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Give the relative rates of disappearance of reactants and formation of products for each of the following reactions. (a) \(2 \mathrm{O}_{3}(\mathrm{g}) \longrightarrow 3 \mathrm{O}_{2}(\mathrm{g})\) (b) \(2 \mathrm{HOF}(\mathrm{g}) \longrightarrow 2 \mathrm{HF}(\mathrm{g})+\mathrm{O}_{2}(\mathrm{g})\)

Short Answer

Expert verified
(a) \(R_{\mathrm{O}_{3}} = -\frac{1}{2} \frac{d[\mathrm{O}_{3}]}{dt}\), \(R_{\mathrm{O}_{2}} = \frac{1}{3} \frac{d[\mathrm{O}_{2}]}{dt}\); (b) \(R_{\mathrm{HOF}} = -\frac{1}{2} \frac{d[\mathrm{HOF}]}{dt}\), \(R_{\mathrm{HF}} = \frac{1}{2} \frac{d[\mathrm{HF}]}{dt}\), \(R_{\mathrm{O}_{2}} = \frac{d[\mathrm{O}_{2}]}{dt}\).

Step by step solution

01

Understanding Relative Rates

For a reaction, the relative rates of disappearance or formation can be understood in terms of stoichiometry from the balanced chemical equation. The general formula involves using the stoichiometric coefficients to express these rates. The rate of change in concentration for a component can be expressed as \(\frac{1}{\text{coefficient}} \times \text{rate of reaction}\).
02

Calculate Relative Rates for Reaction (a)

(a) For the reaction \(2 \mathrm{O}_{3}(\mathrm{g}) \rightarrow 3 \mathrm{O}_{2}(\mathrm{g})\), the rate of disappearance of \(\mathrm{O}_{3}\) is \(-\frac{1}{2} \frac{d[\mathrm{O}_{3}]}{dt}\). The rate of formation of \(\mathrm{O}_{2}\) is \(+\frac{1}{3} \frac{d[\mathrm{O}_{2}]}{dt}\). These expressions reflect the stoichiometric coefficients of 2 for \(\mathrm{O}_{3}\) and 3 for \(\mathrm{O}_{2}\).
03

Calculate Relative Rates for Reaction (b)

(b) For the reaction \(2 \mathrm{HOF}(\mathrm{g}) \rightarrow 2 \mathrm{HF}(\mathrm{g}) + \mathrm{O}_{2}(\mathrm{g})\), the rate of disappearance of \(\mathrm{HOF}\) is \(-\frac{1}{2} \frac{d[\mathrm{HOF}]}{dt}\). The rate of formation of \(\mathrm{HF}\) is \(+\frac{1}{2} \frac{d[\mathrm{HF}]}{dt}\), and for \(\mathrm{O}_{2}\), it is \(+\frac{1}{1} \frac{d[\mathrm{O}_{2}]}{dt}\). The rates are divided by the stoichiometric coefficients from the balanced equation.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Stoichiometry
Stoichiometry involves the study of the quantitative relationships between reactants and products in a chemical reaction. It helps us understand how much of each substance is involved or produced, which is vital for calculating relative reaction rates.
The stoichiometric coefficients in a balanced chemical equation tell us the proportions of reactants and products. For example, in the reaction \(2 \mathrm{O}_{3}(\mathrm{g}) \rightarrow 3 \mathrm{O}_{2}(\mathrm{g})\), the coefficient 2 for \(\mathrm{O}_{3}\) and 3 for \(\mathrm{O}_{2}\) informs us that 2 moles of ozone yield 3 moles of oxygen gas.
This relationship helps determine how the rate of disappearance and formation are related. Stoichiometry ultimately provides the foundation to write expressions for reaction rates, allowing us to predict how quickly a reaction proceeds.
Rate of Disappearance
The rate of disappearance describes how quickly a reactant is consumed in a chemical reaction. It's a measure of the decrease in concentration of a reactant over time.
To find this rate, you use the stoichiometric coefficient from the equation. For example, with \(2 \mathrm{O}_{3}(\mathrm{g}) \rightarrow 3 \mathrm{O}_{2}(\mathrm{g})\), the rate at which \(\mathrm{O}_{3}\) disappears is:
  • \(-\frac{1}{2} \frac{d[\mathrm{O}_{3}]}{dt}\)
This formula means the concentration of \(\mathrm{O}_{3}\) decreases by half of the rate of the overall reaction.
Negative signs indicate a reduction in reactant concentration. Understanding the rate of disappearance is important when determining how fast a reaction uses up reactants.
Balanced Chemical Equation
A balanced chemical equation is crucial as it represents the law of conservation of mass. It shows that atoms are neither created nor destroyed during a chemical reaction; they are simply rearranged.
Balancing equations involves ensuring the same number of each type of atom on both sides. This gives us the correct stoichiometric coefficients, which are essential for calculating reaction rates.
In reactions like \(2 \mathrm{HOF}(\mathrm{g}) \rightarrow 2 \mathrm{HF}(\mathrm{g}) + \mathrm{O}_{2}(\mathrm{g})\), each atom and molecule is accounted for:
  • 2 molecules of \(\mathrm{HOF}\) yield 2 molecules of \(\mathrm{HF}\) and 1 molecule of \(\mathrm{O}_{2}\).
This balance assures accurate calculations of reaction rates and provides a clear understanding of the chemical process.
Rate of Formation
The rate of formation refers to the speed at which a product is generated in a chemical reaction. It is proportional to how rapidly the concentration of the product increases over time.
Using the stoichiometric coefficients, as with the rate of disappearance, we can determine this rate. For example, the \(\mathrm{O}_{2}\) formation in the reaction \(2 \mathrm{O}_{3}(\mathrm{g}) \rightarrow 3 \mathrm{O}_{2}(\mathrm{g})\) is:
  • \(+\frac{1}{3} \frac{d[\mathrm{O}_{2}]}{dt}\)
Here, the positive sign shows an increase in concentration, indicating product generation.
Understanding the rate of formation helps in predicting how much product can be obtained in a given time, which is crucial for industrial and laboratory applications.

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Most popular questions from this chapter

Carbon monoxide reacts with \(\mathrm{O}_{2}\) to form \(\mathrm{CO}_{2}\) : $$2 \mathrm{CO}(\mathrm{g})+\mathrm{O}_{2}(\mathrm{g}) \longrightarrow 2 \mathrm{CO}_{2}(\mathrm{g})$$ Information on this reaction is given in the table below. $$\begin{array}{lll}\hline[\mathrm{CO}](\mathrm{mol} / \mathrm{L}) & {\left[\mathrm{O}_{2}\right](\mathrm{mol} /\mathrm{L})} & \text { Rate }(\mathrm{mol} / \mathrm{L} \cdot \mathrm{min}) \\\\\hline 0.02 & 0.02 & 3.68 \times 10^{-5} \\\0.04 & 0.02 & 1.47 \times 10^{-4} \\\0.02 & 0.04 & 7.36 \times 10^{-5} \\\\\hline\end{array}$$ (a) What is the rate law for this reaction? (b) What is the order of the reaction with respect to CO? What is the order with respect \(\mathrm{O}_{2} ?\) What is the overall order of the reaction? (c) What is the value for the rate constant, \(k ?\)

The decomposition of \(\mathrm{CO}_{2}\) is first order with respect to the concentration of \(\mathrm{CO}_{2}.\) $$2 \mathrm{CO}_{2}(\mathrm{g}) \longrightarrow 2 \mathrm{CO}(\mathrm{g})+\mathrm{O}_{2}(\mathrm{g})$$ Data on this reaction are provided in the table below. $$\begin{array}{lc}\hline\left[\mathrm{CO}_{2}\right](\mathrm{mol} / \mathrm{L}) & \text { Time }(\mathrm{s}) \\\\\hline 0.38 & 0 \\\0.27 & 12 \\\\\hline\end{array}$$ (a) Write the rate equation for this reaction. (b) Use the data to determine the value of \(k\) (c) What is the half-life of \(\mathrm{CO}_{2}\) under these conditions?

A Two molecules of the unsaturated hydrocarbon 1,3-butadiene \(\left(\mathrm{C}_{4} \mathrm{H}_{6}\right)\) form the "dimer" \(\mathrm{C}_{8} \mathrm{H}_{12}\) at higher temperatures. $$2 \mathrm{C}_{4} \mathrm{H}_{6}(\mathrm{g}) \longrightarrow \mathrm{C}_{8} \mathrm{H}_{12}(\mathrm{g})$$ Use the following data to determine the order of the reaction and the rate constant, \(k\). (Note that the total pressure is the pressure of the unreacted \(\mathrm{C}_{4} \mathrm{H}_{6}\) at any time and the pressure of the \(\mathrm{C}_{8} \mathrm{H}_{12} .\)) $$\begin{array}{cl}\hline \text { Time (min) } & \text { Total Pressure (mm Hg) } \\\\\hline 0 & 436 \\\3.5 & 428 \\\11.5 & 413 \\\18.3 & 401 \\\25.0 & 391 \\\32.0 & 382 \\\41.2 & 371 \\\\\hline\end{array}$$

Using the rate equation "Rate \(=k[\mathrm{A}]^{2}[\mathrm{B}],\) define the order of the reaction with respect to A and B. What is the total order of the reaction?

The reaction $$2 \mathrm{NO}(\mathrm{g})+2 \mathrm{H}_{2}(\mathrm{g}) \longrightarrow \mathrm{N}_{2}(\mathrm{g})+2 \mathrm{H}_{2} \mathrm{O}(\mathrm{g})$$ was studied at \(904^{\circ} \mathrm{C},\) and the data in the table were collected. $$\begin{array}{lll}\hline \begin{array}{l}\text { Reactant Concentration } \\\\(\mathrm{mol} / \mathrm{L})\end{array} & & \\\\\hline[\mathrm{N} 0] & {\left[\mathrm{H}_{2}\right]} & \begin{array}{l}\text { Rate of Appearance of } \mathrm{N}_{2} \\\\(\mathrm{mol} / \mathrm{L} \cdot \mathrm{s})\end{array} \\\\\hline 0.420 & 0.122 & 0.136 \\\0.210 & 0.122 & 0.0339 \\\0.210 & 0.244 & 0.0678 \\\0.105 & 0.488 & 0.0339 \\\\\hline\end{array}$$ (a) Determine the order of the reaction for each reactant. (b) Write the rate equation for the reaction. (c) Calculate the rate constant for the reaction. (d) Find the rate of appearance of \(\mathrm{N}_{2}\) at the instant when \([\mathrm{NO}]=0.350 \mathrm{mol} / \mathrm{L}\) and \(\left[\mathrm{H}_{2}\right]=0.205 \mathrm{mol} / \mathrm{L}.\)

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