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Chapter 3: Q158CP (page 139)

Lead(II) chromate (PbCrO4) is used as the yellow pigment in traffic lanes, but is banned from house paint because of the risk of lead poisoning. It is produced from chromite (FeCr2O4), an ore of chromium:

4FeCr2O4(S)+8K2CO3(aq)+7O2(g)鈫�2Fe2O3(s)+8K2CrO4(aq)+8CO2(g)

Lead(II) ion then replaces the K+ ion. If a yellow paint is 0.511% PbCrO4 by mass, how many grams of chromite are needed per kilogram of paint?

Short Answer

Expert verified

There are 1.77 g FeCr2O4of chromite are need to replace per kg of paint.

Step by step solution

01

Calculating the moles of PbCrO4

The moles can be denoted as,

MolesofPbCrO4=5.11gPbCrO4脳1molPbCrO4323.19gPbCrO4=0.0158mol0.0158molPbCrO4脳1molCr1molPbCrO4脳1molFeCr2O42molCr=7.9脳10-3mol

02

Calculating the mass of FeCr2O4

The mass can be calculated as,

MassofFeCr2O4=7.9脳10-3molFeCr2O4脳223.85gFeCr2O41molFeCr2O4MassofFeCr2O4=1.77g

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