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Which of these elements is unlikely to form covalent bonds: \(\mathrm{S}, \mathrm{H}, \mathrm{K}, \mathrm{Ar}, \mathrm{Si}\) ? Explain your choices.

Short Answer

Expert verified
Argon (Ar) is the element that is unlikely to form covalent bonds due to its stable electron configuration as a noble gas, which means it has little tendency to form bonds with other elements.

Step by step solution

01

Review the properties of each element

First, let's briefly discuss the properties of the given elements. 1. Sulfur (S): Sulfur is a nonmetal element in group 16, also known as the chalcogens. Sulfur typically forms covalent bonds, sharing two electrons to achieve a stable electron configuration. 2. Hydrogen (H): Hydrogen is a nonmetal element with only one electron in its outermost shell. It usually forms covalent bonds because it can share this electron with another element to achieve the stable electron configuration of helium. 3. Potassium (K): Potassium is an alkali metal in group 1. Alkali metals generally form ionic bonds by donating one electron to form a +1 cation and achieve a stable electron configuration. 4. Argon (Ar): Argon is a noble gas in group 18, with a full outer electron shell and a very stable electron configuration. Noble gases generally do not form bonds because they are already stable and do not need to share or transfer electrons. 5. Silicon (Si): Silicon is a metalloid element in group 14, also known as the carbon group. Silicon typically forms covalent bonds, sharing four electrons to achieve a stable electron configuration.
02

Identify the element that is unlikely to form covalent bonds

Looking at the properties of each element, it is clear that potassium (K) and argon (Ar) are the least likely to form covalent bonds: - Potassium (K) is an alkali metal that typically forms ionic bonds by donating one electron to form a +1 cation. - Argon (Ar) is a noble gas with a stable electron configuration, which means it has little tendency to form bonds with other elements. However, potassium does form bonds (albeit ionic ones), while argon generally does not form bonds at all due to its stable electron configuration. Therefore, the correct answer is: Argon (Ar) is the element that is unlikely to form covalent bonds.

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Most popular questions from this chapter

Calculate the formal charge on the indicated atom in each of the following molecules or ions: (a) the central oxygen atom in \(\mathrm{O}_{3}\), (b) phosphorus in \(\mathrm{PF}_{6}^{-}\), (c) nitrogen in \(\mathrm{NO}_{2}\), (d) iodine in \(\mathrm{ICl}_{3}\), (e) chlorine in \(\mathrm{HClO}_{4}\) (hydrogen is bonded to \(\mathrm{O}\) ).

(a) Write the electron configuration for the element titanium, Ti. How many valence electrons does this atom possess? (b) Hafnium, Hf, is also found in group \(4 \mathrm{~B}\). Write the electron configuration for Hf. (c) Both \(\mathrm{Ti}\) and Hf behave as though they possess the same number of valence electrons. Which of the subshells in the electron configuration of Hf behave as valence orbitals? Which behave as core orbitals?

Based on data in Table \(8.2\), estimate (within \(30 \mathrm{~kJ} / \mathrm{mol}\) ) the lattice energy for (a) LiBr, (b) \(\mathrm{CsBr}\), (c) \(\mathrm{CaCl}_{2}\).

(a) Based on the lattice cncrgics of \(\mathrm{MgCl}_{2}\) and \(\mathrm{SrCl}_{2}\) given in Table 8.2, what is the range of values that you would expect for the lattice energy of \(\mathrm{CaCl}_{2}\) ? (b) Using data from Appendix C, Figure 7.12, and Figure \(7.14\) and the value of the second ionization energy for \(\mathrm{Ca}\), \(1145 \mathrm{~kJ} / \mathrm{mol}\), calculate the lattice energy of \(\mathrm{CaCl}_{2}\).

Write the electron configuration for phosphorus. Identify the valence electrons in this configuration and the nonvalence electrons. From the standpoint of chemical reactivity, what is the important difference between them?

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