Chapter 15: Q7. (page 497)
Why is triose phosphate isomerase considered to be catalytically perfect?
Short Answer
Triose phosphate isomerase is considered catalytically perfect because of its kcat/Km value which is in the diffusion-limit range.
/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none}
Learning Materials
Features
Discover
Chapter 15: Q7. (page 497)
Why is triose phosphate isomerase considered to be catalytically perfect?
Triose phosphate isomerase is considered catalytically perfect because of its kcat/Km value which is in the diffusion-limit range.
All the tools & learning materials you need for study success - in one app.
Get started for free
What is the advantage of activating pyruvate kinase with fructose-1, 6-bisphosphate?
Bacterial aldolase does not form a Schiff base with the substrate. Instead, it has a divalent Zn2+ion in the active site. How does the ionfacilitate the aldolase reaction?
Identify the intermediate in the phosphoglucomutase reaction.
Nerve cells require a source of free energy to transport vesicles containing neurotransmitters along the length of the axon, where mitochondria are scarce. Explain why it makes sense that glyceraldehyde3-phosphate dehydrogenase is located on the surface of some transport vesicles.
Compare the ATP yield of three glucose molecules that enter glycolysis and are converted to pyruvate with that of three glucose molecules that proceed through the pentose phosphate pathway such that their carbon skeletons (as two F6P and one GAP) re-enter glycolysis and are metabolized to pyruvate.
What do you think about this solution?
We value your feedback to improve our textbook solutions.