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Write balanced chemical equations for the two successive ionizations of carbonic acid in water. Identify the conjugate-base pair in each of the equations.

Short Answer

Expert verified
The two successive ionizations of carbonic acid in water are given by: 1. \( H_2CO_3 (aq) + H_2O (l) \rightleftharpoons HCO_3^- (aq) + H_3O^+ (aq) \) - Conjugate-base pair: Carbonic acid (H2CO3) and Bicarbonate ion (HCO3-) 2. \( HCO_3^- (aq) + H_2O (l) \rightleftharpoons CO_3^{2-} (aq) + H_3O^+ (aq) \) - Conjugate-base pair: Bicarbonate ion (HCO3-) and Carbonate ion (CO3^2-)

Step by step solution

01

Define the Dissociation Reaction

When a polyprotic acid like carbonic acid (H2CO3) is dissolved in water, it donates one or more of its protons, usually one proton per step, to water molecules to form hydronium ions (H3O+). The acid loses a proton and converts into its conjugate base.
02

Write the Reaction Equations for the Two Successive Ionizations

The first ionization of carbonic acid occurs when H2CO3 donates a proton (H+) to a water molecule, resulting in the formation of the bicarbonate ion (HCO3-) and a hydronium ion (H3O+). \( H_2CO_3 (aq) + H_2O (l) \rightleftharpoons HCO_3^- (aq) + H_3O^+ (aq) \) The second ionization occurs when the bicarbonate ion (HCO3-) donates a proton (H+) to another water molecule, resulting in the formation of the carbonate ion (CO3^2-) and another hydronium ion (H3O+). \( HCO_3^- (aq) + H_2O (l) \rightleftharpoons CO_3^{2-} (aq) + H_3O^+ (aq) \)
03

Identify the Conjugate-Base Pairs

For each reaction, the conjugate-base pair comprises the acid and the conjugate base formed after donating a proton. In the first ionization reaction: - Acid: Carbonic acid (H2CO3) - Conjugate base: Bicarbonate ion (HCO3-) In the second ionization reaction: - Acid: Bicarbonate ion (HCO3-) - Conjugate base: Carbonate ion (CO3^2-) Every time a proton is donated, the species acts like an acid, and the species formed after accepting the proton acts like its corresponding conjugate base.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Carbonic Acid Ionization
Carbonic acid (H鈧侰O鈧) is an example of a polyprotic acid, meaning it can donate more than one proton. In water, carbonic acid ionizes through two successive steps. The first step involves donating a proton (H鈦) to a water molecule (H鈧侽), turning it into a hydronium ion (H鈧僌鈦) while forming a bicarbonate ion (HCO鈧冣伝). The equation for this reaction is:

\[H_2CO_3 (aq) + H_2O (l) \rightleftharpoons HCO_3^- (aq) + H_3O^+ (aq)\]

In the second ionization step, the bicarbonate ion (HCO鈧冣伝) donates another proton to another water molecule, forming a carbonate ion (CO鈧僞{2-}) and another hydronium ion (H鈧僌鈦):

\[HCO_3^- (aq) + H_2O (l) \rightleftharpoons CO_3^{2-} (aq) + H_3O^+ (aq)\]

These are typical ionizations of carbonic acid demonstrating its capability to release protons in stages.
Conjugate Acid-Base Pair
In each ionization step, the acid forms from losing a proton and transforms into its conjugate base. A conjugate acid-base pair consists of two species that transform into each other by the gain or loss of a proton.

In the first ionization of carbonic acid:
  • Acid: H鈧侰O鈧 (carbonic acid)
  • Conjugate Base: HCO鈧冣伝 (bicarbonate ion)
In the second ionization:
  • Acid: HCO鈧冣伝 (bicarbonate ion)
  • Conjugate Base: CO鈧僞{2-} (carbonate ion)
Identifying these pairs is key to understanding acid-base chemistry, where the species that gives away a proton is the acid, and the one that takes the proton is its conjugate base.
Dissociation of Acids
Dissociation in chemistry refers to the process where molecules break down into smaller components. When acids dissociate in water, they release protons (hydrogen ions, H鈦 ) into the solution. For carbonic acid, this dissociation occurs in steps as it's polyprotic.

Each dissociation step for acids like carbonic acid is important:
  • First step dissociation: Releases the first H鈦 and forms bicarbonate HCO鈧冣伝 .
  • Second step dissociation: Releases another H鈦 from the bicarbonate to form carbonate CO鈧僞{2-} .
The careful step-wise nature of these dissociations helps control the pH values of solutions, given that each dissociation provides different amounts of H鈦 .
Hydronium Ion Formation
Hydronium ions ( H鈧僌鈦 ) play a fundamental role in the chemistry of acids in water. They form when protons ( H鈦 ) donated by acids such as carbonic acid, interact with water molecules. The presence of hydronium ions is why acidic solutions turn pH indicators certain colors.

Formation happens like this:
  • H鈧侰O鈧 donates H鈦 to water: H鈧侽 receives H鈦 forming H鈧僌鈦 .
  • Bicarbonate HCO鈧冣伝 repeats this in the second step to form another H鈧僌鈦 .
The production of hydronium ions is essential for defining the acidity in any solution.
Polyprotic Acid Reactions
Polyprotic acids like carbonic acid are unique because they can donate multiple hydrogen ions. Their reactions are stepwise, and for any polyprotic acid, each step involves a proton release.

Key features of these reactions:
  • Each proton donation happens one step at a time, first forming HCO鈧冣伝 , then CO鈧僞{2-} .
  • The acidity decreases with each step; the H鈧侰O鈧 to HCO鈧冣伝 is more acidic than HCO鈧冣伝 to CO鈧僞{2-} .
Understanding these reactions helps in predicting the behavior of polyprotic acids in different chemical environments.

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