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Write balanced equations describing the reaction of lithium metal with each of the following: \(\mathrm{O}_{2}, \mathrm{~S}, \mathrm{Cl}_{2}, \mathrm{P}_{4}, \mathrm{H}_{2}, \mathrm{H}_{2} \mathrm{O}\), and \(\mathrm{HCl}\).

Short Answer

Expert verified
The balanced equations for the reaction of lithium with various substances are as follows: 1. \(4 \mathrm{Li} + \mathrm{O}_{2} \rightarrow 2\mathrm{Li}_{2}\mathrm{O}\) 2. \(2\mathrm{Li} + \mathrm{S} \rightarrow \mathrm{Li}_{2}\mathrm{S}\) 3. \(2\mathrm{Li} + \mathrm{Cl}_{2} \rightarrow 2\mathrm{LiCl}\) 4. \(12 \mathrm{Li} + \mathrm{P}_{4} \rightarrow 4\mathrm{Li}_{3}\mathrm{P}\) 5. \(2 \mathrm{Li} + \mathrm{H}_{2} \rightarrow 2\mathrm{LiH}\) 6. \(2\mathrm{Li} + 2\mathrm{H}_{2}\mathrm{O} \rightarrow 2\mathrm{LiOH} + \mathrm{H}_{2}\) 7. \(2\mathrm{Li} + 2\mathrm{HCl} \rightarrow 2\mathrm{LiCl} + \mathrm{H}_{2}\)

Step by step solution

01

Reaction with Oâ‚‚ (oxygen gas)

Lithium (Li) reacts with Oâ‚‚ (oxygen gas) to form lithium oxide (Liâ‚‚O). In order to balance the equation, we need to have the same number of Li and O atoms on both sides. The balanced equation for this reaction is: \[4 \mathrm{Li} + \mathrm{O}_{2} \rightarrow 2\mathrm{Li}_{2}\mathrm{O}\]
02

Reaction with S (sulfur)

Lithium (Li) reacts with S (sulfur) to form lithium sulfide (Liâ‚‚S). In order to balance the equation, we need to have the same number of Li and S atoms on both sides. The balanced equation for this reaction is: \[2\mathrm{Li} + \mathrm{S} \rightarrow \mathrm{Li}_{2}\mathrm{S}\]
03

Reaction with Clâ‚‚ (chlorine gas)

Lithium (Li) reacts with Clâ‚‚ (chlorine gas) to form lithium chloride (LiCl). In order to balance the equation, we need to have the same number of Li and Cl atoms on both sides. The balanced equation for this reaction is: \[2\mathrm{Li} + \mathrm{Cl}_{2} \rightarrow 2\mathrm{LiCl}\]
04

Reaction with Pâ‚„ (phosphorus)

Lithium (Li) reacts with P₄ (phosphorus) to form lithium phosphide (Li₃P). In order to balance the equation, we need to have the same number of Li and P atoms on both sides. The balanced equation for this reaction is: \[12 \mathrm{Li} + \mathrm{P}_{4} \rightarrow 4\mathrm{Li}_{3}\mathrm{P}\]
05

Reaction with Hâ‚‚ (hydrogen gas)

Lithium (Li) reacts with Hâ‚‚ (hydrogen gas) to form lithium hydride (LiH). In order to balance the equation, we need to have the same number of Li and H atoms on both sides. The balanced equation for this reaction is: \[2 \mathrm{Li} + \mathrm{H}_{2} \rightarrow 2\mathrm{LiH}\]
06

Reaction with Hâ‚‚O (water)

Lithium (Li) reacts with Hâ‚‚O (water) to form lithium hydroxide (LiOH) and hydrogen gas (Hâ‚‚). In order to balance the equation, we need to have the same number of Li, O, and H atoms on both sides. The balanced equation for this reaction is: \[2\mathrm{Li} + 2\mathrm{H}_{2}\mathrm{O} \rightarrow 2\mathrm{LiOH} + \mathrm{H}_{2}\]
07

Reaction with HCl (hydrochloric acid)

Lithium (Li) reacts with HCl (hydrochloric acid) to form lithium chloride (LiCl) and hydrogen gas (Hâ‚‚). In order to balance the equation, we need to have the same number of Li, Cl, and H atoms on both sides. The balanced equation for this reaction is: \[2\mathrm{Li} + 2\mathrm{HCl} \rightarrow 2\mathrm{LiCl} + \mathrm{H}_{2}\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Balancing Equations
Balancing chemical equations is a fundamental skill in chemistry that ensures chemical equations accurately represent the law of conservation of mass. Each side of the equation must have the same number of atoms of each element.

To balance an equation, start by writing the unbalanced equation with the correct formulas for all reactants and products. Focus on balancing one element at a time, using coefficients to equalize the number of atoms for each element on both sides.
  • In the reaction of lithium (Li) with oxygen (Oâ‚‚) to form lithium oxide (Liâ‚‚O), the balanced equation is: \[4\mathrm{Li} + \mathrm{O}_{2} \rightarrow 2\mathrm{Li}_{2}\mathrm{O}\]. This ensures four lithium atoms and two oxygen atoms on each side.
  • Repeat this process for each reaction, ensuring the atom counts match up.
Balancing equations may require trial and error, but with practice, identifying common patterns and using simple strategies, like starting with molecules that appear in multiple compounds, can make the process easier.
Lithium Reactions
Lithium, the lightest metal and one of the alkali metals, reacts readily with various substances. Its reactions are unique because lithium often forms simple ionic compounds where it exists as a positive ion, \(\mathrm{Li}^+\).

When lithium reacts with oxygen, it forms lithium oxide (Liâ‚‚O), producing an ionic bond between lithium and oxygen. Lithium also reacts with other non-metals, such as sulfur and chlorine:
  • With sulfur, lithium forms lithium sulfide (\(\mathrm{Li}_2\mathrm{S}\)), a compound where lithium donates electrons to sulfur.
  • With chlorine, lithium forms lithium chloride (\(\mathrm{LiCl}\)), which is a white solid at room temperature.
These reactions demonstrate lithium's propensity to lose one electron, achieving the stable configuration of helium.
Stoichiometry
Stoichiometry involves calculating the quantities of reactants and products in a chemical reaction. It's based on the balanced chemical equation and the principle that matter is conserved, thus ensuring that the mass of reactants equals the mass of products.

A balanced chemical equation is a tool that allows you to understand the proportional relationships between reactants and products. For instance, in the reaction of lithium with hydrogen gas to form lithium hydride (LiH):
  • The balanced equation \( 2 \mathrm{Li} + \mathrm{H}_2 \rightarrow 2 \mathrm{LiH} \) tells you that two atoms of lithium will produce two formula units of lithium hydride for every molecule of hydrogen gas used.
  • By using stoichiometric coefficients, one can calculate how much lithium or hydrogen is needed to produce a certain amount of lithium hydride.
Understanding stoichiometry ensures that reactions are carried out efficiently, with minimal waste of resources.
Oxidation-Reduction Reactions
Oxidation-reduction (redox) reactions are chemical reactions where electrons are transferred between atoms. This process involves the oxidation of one element (losing electrons) and the reduction of another (gaining electrons).

In many lithium reactions, lithium is oxidized while the other element is reduced. For example:
  • When lithium reacts with oxygen, lithium loses electrons (oxidation) to form \(\mathrm{Li}^+\) ions, and oxygen gains those electrons (reduction) to form oxide ions (\(\mathrm{O}^{2-}\)).
  • This electron transfer gives lithium oxide its structure and charge balance.
Oxidation numbers help track electron transfer: lithium starts at 0 and becomes +1 after losing an electron, while oxygen moves from 0 to -2 after gaining electrons.

Understanding redox reactions is vital because these reactions are foundational to processes like metabolism, combustion, and corrosion, and are widely applied in industries like battery manufacturing.

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Most popular questions from this chapter

Thallium and indium form \(+1\) and \(+3\) oxidation states when in compounds. Predict the formulas of the possible compounds between thallium and oxygen and between indium and chlorine. Name the compounds.

List two major industrial uses of hydrogen.

Write the Lewis structure for \(\mathrm{O}_{2} \mathrm{~F}_{2}\). Predict the bond angles and hybridization of the two central oxygen atoms. Assign oxidation states and formal charges to the atoms in \(\mathrm{O}_{2} \mathrm{~F}_{2}\). The compound \(\mathrm{O}_{2} \mathrm{~F}_{2}\) is a vigorous and potent oxidizing and fluorinating agent. Are oxidation states or formal charges more useful in accounting for these properties of \(\mathrm{O}_{2} \mathrm{~F}_{2}\) ?

What is a disproportionation reaction? Use the following reduction potentials $$ \begin{aligned} \mathrm{ClO}_{3}^{-} &+3 \mathrm{H}^{+}+2 \mathrm{e}^{-} \longrightarrow \mathrm{HClO}_{2}+\mathrm{H}_{2} \mathrm{O} & & \mathscr{E}^{\circ}=1.21 \mathrm{~V} \\ \mathrm{HClO}_{2}+2 \mathrm{H}^{+}+2 \mathrm{e}^{-} \longrightarrow \mathrm{HClO}+\mathrm{H}_{2} \mathrm{O} & & \mathscr{E}^{\circ}=1.65 \mathrm{~V} \end{aligned} $$ to predict whether \(\mathrm{HClO}_{2}\) will disproportionate.

Captain Kirk has set a trap for the Klingons who are threatening an innocent planet. He has sent small groups of fighter rockets to sites that are invisible to Klingon radar and put a decoy in the open. He calls this the "fishhook" strategy. Mr. Spock has sent a coded message to the chemists on the fighters to tell the ships what to do next. The outline of the message is Fill in the blanks of the message using the following clues. (1) Symbol of the halogen whose hydride has the second highest boiling point in the series of HX compounds that are hydrogen halides. (2) Symbol of the halogen that is the only hydrogen halide, \(\mathrm{HX}\), that is a weak acid in aqueous solution. (3) Symbol of the element whose existence on the sun was known before its existence on earth was discovered. (4) The Group \(5 \mathrm{~A}\) element in Table \(20.13\) that should have the most metallic character. (5) Symbol of the Group \(6 \mathrm{~A}\) element that, like selenium, is a semiconductor. (6) Symbol for the element known in rhombic and monoclinic forms. (7) Symbol for the element that exists as diatomic molecules in a yellow-green gas when not combined with another element. (8) Symbol for the most abundant element in and near the earth's crust. (9) Symbol for the element that seems to give some protection against cancer when a diet rich in this element is consumed. (10) Symbol for the smallest noble gas that forms compounds with fluorine having the general formula \(\mathrm{AF}_{2}\) and \(\mathrm{AF}_{4}\) (reverse the symbol and split the letters as shown). (11) Symbol for the toxic element that, like phosphorus and antimony, forms tetrameric molecules when uncombined with other elements (split the letters of the symbol as shown). (12) Symbol for the element that occurs as an inert component of air but is a very prominent part of fertilizers and explosives.

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