 cm3×7.46 g/cm3

The moles of lead(II) sulfide m(galena) =211243.701 g

MrPbS=ArPb×ArSMrPbS=207.20+32.06MrPbS=239.26 g/molnPbS=m/Mr = 211243.7g239.26 g/molnPbS=882.9 mol

The Moles of lead(II) sulfide are in 1.00 ft3 of galena is 882.9 mol.

02

Step 2: How many lead atoms are in 1.00 dm3 of galena,

The V=1 dm3 = 103 cm3

m=d×V=7.46 g/cm3 × 103 cm3

m(galena)= 7460gm(galena)=239.26 g/cm3

n(galena) =m/Mr= nPb

ngalena=7460 g239.26 g/mol.n(galena)= 31.18 mol.

nPb= ngalena=31.18 molnPb= nPb×NAnPb=31.18×6.022×10 23NPb=1.88×10 25

The lead atoms are in 1.00 dm3 of galena is 1.88×1025atoms.

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