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Chapter 9: Q. 9.103 (page 318)

How many liters of a $2.50 {MKNO}_{3}$ solution can be prepared from $60.0 g$ of ${KNO}_{3}$ ?

Short Answer

Expert verified

$0.237 L$ of a $2.50 {MKNO}_{3}$ solution can be prepared from $60.0 g$ of ${KNO}_{3}$ .

Step by step solution

01

Given information

To calculate the how much liters of a $2.50 {MKNO}_{3}$ solution can be prepared from $60.0 g$ of ${KNO}_{3}$ .

02

To calculate the moles of KNO3 by using the following expression

Moles of ${KNO}_{3} = \frac{mass of {KNO}_{3}}{molar mass of {KNO}_{3}}$

$= \frac{60 g}{101.1 g / mol}$

$= 0.593 mol$ .

03

To calculate the volume required by using the following expression :

Volume of ${KNO}_{3} = \frac{Moles of {KNO}_{3}}{Molarity of {KNO}_{3}}$

$= \frac{0.593 mol}{2.50 M}$

$= 0.237 L$

Therefore, the required volume of ${KNO}_{3}$ solution is $0.237 L$ .

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Most popular questions from this chapter

How many grams of solute are in each of the following solutions?

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Calculate the mass percent $(m / m)$ for the solute in each of the following:

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