Chapter 14: Problem 20
How many grams of \(\mathrm{CaCl}_{2}\) would be dissolved in 1.0 \(\mathrm{L}\) of a 0.10 \(\mathrm{M}\) solution of \(\mathrm{CaCl}_{2} ?\)
Short Answer
Expert verified
Approximately 11.10 grams of CaCl2 would be dissolved in 1.0 L of a 0.10 M solution of CaCl2.
Step by step solution
01
Write down the given information
We are given:
- Molarity (M) = 0.10 M
- Volume (V) = 1.0 L
02
Find the moles of CaCl2
To determine the moles of CaCl2, we can use the formula:
moles = molarity × volume
moles = 0.10 mol/L × 1.0 L
moles = 0.10 mol
03
Calculate the molar mass of CaCl2
CaCl2 consists of 1 calcium atom and 2 chlorine atoms. The molar mass of each element is:
- Molar mass of Calcium (Ca) = 40.08 g/mol
- Molar mass of Chlorine (Cl) = 35.45 g/mol
So, the molar mass of CaCl2 is:
Molar mass of CaCl2 = (1 × 40.08) + (2 × 35.45)
Molar mass of CaCl2 = 40.08 + 70.90
Molar mass of CaCl2 = 110.98 g/mol
04
Calculate the mass of CaCl2
Now that we have the moles and molar mass, we can determine the mass:
mass = moles × molar mass
mass = 0.10 mol × 110.98 g/mol
mass = 11.098 g
05
Round the answer
Let's round the answer to two decimal places:
mass ≈ 11.10 g
So, approximately 11.10 grams of CaCl2 would be dissolved in 1.0 L of a 0.10 M solution of CaCl2.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Moles calculation
Calculating moles is a key step in understanding solutions in chemistry. The mole is a standard unit for amount of substance used in chemistry, often symbolized as \( n \). To find the number of moles for a given chemical solution, you can use the formula:
- \( \text{moles (n)} = \text{molarity (M)} \times \text{volume (V)} \)
- \( \text{moles} = 0.10 \text{ mol/L} \times 1.0 \text{ L} = 0.10 \text{ mol} \)
Molar mass
Molar mass is the weight of one mole of a given substance and is expressed in grams per mole (g/mol). To determine the molar mass, you add up the atomic masses of each element in a molecule based on its chemical formula.In the case of \(\mathrm{CaCl}_{2}\), we need to consider:
- The atomic mass of calcium (Ca), which is \(40.08 \text{ g/mol}\).
- The atomic mass of chlorine (Cl), which is \(35.45 \text{ g/mol}\).
- \( \text{Molar mass of } \mathrm{CaCl}_{2} = (1 \times 40.08) + (2 \times 35.45) = 110.98 \text{ g/mol} \)
Chemical solution preparation
Preparing a chemical solution requires knowledge of both the concentration (molarity) and the total volume you want to create. This process involves calculating the precise amount of solute - in grams - to be dissolved in a solvent.To determine how many grams of \(\mathrm{CaCl}_{2}\) you need, follow these steps:
- First, calculate the moles required using the desired molarity and volume: \(0.10 \text{ mol/L} \times 1.0 \text{ L} = 0.10 \text{ mol}\).
- Then, convert moles to grams using the molar mass calculated:\( \text{mass} = \text{moles} \times \text{molar mass} \).
- For \(\mathrm{CaCl}_{2}\), with a molar mass of \(110.98 \text{ g/mol}\), the calculation is: \( \text{mass} = 0.10 \text{ mol} \times 110.98 \text{ g/mol} = 11.10 \text{ g}\).