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Using the rate equation "Rate \(=k[\mathrm{A}]^{2}[\mathrm{B}],\) define the order of the reaction with respect to A and B. What is the total order of the reaction?

Short Answer

Expert verified
Second order with respect to A, first order with respect to B, total order is 3.

Step by step solution

01

Understanding the Rate Law

The rate equation given is \( \text{Rate} = k[\mathrm{A}]^{2}[\mathrm{B}] \). Here, \( k \) is the rate constant, \( [\mathrm{A}] \) and \( [\mathrm{B}] \) are the concentrations of reactants A and B respectively. The exponents indicate the order of the reaction with respect to each reactant.
02

Determining the Order with Respect to A

The exponent on concentration \( [\mathrm{A}] \) is \( 2 \), which means the reaction is second order with respect to reactant A.
03

Determining the Order with Respect to B

The exponent on concentration \( [\mathrm{B}] \) is \( 1 \), as it is implicitly understood to be \( [\mathrm{B}]^1 \). This indicates the reaction is first order with respect to reactant B.
04

Calculating the Total Order of the Reaction

The total order of a reaction is the sum of the orders with respect to each reactant. Thus, the total order is \( 2 + 1 = 3 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Rate Law
In chemical kinetics, the rate law is an equation that relates the reaction rate to the concentration of reactants. It helps us understand how the speed of a reaction changes as the concentrations of the starting materials change. For example, in the rate equation given, \( \text{Rate} = k[\mathrm{A}]^{2}[\mathrm{B}] \), the rate at which the chemical reaction proceeds is a function of the concentrations of reactants A and B. The rate constant \( k \) is a proportionality constant that you can think of as a specific number that brings everything together. Different reactions have different rate laws, and discovering the rate law for a reaction can reveal a lot about the reaction mechanism, which is the step-by-step process that leads to the reaction.
Rate Constant
The rate constant, symbolized by \( k \), is an essential component of the rate law. It serves as a unique identifier for a particular reaction under certain conditions such as temperature and pressure. You might wonder why temperature is crucial here: that's because the rate constant changes with temperature, generally increasing as temperatures rise.
The units of \( k \) can define the overall order of a reaction. For instance, in this exercise, since the reaction is third-order, \( k \) would typically have units of \( \text{L}^2 \cdot \text{mol}^{-2} \cdot \text{s}^{-1} \). Understanding the rate constant helps dissect the pace at which a reaction converts reactants into products, mapping out an imaginary speedometer for chemical changes.
Concentration of Reactants
The concentration of reactants is a pivotal factor in determining the reaction rate. This concentration is expressed in terms of molarity, which measures how many moles of a substance are dissolved in a liter of solution. By looking at the exponents in the rate law \( [\mathrm{A}]^{2}[\mathrm{B}] \), we get a sense of how much each reactant influences the rate. Reactant A is squared, showing that even a slight increase in its concentration can have a large impact on the rate; this is because the rate depends on the square of its concentration.
On the other hand, reactant B is to the first power, indicating a direct, linear relationship between its concentration and the rate of the reaction. Monitoring the concentrations of reactants helps chemists predict and control the speed of reactions, which is particularly vital in industrial applications where time is crucial.
Total Reaction Order
The total reaction order is an add-up of the individual orders with respect to each reactant, giving a total order that represents the collective dependency of the rate on overall reactant concentrations. In the given exercise, with orders being 2 for \( [\mathrm{A}] \) and 1 for \( [\mathrm{B}] \), the total reaction order sums up to 3. This sum tells us how sensitive the rate is to changes in concentrations.
Understanding the total order can help predict how the reaction behaves under different concentrations, which is important for optimizing conditions to achieve desired outcomes in chemical processes. Higher-order reactions often show more complex behavior compared to simpler reactions, emphasizing the necessity of grasping each factor involved.

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Most popular questions from this chapter

Data for the reaction $$\mathrm{H}_{2} \mathrm{PO}_{4}^{-}(\mathrm{aq})+\mathrm{OH}^{-}(\mathrm{aq}) \longrightarrow \mathrm{HPO}_{4}^{2-}(\mathrm{aq})+\mathrm{H}_{2} \mathrm{O}(\ell)$$ are provided in the table. $$\begin{array}{llll}\hline & & & \text { Initial Rate } \\\\\text { Experiment } & {\left[\mathrm{H}_{2} \mathrm{PO}_{4}^{-}\right](\mathrm{M})} &{\left[\mathrm{OH}^{-}\right](\mathrm{M})} & (\mathrm{mol} / \mathrm{L} \cdot \mathrm{min}) \\\\\hline 1 & 0.0030 & 0.00040 & 0.0020 \\\2 & 0.0030 & 0.00080 & 0.0080 \\\3 & 0.0090 & 0.00040 & 0.0060 \\\4 & ? & 0.00033 & 0.0020 \\\\\hline\end{array}$$ (a) What is the rate law for this reaction? (b) What is the value of \(k ?\) (c) What is the concentration of \(\mathrm{H}_{2} \mathrm{PO}_{4}^{-}\) in experiment 4?

Describe each of the following statements as true or false. If false, rewrite the sentence to make it correct. (a) The rate-determining elementary step in a reaction is the slowest step in a mechanism. (b) It is possible to change the rate constant by changing the temperature. (c) As a reaction proceeds at constant temperature, the rate remains constant. (d) A reaction that is third order overall must involve more than one step.

The decomposition of \(\mathrm{SO}_{2} \mathrm{Cl}_{2}\) is a first-order reaction: $$\mathrm{SO}_{2} \mathrm{Cl}_{2}(\mathrm{g}) \longrightarrow \mathrm{SO}_{2}(\mathrm{g})+\mathrm{Cl}_{2}(\mathrm{g})$$ The rate constant for the reaction is \(2.8 \times 10^{-3} \mathrm{min}^{-1}\) at \(600 \mathrm{K} .\) If the initial concentration of \(\mathrm{SO}_{2} \mathrm{Cl}_{2}\) is \(1.24 \times 10^{-3}\) mol/L, how long will it take for the concentration to drop to \(0.31 \times 10^{-3} \mathrm{mol} / \mathrm{L} ?\)

At temperatures below \(500 \mathrm{K},\) the reaction between carbon monoxide and nitrogen dioxide $$ \mathrm{NO}_{2}(\mathrm{g})+\mathrm{CO}(\mathrm{g}) \longrightarrow \mathrm{CO}_{2}(\mathrm{g})+\mathrm{NO}(\mathrm{g}) $$ has the following rate equation: Rate \(=k\left[\mathrm{NO}_{2}\right]^{2} .\) Which of the three mechanisms suggested here best agrees with the experimentally observed rate equation? Mechanism 1 \(\quad\) single, elementary step $$\mathrm{NO}_{2}+\mathrm{CO} \longrightarrow \mathrm{CO}_{2}+\mathrm{NO}$$ Mechanism \(2 \quad\) Two steps $$\begin{aligned}&\text { Slow } \quad \mathrm{NO}_{2}+\mathrm{NO}_{2} \longrightarrow \mathrm{NO}_{3}+\mathrm{NO}\\\&\text { Fast } \quad \mathrm{NO}_{3}+\mathrm{CO} \longrightarrow \mathrm{NO}_{2}+\mathrm{CO}_{2}\end{aligned}$$ Mechanism 3 \(\quad\) Two steps $$\begin{aligned}&\text { Slow } \quad \mathrm{NO}_{2} \longrightarrow \mathrm{NO}+\mathrm{O}\\\&\text { Fast } \quad \mathrm{CO}+\mathrm{O} \longrightarrow \mathrm{CO}_{2}\end{aligned}$$

The reaction between ozone and nitrogen dioxide at \(231 \mathrm{K}\) is first order in both \(\left[\mathrm{NO}_{2}\right]\) and \(\left[\mathrm{O}_{3}\right]\) $$2 \mathrm{NO}_{2}(\mathrm{g})+\mathrm{O}_{3}(\mathrm{g}) \longrightarrow \mathrm{N}_{2} \mathrm{O}_{5}(\mathrm{s})+\mathrm{O}_{2}(\mathrm{g})$$ (a) Write the rate equation for the reaction. (b) If the concentration of \(\mathrm{NO}_{2}\) is tripled, what is the change in the reaction rate? (c) What is the effect on reaction rate if the concentration of \(\mathrm{O}_{3}\) is halved?

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