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Is the rate of an overall reaction lower, higher, or equal to the average rate of the individual steps? Explain.

Short Answer

Expert verified

The individual steps of a reaction rate can be fast as well as slow. The average of the individual rates includes the average if fast as well as slow step. On the other hand, the overall reaction rate is the rate of the slowest step only. Hence, it would be lesser as compared to the average of the individual rates.

Step by step solution

01

What is average rate

The average rateof reaction is calculated by averaging the change in concentration over a period of time. Chemical reactions occur at different rates. A response rate is usually defined as the change in the concentration of a chemical over time.

02

Average rate of the individual steps

A reaction rate's individual steps might be both rapid and slow. The average of individual rates takes into account both quick and slow steps. The entire reaction rate, on the other hand, is simply the rate of the slowest step. As a result, it would be lower than the average of the individual rates.

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Most popular questions from this chapter

Carbon disulfide, a poisonous, flammable liquid, is an excellent solvent for phosphorus, sulfur, and some other nonmetals. A kinetic study of its gaseous decomposition reveals these data:

Experiment

Initial[CS2] mol/L

Initial rate (mol/Ls-1 )

1

0.100

2.7×10-7

2

0.080

2.2×10-7

3

0.055

1.5×10-7

4

0.044

1.2×10-7

(a) Write the rate law for the decomposition ofCS2 .

(b) Calculate the average value of the rate constant

Chlorine is commonly used to disinfect drinking water, and the inactivation of pathogens by chlorine follows first-order kinetics. The following data show E. coli inactivation:

Contact time (min)

Percent (%) inactivation

0.00

0.0

0.50

68.3

1.00

90.0

1.50

96.8

2.00

99.0

2.50

99.7

3.00

99.9

(a) Determine the first-order inactivation constant, k. [Hint: % inactivation

=100×(1-AtA0)

(b) How much contact time is required for 95% inactivation?

Even when a mechanism is consistent with the rate law, later work may show it to be incorrect. For example, the reaction between hydrogen and iodine has this rate law: rate=k[H2][I2] . The long-accepted mechanism had a single bimolecular step; that is, the overall reaction was thought to be elementary:

H2(g)+I2(g)→2HI(g)

In the 1960s, however, spectroscopic evidence showed the presence of free I atoms during the reaction. Kineticists have since proposed a three-step mechanism:

(1)I2(g)⇌2I(g)[fast](2)H2(g)+I(g)⇌H2I(g)[fast](3)H2I(g)+I(g)⇌2HI(g)[slow]

Show that this mechanism is consistent with the rate law.

Question: Reaction rate is expressed in terms of changes in concentration of reactants and products. Write a balanced equation for

Rate=-∆[CH4]∆t=12∆[O2]∆t=12∆[H2O]∆t=-∆[CO2]∆t

The rate constant of a reaction is 4.7×10-3s-1at 250C, and the activation energy is 33.6 kJ/mol. What is k at 750C?

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