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Without doing any calculations, predict which compound in each pair releases more energy during combustion: a. 1 mole of \(\mathrm{CH}_{4}\) or 1 mole of \(\mathrm{H}_{2}\) b. \(1 \mathrm{g}\) of \(\mathrm{CH}_{4}\) or \(1 \mathrm{g}\) of \(\mathrm{H}_{2}\)

Short Answer

Expert verified
And which compound releases more energy when 1 gram of each is combusted? Answer: 1 mole of CHâ‚„ (methane) releases more energy during combustion compared to 1 mole of Hâ‚‚ (hydrogen). However, when considering 1 gram of each compound, 1 gram of Hâ‚‚ releases more energy than 1 gram of CHâ‚„.

Step by step solution

01

Analyze the combustion reaction for both compounds

In a combustion reaction, a compound reacts with oxygen to produce carbon dioxide and water as products. The general equation for the combustion of a hydrocarbon can be written as: $$\text{Hydrocarbon} + \text{O}_{2} \rightarrow \text{CO}_{2} + \text{H}_{2}\text{O}$$ For CHâ‚„, the balanced combustion reaction is: $$\text{CH}_{4} + 2\text{O}_{2} \rightarrow \text{CO}_{2} + 2\text{H}_{2}\text{O}$$ For Hâ‚‚, the balanced combustion reaction is: $$2\text{H}_{2} + \text{O}_{2} \rightarrow 2\text{H}_{2}\text{O}$$ Notice that for 1 mole of CHâ‚„ and 1 mole of Hâ‚‚, both reactions create the same number of moles of water.
02

Compare energy release for 1 mole of each compound

Since both reactions produce the same number of moles of water and the energy released is similar for each reaction, we can conclude that for 1 mole of each compound, CHâ‚„ will release more energy during combustion because it also forms 1 mole of COâ‚‚, which contributes to the total energy release. Hence, for part (a), 1 mole of CHâ‚„ releases more energy during combustion than 1 mole of Hâ‚‚.
03

Compare energy release for 1 gram of each compound

When comparing the energy released per gram of compound, it is useful to consider the molar masses of the compounds. The molar mass of CHâ‚„ is \(12.01 + 4(1.01) = 16.05 \, \text{g/mol}\), while the molar mass of Hâ‚‚ is \(2(1.01) = 2.02 \, \text{g/mol}\). Therefore, 1 gram of methane (CHâ‚„) is equal to approximately \(\frac{1}{16.05}\) mole, while 1 gram of hydrogen (Hâ‚‚) is equal to approximately \(\frac{1}{2.02}\) mole. Since there are more moles of Hâ‚‚ in 1 gram compared to CHâ‚„, this means that during the combustion of 1 gram, more energy will be released from Hâ‚‚ as there are more moles of Hâ‚‚ involved in the reaction. Hence, for part (b), 1 gram of Hâ‚‚ releases more energy during combustion than 1 gram of CHâ‚„.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Energy Release
In combustion reactions, the energy release is a critical factor to examine, as it determines how much heat and work can be generated from the reaction. A combustion reaction occurs when a fuel reacts with oxygen, producing carbon dioxide, water, and releasing energy in the form of heat. The amount of energy released during combustion is directly related to the complete breakdown of the molecular bonds present in the compound.

There are key points to consider in energy release during combustion:
  • The type of fuel: Different fuels release different amounts of energy due to their chemical structure.
  • The number of moles of product formed: More products usually indicate more bonds breaking, which can release more energy.
  • The type of products: For hydrocarbons, forming carbon dioxide and water releases significant energy.
When comparing 1 mole of methane (CHâ‚„) and 1 mole of hydrogen (Hâ‚‚), methane releases more energy in its combustion reaction due to the formation of both water and carbon dioxide, whereas hydrogen forms only water. This additional carbon dioxide formation in methane contributes to the greater energy release.
Moles and Molar Mass
Understanding moles and molar mass is fundamental in comparing energy release among different substances. A mole is a unit used to express the amount of a substance, and molar mass is the weight of that substance expressed in grams per mole.

To calculate molar mass, sum up the atomic masses of all atoms in a molecule:
  • For methane (CHâ‚„), its molar mass is calculated as follows: \( 12.01 + 4 \times 1.01 = 16.05 \, \text{g/mol} \).
  • For hydrogen (Hâ‚‚), it is \( 2 \times 1.01 = 2.02 \, \text{g/mol} \).
In energy-related problems, the concept of moles is crucial because the number of moles directly affects how much energy can be released. When the same weight of different substances is used – like 1 gram of CH₄ versus 1 gram of H₂ – the substance with a lower molar mass has more moles and, therefore, can potentially release more energy during combustion. In this case, hydrogen has more moles in 1 gram compared to methane, leading to a greater energy release.
Hydrocarbons
Hydrocarbons are organic compounds composed solely of carbon and hydrogen atoms. They serve as a primary source of fuel due to their high energy release upon combustion.

Hydrocarbons are categorized based on their structural characteristics and include:
  • Alkanes, which are saturated hydrocarbons, such as methane (CHâ‚„).
  • Alkenes and alkynes, which are unsaturated hydrocarbons with double or triple bonds.
In combustion, hydrocarbons react with oxygen to produce carbon dioxide and water, releasing a significant amount of energy. This reaction can be generally represented as:
\[ \text{Hydrocarbon} + \text{O}_2 \rightarrow \text{CO}_2 + \text{H}_2\text{O} \]
As seen in the comparison between CHâ‚„ and Hâ‚‚, methane serves as an excellent example of a hydrocarbon releasing more energy due to forming both water and carbon dioxide during its combustion. Hydrocarbons like methane are widely used for energy due to their efficiency and the substantial energy they release, making them valuable in various energy applications.

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Most popular questions from this chapter

The heavier (more dense) hydrocarbons in camp stove fuel are hexanes \(\left(\mathrm{C}_{6} \mathrm{H}_{14}\right)\). a. Calculate the fuel value of \(\mathrm{C}_{6} \mathrm{H}_{14},\) given that \(\Delta H_{\text {comb }}^{\circ}=\) \(-4163 \mathrm{kJ} / \mathrm{mol}\). b. How much heat is released during the combustion of \(1.00 \mathrm{kg}\) of \(\mathrm{C}_{6} \mathrm{H}_{14} ?\) c. How many grams of \(\mathrm{C}_{6} \mathrm{H}_{14}\) are needed to heat \(1.00 \mathrm{kg}\) of water from \(25.0^{\circ} \mathrm{C}\) to \(85.0^{\circ} \mathrm{C} ?\) Assume that all of the heat released during combustion is used to heat the water. d. Assume white gas is \(25 \% \mathrm{C}_{5}\) hydrocarbons (see Problem 9.109) and \(75 \%\) C \(_{6}\) hydrocarbons; how many grams of white gas are needed to heat \(1.00 \mathrm{kg}\) of water from \(25.0^{\circ} \mathrm{C}\) to \(85.0^{\circ} \mathrm{C} ?\)

In a high-temperature gas-phase reaction, methanol \(\left(\mathrm{CH}_{3} \mathrm{OH}\right)\) reacts with \(\mathrm{N}_{2}\) to produce \(\mathrm{HCN}\) and \(\mathrm{NH}_{3}\). The reaction is endothermic, requiring \(164 \mathrm{kJ}\) of thermal energy per mole of methanol under standard conditions. a. Write a balanced chemical equation for this reaction. b. Is energy a reactant or a product? c. What is the change in enthalpy under standard conditions if \(60.0 \mathrm{g}\) of \(\mathrm{CH}_{3} \mathrm{OH}(g)\) reacts with excess \(\mathrm{N}_{2}(g),\) forming \(\mathrm{HCN}(g),\) and \(\mathrm{NH}_{3}(g) ?\)

How much heat must be absorbed by \(100.0 \mathrm{g}\) of water to raise its temperature from \(30.0^{\circ} \mathrm{C}\) to \(100.0^{\circ} \mathrm{C} ?\)

Why is the heat of vaporization of water so much greater than its heat of fusion?

When measuring the heat of combustion of a very small amount of material, would you prefer to use a calorimeter having a heat capacity that is small or large?

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