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Chapter 3: Q3.28P (page 132)

The mineral galena is composed of lead(II) sulfide and has an average density of7.46鈥�g/cm3.

  1. How many moles of lead(II) sulfide are in 1.00鈥�ft3of galena?
  2. How many lead atoms are in 1.00鈥�dm3of galena?

Short Answer

Expert verified
  1. The Moles of lead(II) sulfide are in 1.00 ft3 of galena is 882.9 mol.
  2. The lead atoms are in 1.00 dm3 of galena is 1.88脳1025atoms.

Step by step solution

01

To Calculate how many moles of lead(II) sulfide are in 1.00 ft3 of galena,

The V(galena) are in1鈥�ft3鈥�=鈥�28316.85鈥�cm3

The density of d(galena) is7.46鈥�g/cm3

The moles of lead(II) sulfide m(galena)鈥�=d脳鈥�V

=28316.85鈥�cm3脳7.46鈥�g/cm3

The moles of lead(II) sulfide m(galena)鈥�=211243.701鈥�g

MrPbS=ArPb脳ArSMrPbS=207.20+32.06MrPbS=239.26鈥�g/molnPbS=m/Mr鈥�=鈥�211243.7g239.26鈥�g/molnPbS=882.9鈥�mol

The Moles of lead(II) sulfide are in 1.00 ft3 of galena is 882.9 mol.

02

Step 2: How many lead atoms are in 1.00 dm3 of galena,

The V=1鈥�dm3鈥�=鈥�103鈥�cm3

m=d脳V=7.46鈥�g/cm3鈥�脳鈥�103鈥�cm3

m(galena)= 7460gm(galena)=239.26 g/cm3

n(galena) =m/Mr=鈥�nPb

ngalena=7460鈥�g239.26鈥�g/mol.n(galena)= 31.18 mol.

nPb=鈥�ngalena=31.18鈥�molnPb=鈥�nPb脳NAnPb=31.18脳6.022脳10鈥�23NPb=1.88脳10鈥�25

The lead atoms are in 1.00 dm3 of galena is 1.88脳1025atoms.

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