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Calculate The \(K_{s p}\) of magnesium carbonate \(\left(\mathrm{Mg} \mathrm{CO}_{3}\right)\) is \(2.6 \times 10^{-9} .\) What is the solubility of \(\mathrm{Mg} \mathrm{CO}_{3}\) in pure water?

Short Answer

Expert verified
The solubility of magnesium carbonate (MgCO3) in pure water is approximately \(1.61 \times 10^{-5}\) M.

Step by step solution

01

Write the balanced chemical equation for the dissolution of MgCO3

First, we need to write the balanced chemical equation for the dissolution of magnesium carbonate in water: \(MgCO_3 (s) \rightleftharpoons Mg^{2+} (aq) + CO_3^{2-} (aq)\) Where (s) indicates the solid state, and (aq) indicates the aqueous state. This equation shows that one mole of solid magnesium carbonate dissociates into one mole of magnesium ions (Mg虏鈦) and one mole of carbonate ions (CO鈧兟测伝).
02

Write the Ksp expression

Now we will set up the Ksp expression for the dissolution of magnesium carbonate. The solubility product constant, Ksp, is equal to the product of the ion concentrations raised to the power of their respective stoichiometric coefficients: \(K_{sp} =[Mg^{2+}] [CO_3^{2-}]\)
03

Define the solubility of MgCO3

Let the solubility of magnesium carbonate in water be 鈥淪,鈥 which represents the concentration in moles per liter (M). Since MgCO3 dissociates into 1 mole of Mg虏鈦 and 1 mole of CO鈧兟测伝, at equilibrium we can say: [Mg虏鈦篯 = S [CO鈧兟测伝] = S
04

Substitute the Ksp expression with solubility

Now we replace the ion concentrations in the Ksp expression with the solubility (S) and known Ksp value (2.6 x 10鈦烩伖): \(2.6 \times 10^{-9} = S^2\)
05

Solve for solubility (S)

Finally, solve for S by taking the square root of both sides of the equation: \(S = \sqrt{2.6 \times 10^{-9}}\) \(S \approx 1.61 \times 10^{-5} M\) The solubility of magnesium carbonate (MgCO3) in pure water is approximately \(1.61 \times 10^{-5}\) M.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Equilibrium
When it comes to understanding how substances dissolve in water, chemical equilibrium plays a central role. Chemical equilibrium occurs when the rate of the forward reaction, in this case the dissolution of a compound into ions, is equal to the rate of the reverse reaction, the reformation of the solid from the ions. At equilibrium, the concentration of the reactants and products remain constant.

In the context of solubility, when a sparingly soluble solid like magnesium carbonate (\(MgCO_3\)) is added to water, it dissociates to a limited extent into its ions (\(Mg^{2+}\) and \(CO_3^{2-}\) ions), establishing a dynamic equilibrium with the undissolved solid. The balanced equation for dissolution of magnesium carbonate in water is:
\(MgCO_3 (s) \rightleftharpoons Mg^{2+} (aq) + CO_3^{2-} (aq)\)

The point at which this system reaches equilibrium is described quantitatively by the solubility product constant (Ksp), which in essence, gives us a measure of how much of the solid can dissolve in water at a certain temperature.
Dissociation of Ionic Compounds
Ionic compounds like magnesium carbonate consist of positive and negative ions held together by ionic bonds. When an ionic compound dissolves in water, the process known as dissociation occurs. This is when the ionic compound breaks apart into its component ions.

For example, when magnesium carbonate (\(MgCO_3\)) is placed in water, it dissociates into magnesium ions (\(Mg^{2+}\)) and carbonate ions (\(CO_3^{2-}\)). The dissolution process can be represented by a balanced chemical equation, which is crucial in understanding the stoichiometry of the ions being produced. The one-to-one stoichiometry indicated in the magnesium carbonate dissolution equation means that for each mole of \(MgCO_3\) that dissolves, one mole of \(Mg^{2+}\) ions and one mole of \(CO_3^{2-}\) ions are produced. Keep in mind not all ionic compounds dissociate completely; only those soluble enough to exceed their Ksp will do so.
Molar Solubility
Molar solubility is the number of moles of a substance that can be dissolved in a liter of solution before reaching saturation. It gives us insight into how much of a compound can dissolve in a given amount of solvent at a specified temperature and is expressed in moles per liter (M).

In the example of magnesium carbonate, we have calculated the molar solubility based on the known Ksp value. We expressed the solubility (S) of \(MgCO_3\) in terms of M, where S is equated to the concentrations of \(Mg^{2+}\) and \(CO_3^{2-}\) in moles per liter at equilibrium due to the one-to-one ratio of their production upon dissociation.

Understanding molar solubility is not only critical for predicting the extent to which a compound will dissolve but also important for applications such as drug delivery, where the solubility of a compound can affect its bioavailability. It is also worth noting that solubility can be affected by factors such as temperature, pressure, and the presence of other ions in the solution which may interact with the ions of the compound being dissolved.

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