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Chapter 10: Q.10.87 (page 359)

Determine the pH for the following solutions:
a. $[H_{3} O^{+}] = 1.0 脳 10^{鈭� 11} M$
b. $[H_{3} O^{+}] = 5.0 脳 10^{鈭� 2} M$
c. $[{OH}^{鈭�}] = 3.5 脳 10^{鈭� 4} M$
d. $[{OH}^{鈭�}] = 0.005 M$

Short Answer

Expert verified

Part a. $11$

Part b. $1.3$

Part c. $10.5$

Part d. $11.7$

Step by step solution

01

Given Information (Part a)

The representation of a chemical reaction in the type of substance is known as a chemical equation. The equation in which the quantity of particles of the multitude of atoms is equivalent on the two sides of the equation is known as a fair chemical equation.

02

Explanation Part (a)

We know,

$[H_{3} O^{+}] = 1.0 脳 10^{鈭� 11} M$

Using,

$pH = 鈭� \log 鈦� [H_{3} O^{+}]$

$pH = 鈭� \log 鈦� (1.0 脳 10^{鈭� 11}) = 11$

03

Explanation Part (b)

We know,

$[H_{3} O^{+}] = 5.0 脳 10^{鈭� 2} M$

Using,

$\begin{aligned} pH = 鈭� \log 鈦� [H_{3} O^{+}] \end{aligned}$

$pH = 鈭� \log 鈦� (5.0 脳 10^{鈭� 2}) = 1.30$

04

Explanation Part (c)

We know,

$[{OH}^{鈭�}] = 3.5 脳 10^{鈭� 4} M$

Calculating $H_{3} O^{+}$ ,

role="math" localid="1653141748429" $[H_{3} O^{+}] = \frac{1 脳 10^{鈭� 14}}{[{OH}^{鈭�}]} = \frac{1 脳 10^{鈭� 14}}{3.5 脳 10^{- 4}} = 2.85 脳 10^{- 11}$

Using,

$pH = 鈭� \log 鈦� [H_{3} O^{+}] p H = 鈭� \log 鈦� (2.85 脳 10^{- 11}) p H = 10.5$

05

Explanation Part (d)

We know,

$[{OH}^{鈭�}] = 0.005 M$

Calculating $H_{3} O^{+}$

$[H_{3} O^{+}] = \frac{1 脳 10^{鈭� 14}}{[{OH}^{鈭�}]} = \frac{1 脳 10^{鈭� 14}}{0.005} = 2 脳 10^{- 12}$

Using,

$pH = 鈭� \log 鈦� [H_{3} O^{+}]$

$pH = 鈭� \log 鈦� (2.0 脳 10^{鈭� 12}) p H = 11.7$

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Most popular questions from this chapter

In the blood plasma. pH is maintained by the carbonic acid bicarbonate buffer system, $(10, 8)$

a. How is pH maintained when acid is added to the buffer system?

b. How is pH maintained when base is added to the buffer system?

If you know the $[{OH}^{-}]$ , how can you determine the pH of a solution?

Complete and balance the equation for each of the following reactions:

a. ${ZnCO}_{3} (s) + HBr (a q) 鉄�$

b. $Zn (s) + HCl (a q) 鉄�$

c. $HCl (a q) + {NaHCO}_{3} (s) 鉄�$

d. $H_{2} {SO}_{4} (a q) + Mg (OH)_{2} (s) 鉄�$

At rest, the $[H_{3} O^{+}]$ of the stomach fluid is $2.0 脳 10^{- 4} M$ . What is the $pH$ of the stomach fluid?

Calculate the pH of each solution given the follow in:

a. $|H_{2} O^{+}| = 1 脳 10^{4} M$

b. $|H, O^{+}| = 3 脳 10^{- 9} M$

c. $[OH] = 1 脳 10^{- 9} M$

d. $鈱� OH 鈱� = 2.5 脳 10^{- 11} M$

e. $|H, O^{'}| = 6.7 脳 10^{- 1} M$

f. $[{OH}^{-}] = 8.2 脳 10^{- 4} M$

See all solutions

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