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Chapter 19: Q19.95P (page 875)

Write a balanced equation for the reaction of ${Hg(H}_{2} {O)}_{4}^{2 +}$ in aqueous $KCN$ .

Short Answer

Expert verified

The balanced equation for the reaction of $Hg {(H_{2} O)}_{4}^{2 +}$ in aqueous KCN is 鈥�

$Hg {(H_{2} O)}_{4}^{2 +} (aq) + 4 {CN}^{-} (aq) 鈬� Hg (CN)_{4}^{2 -} (aq) + 4 H_{2} O (l)$

Step by step solution

01

Concept Introduction

A chemical equation is a representation of a chemical process in the form of components. A balanced chemical equation is one in which the number of atoms in all of the molecules is equal on both sides of the equation.

02

Balanced Equation for Hg(H2O)42 +

First mention that the coordination number for $Hg(II)$ is $4$ . Thus, when $Hg {(H_{2} O)}_{4}^{2 +}$ reacts with $KCN$ , there can't be more than ${4 CN}^{-}$ ions coordinated to $Hg(II)$ .

The reaction is as follows 鈥�

$Hg {(H_{2} O)}_{4}^{2 +} (aq) + 4 {CN}^{-} (aq) 鈬� Hg (CN)_{4}^{2 -} (aq) + 4 H_{2} O (l) K_{f} = \frac{[Hg (CN)_{4}^{2 -}]}{[Hg {(H_{2} O)}_{4}^{2 +}] 脳 {[{CN}^{-}]}^{4}}$

Liquid and solid compounds are not included in in K_f expression.

Therefore, the balanced equation is:

$Hg {(H_{2} O)}_{4}^{2 +} {(aq) + 4CN}^{-} (aq) 鈬� {Hg(CN)}_{4}^{2 -} {(aq) + 4H}_{2} O(l)$ .

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