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Write a balanced equation for the ionization of nitric acid in water.

Short Answer

Expert verified
HNO鈧 ionizes to form H鈧僌鈦 and NO鈧冣伝 in water, written as: HNO鈧(aq) + H鈧侽(l) 鈫 NO鈧冣伝(aq) + H鈧僌鈦(aq).

Step by step solution

01

Understanding the Ionization Process

Nitric acid (HNO鈧) is a strong acid that ionizes completely in water. The ionization of an acid in water typically involves the transfer of a proton (H鈦) from the acid to water (H鈧侽), forming a hydronium ion (H鈧僌鈦).
02

Identify Reactants and Products

In water, the nitric acid (HNO鈧) ionizes to form nitrate ions (NO鈧冣伝) and hydronium ions (H鈧僌鈦). The reactants are nitric acid (HNO鈧) and water (H鈧侽), and the products are nitrate ions (NO鈧冣伝) and hydronium ions (H鈧僌鈦).
03

Write the Chemical Equation

Write the balanced chemical equation that represents the ionization process. The chemical equation is:\[ \text{HNO}_3 (aq) + \text{H}_2\text{O} (l) \rightarrow \text{NO}_3^- (aq) + \text{H}_3\text{O}^+ (aq) \]
04

Verify Equation Balance

Check if the number of atoms for each element is balanced on both sides of the equation. All elements should appear in equal numbers on both the reactant and product sides.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ionization Process
The ionization process is a fundamental concept in chemistry, especially when dealing with acids and bases. When an acid dissolves in water, it breaks apart into its ions. This is called ionization. The process often involves the acid donating a proton (H鈦) to a molecule of water (H鈧侽). As a result, new ions are formed. This is characteristic of how acids behave in aqueous solution.

In the case of nitric acid (HNO鈧), it dissociates completely in water. The nitric acid, being a strong acid, will ionize fully. This means that each molecule of nitric acid will donate a proton to a water molecule, which leads to the formation of hydronium ions (H鈧僌鈦) and nitrate ions (NO鈧冣伝). This process can be seen in many strong acids.
Proton Transfer
Proton transfer is a key part of how acids interact with water during ionization. In this process, a proton (H鈦) is transferred from the acid to a water molecule. This is a typical behavior of acids in water. The transfer of a proton fundamentally changes the components involved, turning water into a hydronium ion.

To visualize this: imagine HNO鈧 splitting in water. It loses a proton, while water accepts this proton, becoming H鈧僌鈦. This exchange signifies a chemical change and is critical for understanding reactions in chemistry involving acids and bases. Proton transfer thus marks the creation of different ions from the original molecules.
Strong Acids
Strong acids like nitric acid (HNO鈧) have a specific property: they ionize completely in water. This means that when a strong acid is dissolved, it fully separates into its constituent ions.

The stronger the acid, the more readily it donates protons to the water, increasing the concentration of hydronium ions in the solution. This concept is crucial for comprehending the strength and behavior of various acids. Other examples of strong acids include hydrochloric acid (HCl) and sulfuric acid (H鈧係O鈧), which also ionize completely in water, similar to nitric acid.
  • Complete ionization is a hallmark characteristic of strong acids.
  • This results in higher conductivity of the solution due to the free moving ions.
Understanding the nature of strong acids aids in predicting the outcomes of various chemical reactions they are involved in.
Hydronium Ion Formation
Hydronium ion formation is a crucial outcome of the ionization process in water. As the acid donates a proton to water, the water molecule is transformed into a hydronium ion (H鈧僌鈦).

The creation of hydronium ions in solution is essential because it represents the increased acidity of the solution. A higher concentration of hydronium ions corresponds to a lower pH, indicating stronger acidity.

For instance, when HNO鈧 dissolves in water, each HNO鈧 molecule contributes one hydronium ion, demonstrating a direct impact on the acidity of the solution. This is why understanding hydronium ion formation is fundamental when discussing the properties and behavior of acids.

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Most popular questions from this chapter

A compound has been isolated that can have either of two possible formulas: (a) \(\mathrm{K}\left[\mathrm{Fe}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)_{2}\left(\mathrm{H}_{2} \mathrm{O}\right)_{2}\right]\) or (b) \(\mathrm{K}_{3}\left[\mathrm{Fe}\left(\mathrm{C}_{2} \mathrm{O}_{4}\right)_{3}\right] .\) To find which is correct, you dissolve a weighed sample of the compound in acid and then titrate the oxalate ion \(\left(\mathrm{C}_{2} \mathrm{O}_{4}^{2}\right)\) that comes from the compound with potassium permanganate, \(\mathrm{KMnO}_{4}\) (the source of the \(\mathrm{MnO}_{4}^{-}\) ion). The balanced, net ionic equation for the titration is $$\begin{array}{rl}5 \mathrm{C}_{2} \mathrm{O}_{4}^{2-}(\mathrm{aq})+2 \mathrm{MnO}_{4}^{-}(\mathrm{aq})+16 \mathrm{H}^{+}(\mathrm{aq}) & \longrightarrow \\\2 \mathrm{Mn}^{2+}(\mathrm{aq})+10 \mathrm{CO}_{2}(\mathrm{g})+8 & \mathrm{H}_{2} \mathrm{O}(\ell) \end{array}$$ Titration of \(1.356 \mathrm{g}\) of the compound requires \(34.50 \mathrm{mL}\) of \(0.108 \mathrm{M} \mathrm{KMnO}_{4} .\) Which is the correct formula of the iron-containing compound: (a) or (b)?

You have \(0.954 \mathrm{g}\) of an unknown acid, \(\mathrm{H}_{2} \mathrm{A},\) which reacts with NaOH according to the balanced equation \(\mathrm{H}_{2} \mathrm{A}(\mathrm{aq})+2 \mathrm{NaOH}(\mathrm{aq}) \longrightarrow \mathrm{Na}_{2} \mathrm{A}(\mathrm{aq})+2 \mathrm{H}_{2} \mathrm{O}(\ell)\) If 36.04 mI. of \(0.509 \mathrm{M} \mathrm{NaOH}\) is required to titrate the acid to the equivalence point, what is the molar mass of the acid?

Balance the equation for the following precipitation reaction, and then write the net ionic equation. Indicate the state of each species \((s, \ell, \text { aq, or } g\) ). $$\mathrm{CdCl}_{2}+\mathrm{NaOH} \longrightarrow \mathrm{Cd}(\mathrm{OH})_{2}+\mathrm{NaCl}$$

What mass of oxalic acid, \(\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4},\) is required to prepare \(250 .\) mL of a solution that has a concentration of \(0.15 \mathrm{M}\) \(\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{D}_{4} ?\)

Identify each of the following substances as an oxidizing or reducing agent: \(\mathrm{HNO}_{3}, \mathrm{Na}, \mathrm{Cl}_{2}, \mathrm{O}_{2}, \mathrm{KMnO}_{4}\).

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