Chapter 19: Problem 81
Balance these ionic redox equations by any method. a. \(\mathrm{Mg}+\mathrm{Fe}^{3+} \rightarrow \mathrm{Mg}^{2+}+\mathrm{Fe}\) b. \(\mathrm{ClO}_{3}^{-}+\mathrm{SO}_{2} \rightarrow \mathrm{Cl}^{-}+\mathrm{SO}_{4}^{2-}(\text { in acid solution })\)
Short Answer
Expert verified
The balanced ionic redox equations are: \\
a) \( 3\mathrm{Mg} + 2\mathrm{Fe}^{3+} \rightarrow 3\mathrm{Mg}^{2+} + 2\mathrm{Fe} \) \\
b) \( 3\mathrm{SO}_2 + 3\mathrm{ClO}_{3}^- + 6\mathrm{H}^+ \rightarrow 3\mathrm{SO}_{4}^{2-} + 3\mathrm{Cl}^- + 9\mathrm{H}_2\mathrm{O} \)
Step by step solution
01
Identify the oxidation states
For the first reaction (Mg + Fe鲁鈦 鈫 Mg虏鈦 + Fe), let's assign oxidation states to each of the elements:
Mg: 0 (in its elemental form) \\
Fe鲁鈦: +3 \\
Mg虏鈦: +2 \\
Fe: 0 (in its elemental form)
02
Write the half-reactions
From the oxidation states, we can now write the half-reactions:
Oxidation half-reaction: Mg 鈫 Mg虏鈦 + 2e鈦 \\
Reduction half-reaction: Fe鲁鈦 + 3e鈦 鈫 Fe
03
Balance the electron transfer
In order to balance the electron transfer, multiply the oxidation half-reaction by 3 and the reduction half-reaction by 2:
Oxidation: (3) x (Mg 鈫 Mg虏鈦 + 2e鈦) \\
Reduction: (2) x (Fe鲁鈦 + 3e鈦 鈫 Fe)
04
Combine the balanced half-reactions
Now, we can combine the balanced half-reactions and cancel out the electrons:
3Mg + 2Fe鲁鈦 鈫 3Mg虏鈦 + 2Fe
#b. Chlorate and Sulfur dioxide reaction#
05
Identify the oxidation states
For the second reaction, assign the oxidation states in acid solution:
Cl in ClO鈧冣伝: +5 \\
O in SO鈧: -2 \\
Cl鈦: -1 \\
S in SO鈧劼测伝: +6
06
Write the half-reactions
From the oxidation states, write the half-reactions:
Oxidation half-reaction: SO鈧 鈫 SO鈧劼测伝 \\
Reduction half-reaction: ClO鈧冣伝 鈫 Cl鈦
07
Balance the half-reactions including H and OH鈦 ions in acid solution
Balance the half-reactions by adding appropriate numbers of H鈧侽, H鈦, and e鈦 (as needed) to each side:
Oxidation: SO鈧 + 2H鈧侽 鈫 SO鈧劼测伝 + 4H鈦 + 2e鈦 \\
Reduction: ClO鈧冣伝 + 6e鈦 + 6H鈦 鈫 Cl鈦 + 3H鈧侽
08
Balance the electron transfer
In order to balance the electron transfer, multiply the oxidation half-reaction by 3 and leave the reduction half-reaction as is:
Oxidation: (3) x (SO鈧 + 2H鈧侽 鈫 SO鈧劼测伝 + 4H鈦 + 2e鈦) \\
Reduction: ClO鈧冣伝 + 6e鈦 + 6H鈦 鈫 Cl鈦 + 3H鈧侽
09
Combine the balanced half-reactions
Combine the balanced half-reactions and cancel out the electrons:
3SO鈧 + 3ClO鈧冣伝 + 6H鈦 鈫 3SO鈧劼测伝 + 3Cl鈦 + 9H鈧侽
The complete balanced ionic redox equations are: \\
a) 3Mg + 2Fe鲁鈦 鈫 3Mg虏鈦 + 2Fe \\
b) 3SO鈧 + 3ClO鈧冣伝 + 6H鈦 鈫 3SO鈧劼测伝 + 3Cl鈦 + 9H鈧侽
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Oxidation and Reduction
Understanding oxidation and reduction is crucial for grasping the concept of redox reactions. In the realm of chemistry, these two processes are always linked鈥攚here one substance loses electrons (oxidation), another gains electrons (reduction).
Oxidation is the process which involves the loss of electrons. When magnesium (Mg) turns into a magnesium ion (Mg虏鈦), it loses two electrons, signifying it has been oxidized. Reduction, on the contrary, entails gaining electrons. Iron (III) ion (Fe鲁鈦) gains three electrons to revert back to metallic iron (Fe), demonstrating a reduction.
In contextualizing the concept:
Oxidation is the process which involves the loss of electrons. When magnesium (Mg) turns into a magnesium ion (Mg虏鈦), it loses two electrons, signifying it has been oxidized. Reduction, on the contrary, entails gaining electrons. Iron (III) ion (Fe鲁鈦) gains three electrons to revert back to metallic iron (Fe), demonstrating a reduction.
In contextualizing the concept:
- Oxidation: Mg 鈫 Mg虏鈦 + 2e鈦 (loses 2 electrons)
- Reduction: Fe鲁鈦 + 3e鈦 鈫 Fe (gains 3 electrons)
Half-Reaction Method
The half-reaction method is fundamental for balancing redox reactions. It is a systematic approach that breaks down the overall redox reaction into two separate half-reactions鈥攐ne for oxidation and one for reduction. Each half-reaction is balanced individually for mass and charge, before combining them back together for the final balanced equation.
For instance:
For instance:
Balancing Magnesium and Iron Reaction
- Write two half-reactions for oxidation and reduction.
- Balance the atoms other than oxygen and hydrogen first.
- Balance oxygen atoms by adding H2O, hydrogen atoms by adding H鈦 (in acidic solutions), and charge by adding electrons.
- Multiply each half-reaction by appropriate coefficients to balance the electrons transferred.
- Add the half-reactions together and simplify to remove any species that appear on both sides of the equation.
Oxidation States
Oxidation states, also known as oxidation numbers, provide insight into the degree of oxidation or reduction of an atom within a molecule or ion. They are hypothetical charges that an atom would have if all bonds were ionic, with no covalent component.
In the provided example, oxidation states allow us to determine which elements have been oxidized or reduced:
In the provided example, oxidation states allow us to determine which elements have been oxidized or reduced:
- Mg goes from 0 to +2, indicating oxidation.
- Fe鲁鈦 goes from +3 to 0, indicating reduction.
- An element in its standard state has an oxidation state of 0.
- The sum of oxidation states for a neutral compound is 0.
- In ions, the sum of oxidation states equals the charge of the ion.
- Typically, oxygen has an oxidation state of -2, and hydrogen has +1 in compounds (except metal hydrides where it's -1).