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If fewer moles of \(\mathrm{A}\) are present in a reaction between \(\mathrm{A}\) and B, then \(A\) must be the limiting reagent. What is wrong with this statement?

Short Answer

Expert verified
Answer: No, it is not accurate. To determine the limiting reagent in a reaction between A and B, we must consider both the amounts of A and B (moles) and their stoichiometric coefficients from the balanced chemical equation. The reactant with the smallest mole ratio (moles of reactant divided by its respective stoichiometric coefficient) will be the limiting reagent.

Step by step solution

01

Understand limiting reagents

A limiting reagent is the reactant that limits the amount of product formed in a chemical reaction. It is the reactant that gets completely consumed first, preventing the reaction from proceeding further.
02

Analyze the statement

The statement claims that if fewer moles of reactant A are present in a reaction between A and B, then A must be the limiting reagent.
03

Explain the issue with the statement

The issue with this statement is that it ignores the stoichiometry of the reaction. The stoichiometric coefficients in a balanced chemical equation can help determine which reactant is the limiting reagent. It's important to consider both the amounts of reactants (moles) and their stoichiometric coefficients to accurately determine the limiting reagent. Simply having fewer moles of one reactant doesn't guarantee it is the limiting reagent.
04

Provide a corrected statement

A corrected statement should be: To determine the limiting reagent in a reaction between A and B, we must consider both the amounts of A and B (moles) and their stoichiometric coefficients from the balanced chemical equation. The reactant with the smallest mole ratio (moles of reactant divided by its respective stoichiometric coefficient) will be the limiting reagent.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Stoichiometry
In chemistry, stoichiometry plays a crucial role in understanding how substances interact in a chemical reaction. It involves calculating the quantities of reactants and products in a chemical reaction based on a balanced chemical equation. This concept ensures that the reactants combine in the exact proportions needed to form the desired products.

To determine the quantities involved, stoichiometry uses the coefficients from the balanced equation, which serve as a bridge between the number of moles of different substances. For example, in the reaction:
  • 3A + 4B → 2C
we understand that 3 moles of A react with 4 moles of B to produce 2 moles of C. This illustrates how stoichiometry allows us to predict the amount of product that can form from a certain amount of reactants, or conversely, how much of each reactant is needed to produce a desired amount of product.
Chemical Reaction
A chemical reaction represents a process in which substances, known as reactants, undergo a transformation to form new substances called products. The nature of a chemical reaction is governed by the principle of conservation of mass, meaning that the total mass of reactants is equal to the total mass of products.
  • The reactants are placed on the left side and the products on the right side of the equation.
  • An arrow (→) separates them, indicating the direction of the reaction.
Additionally, reactions can be categorized into different types such as synthesis, decomposition, single displacement, and double displacement based on how atoms and molecules rearrange. Understanding chemical reactions is fundamental in predicting the behavior of substances and their interactions, which is vital for fields like chemistry, biology, and environmental science.
Stoichiometric Coefficients
Stoichiometric coefficients are the numbers placed in front of the reactants and products in a balanced chemical equation. They indicate the ratio of moles needed or produced in the reaction. These coefficients are critical for accurately determining the proportions of substances participating in the reaction.

In the context of limiting reagents, stoichiometric coefficients help assess which reactant will run out first, effectively limiting the reaction. For example, if a reaction is represented by:
  • 2Hâ‚‚ + Oâ‚‚ → 2Hâ‚‚O
The coefficients (2 for Hâ‚‚ and 1 for Oâ‚‚) indicate that two moles of hydrogen gas react with one mole of oxygen gas to yield two moles of water. Thus, understanding and correctly applying stoichiometric coefficients is crucial to calculating the correct amounts of reactants and products, ensuring efficient resource use in experiments and industrial processes.

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Most popular questions from this chapter

How many moles of water vapor are produced for every mole of methane consumed in the combustion reaction \(\mathrm{CH}_{4}(g)+2 \mathrm{O}_{2}(g) \rightarrow \mathrm{CO}_{2}(g)+2 \mathrm{H}_{2} \mathrm{O}(g) ?\)

Baking soda (NaHCO \(_{3}\) ) is produced on an industrial scale by the Solvay process. A key reaction in the process is $$\mathrm{NaCl}(a q)+\mathrm{NH}_{3}(a q)+\mathrm{CO}_{2}(a q)+\mathrm{H}_{2} \mathrm{O}(\ell) \rightarrow$$ $$\quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \quad \mathrm{NaHCO}_{3}(s)+\mathrm{NH}_{4} \mathrm{Cl}(a q)$$ Suppose a reaction vessel initially contains \(58.5 \mathrm{kg} \mathrm{NaCl}\) \(18.8 \mathrm{kg} \mathrm{NH}_{3},\) and excess \(\mathrm{CO}_{2}\) and \(\mathrm{H}_{2} \mathrm{O} .\) If \(66 \mathrm{kg} \mathrm{NaHCO}_{3}\) is produced, what is the percent yield?

Some catalytic converters in automobiles contain two manganese oxides: \(\mathrm{Mn}_{2} \mathrm{O}_{3}\) and \(\mathrm{MnO}_{2}.\) a. What are the names of these compounds? b. What is the manganese content of each (expressed as a percent by mass)? c. Explain how \(\mathrm{Mn}_{2} \mathrm{O}_{3}\) and \(\mathrm{MnO}_{2}\) are consistent with the law of multiple proportions.

Combustion of 135.0 mg of a hydrocarbon produces \(440.0 \mathrm{mg} \mathrm{CO}_{2}\) and \(135.0 \mathrm{mg} \mathrm{H}_{2} \mathrm{O} .\) The molar mass of the hydrocarbon is \(270 \mathrm{g} / \mathrm{mol}\). What are the empirical and molecular formulas of this compound?

Marine Chemistry of Iron On the seafloor, solid iron(II) oxide may react with water to form solid \(\mathrm{Fe}_{3} \mathrm{O}_{4}\) and hydrogen gas. a. Write a balanced chemical equation for the reaction. b. When \(\mathrm{CO}_{2}\) is also present, the product of the reaction is methane, not hydrogen. Write a balanced chemical equation for this reaction.

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