91Ó°ÊÓ

Box A has twelveparticles with unit volume.If the volume is tripled, then the number of particles will be calculated as follows:

$1\text{unit volume}×\frac{12\text{particles}}{3\text{unit volume}}=4\text{particles}$

Hence, Box C has triple volume than A,as four particles are present in it.

Box A has twelve particles with unit volume. If the volume is doubled then the number of particles will be calculated as follows:

$1\text{unit volume}×\frac{12\text{particles}}{\text{2 unit volume}}=6\text{particles}$

Hence,Box B has a double volume of A , as six particles are present in it.

Box A has twelve particles with unit volume. If the volume isquadruple, then the number of particles will be calculated as follows:

$1\text{unit volume}×\frac{12\text{particles}}{\text{4 unit volume}}=3\text{particles}$

Hence, Box D has aquadruple volume of A, as three particles are present in it.

Result:

1. Box C has triple volume than A
2. Box B has a double volume of A
3. Box D has aquadruple volume of A