Q21P The equilibrium constant for the... [FREE SOLUTION]

Chapter 1: Q21P (page 22)

The equilibrium constant for the reaction $Q 鈫� R$ is 25.
If $50 渭 M$ of Q is mixed with $50 渭 M$ of R, which way will the reaction proceed to generate more Q or more R?
Calculate the equilibrium concentrations of Q and R.

Short Answer

Expert verified

In the solution (a), equal concentration of $[Q]$ and $[R]$ is mixed, the reaction will proceed to produce more R molecules.

In the solution (b), the equilibrium concentration of $[Q] = 3.85渭M$ and $[R] = 96.15渭M$ .

Step by step solution

Given data

$\begin{array}{l} [Q] = 3.85 渭 M \\ [鈩�] = 96.15 渭 M \end{array}$

$K_{eq}$ for the given reaction $Q 鈫� R$ is 25.

Then,

$K_{e q} = \frac{[R]}{[Q]} = 25$

In solution (a), the reaction will proceed to generate more R.

$K_{e q} = \frac{[R]}{[Q]} = 25$

Therefore,

$[R] = 25$ times of $[Q]$

At equilibrium, R molecules are 25 times more than the Q molecules.

However, when equal concentration of $[Q]$ and $[R]$ are mixed, the reaction will proceed forward and more Q molecules are converted to R molecules.

In solution (b), calculation of equilibrium concentration of Q and R.

Let us assume that the amount of Q converted to R is x.

Then,

$\begin{array}{rcl} [R] = 50 + x \\ [Q] = 50 - x \\ Calculating the value of x, \\ K_{eq} = \frac{[R]}{[Q]} \\ 25 = \frac{50 + x}{50 - x} \\ 50 + x = 25 (50 - x) \\ x = 46.15 \end{array}$

Now, calculating equilibrium constants,

$[Q] = 50 - 46.15 = 3.85渭M$

Similarly,

$[R] = 50 + 46.15 = 96.15渭M$

Hence, the equilibrium constant of [Q] is 3.85碌M and [R] is 96.15 碌M.

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The equilibrium constant for the reaction $Q 鈫� R$ is 25.
If $50 渭 M$ of Q is mixed with $50 渭 M$ of R, which way will the reaction proceed to generate more Q or more R?
Calculate the equilibrium concentrations of Q and R.

Short Answer

Step by step solution

Given data

In solution (a), the reaction will proceed to generate more R.

In solution (b), calculation of equilibrium concentration of Q and R.

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91影视

The equilibrium constant for the reaction Q鈫�Ris 25.If 50渭Mof Q is mixed with 50渭Mof R, which way will the reaction proceed to generate more Q or more R?Calculate the equilibrium concentrations of Q and R.

Short Answer

Step by step solution

Given data

In solution (a), the reaction will proceed to generate more R.

In solution (b), calculation of equilibrium concentration of Q and R.

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Biology Textbooks

Cell Communication

Energy Transfers

Communicable Diseases

Cells

Ecology

Organ Systems

Study anywhere. Anytime. Across all devices.

The equilibrium constant for the reaction $Q 鈫� R$ is 25.
If $50 渭 M$ of Q is mixed with $50 渭 M$ of R, which way will the reaction proceed to generate more Q or more R?
Calculate the equilibrium concentrations of Q and R.