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Chapter 10: Q. 10.38 (page 346)

If you know the $[{OH}^{-}]$ , how can you determine the pH of a solution?

Short Answer

Expert verified

The pH of a solution is determined as $p H = - \log [H_{3} O^{+}]$

Step by step solution

01

Introduction

The objective is to determine the pH of a solution when $[{OH}^{-}]$ is known.

02

Explanation

We'll start by calculating the $H_{3} O^{+}$ using $K_{蝇}$ (Ionic product) for water i.e localid="1653974998099" $K_{蝇} = [H_{3}^{+} O] 脳 [{OH}^{-}]$ and $[H_{3} O^{+}] = \frac{K_{蝇}}{[{OH}^{-}]} = \frac{1.0 脳 10^{- 14}}{[{OH}^{-}]}$

Then enter the calculate value $[H_{3} O^{+}]$ far computation based on formula $pH$ , which is

localid="1653975011962" $pH = - \log [H_{3} O^{+}]$

As a result, pH can be determined

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Most popular questions from this chapter

If a base is added to pure water, why does the $H_{3} O^{+}$ decrease?

What is the molarity of a solution of HCL if 5ml of the HCL solution is titrated with 28.6ml of a 0.145 M NaOH solution?

$HCl (a q) + NaOH (a q) 鉄� H_{2} O (l) + NaCl (a q)$

A buffer solution is made by dissolving ${HC}_{2} H_{3} O_{2} and {NaC}_{2} H_{3} O_{2}$ in water.

a. Write an equation that shows how this buffer neutralizes added acid.

b. Write an equation that shows how this buffer neutralizes added base.

10.25 Why are the concentrations of $H_{3} O^{+}$ and ${OH}^{-}$ equal in pure water?

Determine the pH for the follow ing solutions: $(10, 6)$

a. $[OH] = 1.0 脳 10^{- 7} M$

b. $[H_{2} O^{'}] = 4.2 脳 10^{- 3} M$

c. $[H_{2} O^{+}] = 0.0001 M$

d. $[OH] = 8.5 脳 10^{- 9} M$

See all solutions

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