Q19.17P Find the pH of a buffer that con... [FREE SOLUTION]

Chapter 19: Q19.17P (page 873)

Find the pH of a buffer that consists of 1.3M sodium phenolate ( $C_{6} H_{5} ONa$ ) and 1.2M phenol ( $C_{6} H_{5} OH$ ) ( ${pK}_{a}$ of phenol=10.00)?

Short Answer

Expert verified

The pH value of the given buffer solution is 10.03.

Step by step solution

Define Ionic Equilibrium

An ionic equilibrium refers to an equilibrium that exists in the solution of weak electrolytes between unionized molecules and ions.

The pH of the given solution

Write the 1.2 M $C_{6} H_{5} OH$ dissociation equation first.

$C_{6} H_{5} {OH +H}_{2} O 鈬� C_{6} H_{5} O^{-} {+H}_{3} O^{+} .$

Then, write the 1.3 M $C_{6} H_{5} ONa$ dissociation equation.

$C_{6} H_{5} ONa 鈫� C_{6} H_{5} O^{-} {+ Na}^{+} .$

We now have the initial phenol and phenolate concentrations.

$C_{6} H_{5} OH = 1.2 M. C_{6} H_{5} O^{-} = 1.3 M.$

To find the pH, we may utilize the Henderson-Hasselbalch equation.

$pH = pKa + log \frac{[C_{6} H_{5} O^{-}]}{[C_{6} H_{5} OH]} = 10.00 + log \frac{1.3 M}{1.2 M} = 10.03.$

Therefore, the pH value of the given buffer solution is 10.03.

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91影视

Find the pH of a buffer that consists of 1.3M sodium phenolate ( $C_{6} H_{5} ONa$ ) and 1.2M phenol ( $C_{6} H_{5} OH$ ) ( ${pK}_{a}$ of phenol=10.00)?

Short Answer

Step by step solution

Define Ionic Equilibrium

The pH of the given solution

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91影视

Find the pH of a buffer that consists of 1.3M sodium phenolate (C6H5ONa) and 1.2M phenol (C6H5OH) (pKaof phenol=10.00)?

Short Answer

Step by step solution

Define Ionic Equilibrium

The pH of the given solution

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Chemistry Textbooks

Inorganic Chemistry

Chemical Analysis

The Earths Atmosphere

Nuclear Chemistry

Organic Chemistry

Chemistry Branches

Study anywhere. Anytime. Across all devices.

Find the pH of a buffer that consists of 1.3M sodium phenolate ( $C_{6} H_{5} ONa$ ) and 1.2M phenol ( $C_{6} H_{5} OH$ ) ( ${pK}_{a}$ of phenol=10.00)?