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Chapter 1: Q14P (page 21)

Calculate the equilibrium constant for the reaction. Glucose-1-phosphate+H2O gives Glucose+ H2PO4- at pH 7 and 25oC.

Short Answer

Expert verified

Glucose-1-phosphate on hydrolysis yields Glucose and Phosphate at pH 7 is K=4.627脳103.

Step by step solution

01

Given data

Glucose-1-phosphate on hydrolysis yields Glucose and Phosphate.

螖G0=-20.9kg/molT=25掳C=298KR=8.31J/molK

02

Formula and calculation for equilibrium constant

螖G0=-RTlnK

-20.9脳103=-8.31脳298lnKlnK=8.439K=e8.439=4.627脳103

03

Conclusion

Therefore, the equilibrium constant for the reaction Glucose-1-phosphate on hydrolysis yields Glucose and Phosphate at pH 7 is K=4.627脳103.

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