/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 66 A mixture of gases contains \(0.... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A mixture of gases contains \(0.31 \mathrm{~mol} \mathrm{CH}_{4}, 0.25 \mathrm{~mol}\) \(\mathrm{C}_{2} \mathrm{H}_{6}\), and \(0.29 \mathrm{~mol} \mathrm{C}_{3} \mathrm{H}_{8}\). The total pressure is \(1.50 \mathrm{~atm} .\) Calculate the partial pressures of the gases.

Short Answer

Expert verified
The partial pressures are: \(\mathrm{CH}_4\) is 0.547 atm, \(\mathrm{C}_2\mathrm{H}_6\) is 0.441 atm, and \(\mathrm{C}_3\mathrm{H}_8\) is 0.511 atm.

Step by step solution

01

Calculate Total Moles of Gas

First, we need to determine the total number of moles in the gas mixture. Add the moles of each gas together to get the total n (in moles):\[n = 0.31 + 0.25 + 0.29 = 0.85 \text{ mol}\]
02

Determine Mole Fraction

Next, we calculate each gas's mole fraction \(X_i\). For each gas \(i\), use the formula:\[X_i = \frac{\text{moles of } i}{n}\]E.g., for \(\mathrm{CH}_4\):\[X_{\mathrm{CH}_4} = \frac{0.31}{0.85} \approx 0.3647\]Repeat for \(\mathrm{C}_2\mathrm{H}_6\) and \(\mathrm{C}_3\mathrm{H}_8\).
03

Calculate Partial Pressures

Now use the mole fraction and total pressure to find each gas's partial pressure \(P_i\) using:\[P_i = X_i \cdot P_{\text{total}}\]For \(\mathrm{CH}_4\):\[P_{\mathrm{CH}_4} = 0.3647 \times 1.50 = 0.547 \text{ atm}\]Repeat this for \(\mathrm{C}_2\mathrm{H}_6\) and \(\mathrm{C}_3\mathrm{H}_8\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gas Mixture
A gas mixture consists of two or more gases blended together without any specific chemical reactions occurring between them. In this concept, understanding how different gases combine and share a container is essential for calculating properties like pressure and volume.

In our example, the mixture is composed of methane (\(\mathrm{CH}_4\)), ethane (\(\mathrm{C}_2\mathrm{H}_6\)), and propane (\(\mathrm{C}_3\mathrm{H}_8\)). Each gas contributes to the overall properties of the mixture. The total behavior of the mixture is affected by:
  • The number of moles of each gas present
  • The temperature and pressure of the mixture
  • The interactions between the different gas molecules
A crucial aspect is calculating the contribution of each gas to the overall mixture, which is directly related to its mole fraction in the gas mixture.
Mole Fraction
Mole fraction is a way to express the concentration of a component in a mixture. It is defined as the ratio of the moles of a particular component to the total moles in the mixture. This method of expression is particularly useful when dealing with gas mixtures because it allows us to easily calculate each gas's influence on the total pressure.

The formula used to calculate the mole fraction \(X_i\) of a particular gas \(i\) in a mixture is:
  • \(X_i = \frac{\text{moles of } i}{\text{total moles}}\)
For instance, in our problem, methane has a mole fraction calculated as \(X_{\mathrm{CH}_4} = \frac{0.31}{0.85}\). This tells us how much of the total mixture is comprised of methane, and similarly, this can be done for ethane and propane. Knowing each gas's mole fraction, we can determine each gas's contribution to pressure, utilizing Dalton's Law.
Dalton's Law of Partial Pressures
Dalton's Law of Partial Pressures is a critical principle in gas mixture calculations. It states that the total pressure exerted by a gas mixture is the sum of the partial pressures of each individual gas within the mix. Each gas's partial pressure is its mole fraction times the total pressure of the gas mixture.

This can be mathematically represented as:
  • \(P_i = X_i \cdot P_{\text{total}}\)
where \(P_i\) is the partial pressure of gas \(i\), \(X_i\) is its mole fraction, and \(P_{\text{total}}\) is the overall pressure of the gas mixture. For example, the partial pressure of methane in our problem is \(0.547 \text{ atm}\). Knowing how each gas's partial pressure contributes to the total gives us insights into the behavior of the whole mixture and is crucial when analyzing or designing systems where gas mixtures are involved, like chemical reactions or industrial applications.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Venus's atmosphere is composed of 96.5 percent \(\mathrm{CO}_{2}\), 3.5 percent \(\mathrm{N}_{2}\), and 0.015 percent \(\mathrm{SO}_{2}\) by volume. Its standard atmospheric pressure is \(9.0 \times 10^{6} \mathrm{~Pa}\). Calculate the partial pressures of the gases in pascals.

Sodium bicarbonate \(\left(\mathrm{NaHCO}_{3}\right)\) is called baking soda because, when heated, it releases carbon dioxide gas, which is responsible for the rising of cookies, some doughnuts, and cakes. (a) Calculate the volume (in liters) of \(\mathrm{CO}_{2}\) produced by heating \(5.0 \mathrm{~g}\) of \(\mathrm{NaHCO}_{3}\) at \(180^{\circ} \mathrm{C}\) and 1.3 atm. (b) Ammonium bicarbonate \(\left(\mathrm{NH}_{4} \mathrm{HCO}_{3}\right)\) has also been used for the same purpose. Suggest one advantage and one disadvantage of using \(\mathrm{NH}_{4} \mathrm{HCO}_{3}\) instead of \(\mathrm{NaHCO}_{3}\) for baking.

The following procedure is a simple though somewhat crude way to measure the molar mass of a gas. A liquid of mass \(0.0184 \mathrm{~g}\) is introduced into a syringe like the one shown here by injection through the rubber tip using a hypodermic needle. The syringe is then transferred to a temperature bath heated to \(45^{\circ} \mathrm{C},\) and the liquid vaporizes. The final volume of the vapor (measured by the outward movement of the plunger) is \(5.58 \mathrm{~mL},\) and the atmospheric pressure is \(760 \mathrm{mmHg}\). Given that the compound's empirical formula is \(\mathrm{CH}_{2}\), determine the molar mass of the compound.

In the metallurgical process of refining nickel, the metal is first combined with carbon monoxide to form tetracarbonylnickel, which is a gas at \(43^{\circ} \mathrm{C}:\) $$ \mathrm{Ni}(s)+4 \mathrm{CO}(g) \longrightarrow \mathrm{Ni}(\mathrm{CO})_{4}(g) $$ This reaction separates nickel from other solid impurities. (a) Starting with \(86.4 \mathrm{~g}\) of \(\mathrm{Ni}\), calculate the pressure of \(\mathrm{Ni}(\mathrm{CO})_{4}\) in a container of volume \(4.00 \mathrm{~L}\). (Assume the preceding reaction goes to completion.) (b) At temperatures above \(43^{\circ} \mathrm{C},\) the pressure of the gas is observed to increase much more rapidly than predicted by the ideal gas equation. Explain.

An unknown gas evolved from the fermentation of glucose is found to effuse through a porous barrier in 15.0 min. Under the same conditions of temperature and pressure, it takes an equal volume of \(\mathrm{N}_{2} 12.0 \mathrm{~min}\) to effuse through the same barrier. Calculate the molar mass of the unknown gas, and suggest what the gas might be.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.