91Ó°ÊÓ

The melting point of dibromomethane =$-{53}^{o}C$

The boiling point of dibromomethane =${97}^{o}C$

Dibromomethane stays in solid structure till $-{53}^{o}C$and starts to melt from this point onwards as it is the melting point.

Hence, dibromomethane is in solid-state at$−{75}^{∘}\mathrm{C}$.

The melting point of dibromomethane =$−{53}^{∘}\mathrm{C}$

The boiling point of dibromomethane =${97}^{o}C$

At $−{53}^{∘}\mathrm{C}$both the solid-state and liquid state co-exist as this is the melting point.

The melting point of dibromomethane =$−{53}^{∘}\mathrm{C}$

The boiling point of dibromomethane =${97}^{o}C$

dibromomethane remains in the liquid state from $−{53}^{∘}\mathrm{C}\text{to}{97}^{∘}\mathrm{C}$.

Hence it will be in a liquid state at$−{18}^{∘}\mathrm{C}$

The melting point of dibromomethane =$−{53}^{∘}\mathrm{C}$

The boiling point of dibromomethane = ${97}^{o}C$

dibromomethane is in a gaseous state at ${97}^{o}C$as it is the boiling point.

hence it will be in a gaseous state at${110}^{o}C$.

The melting point of dibromomethane =$-{53}^{o}C$

The boiling point of dibromomethane =${97}^{o}C$

At $-{53}^{o}C$it will be in both solid and liquid states as this is the melting point. At the melting point, both the liquid and solid-state are present.

The graph is,