/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q15.5-1CC Gene dosage鈥攖he number of copi... [FREE SOLUTION] | 91影视

91影视

Gene dosage鈥攖he number of copies of a gene that are actively being expressed鈥攊s important to proper development. Identify and describe two processes that establish the proper dosage of certain genes.

Short Answer

Expert verified

The two processes that establish the proper dosage of certain genes are inactivation of an X chromosome in females and genomic imprinting. The dosage of a gene is particularly dealt with the copies of the gene present in the entire genome.

Step by step solution

01

Description of gene expression

Genes are basic hereditary segments present in the DNA. The proper expression of the genome is necessary for the effective functioning of the body's metabolism. Genes are converted into protein, for which proper loading of gene dosage is necessary.

02

Description of gene dosage

The quantity of gene products expressed by the cell is known as gene dosage. It can change due to the insertions or deletions in the entire genome, leading to copy number variations.

The variation in the number of copies of a gene happens in different organisms. The drastic change in gene dosage is the basis for certain types of disease.

03

Processes responsible for the establishment of gene dosage

X chromosomes inactivation and genome imprinting are the processes responsible for establishing gene dosage. The X chromosome is the same in males and females, but it is maintained in males due to the X chromosome inactivation.

X chromosomes present in the cells other than egg cells are inactivated randomly or permanently.

Genomic imprinting determines the gene's ability that is passed from the parents to the offspring. Usually, the inheritance of the gene happens from the mother. With the help of genomic imprinting, one allele gets expressed phenotypically.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Using the information from problem 4, scientists do a further testcross using a heterozygote for height and nose morphology. The offspring are tall upturned snout, 40; dwarf upturned snout, 9; dwarf downturned snout, 42; tall downturned snout, 9. Calculate the recombination frequency from these data, and then use your answer from problem 4 to determine the correct order of the three linked genes.

Neither Tim nor Rhoda had Duchenne muscular dystrophy, but their firstborn son does. What is the probability that a second child will have the disease? What is the probability if the second child is a boy? A girl?

A planet is inhabited by creatures that reproduce with the same hereditary patterns seen in humans. Three phenotypic characters are height (T = tall, t= dwarf), head appendages (A = antennae, a = no antennae), and nose morphology (S = upturned snout, s = downturned snout). Since the creatures are not 鈥渋ntelligent,鈥 Earth scientists are able to do some controlled breeding experiments using various heterozygotes in testcrosses. For tall heterozygotes with antennae, the offspring are tall antennae, 46; dwarf antennae, 7; dwarf no antennae, 42; tall no antennae, 5. For heterozygotes with antennae and an upturned snout, the offspring are antennae upturned snout 47; antennae downturned snout, 2; no antennae downturned snout, 48; no antennae upturned snout, 3. Calculate the recombination frequencies for both experiments.

Assume you are mapping genes A, B, C, and D in Drosophila. You know that these genes are linked on the same chromosome, and you determine the recombination frequencies between each pair of genes to be as follows: A-B, 8%; A-C, 28%; A-D, 25%; B-C, 20%; B-D, 33%.

  1. Describe how you determined the recombination frequency for each pair of genes.

  2. Draw a chromosome map based on your data.

Two genes of a flower, one controlling blue (B) versus white (b) petals and the other controlling round (R) versus oval (r) stamens, are linked and are 10 map units apart. You cross a homozygous blue oval plant with a homozygous white round plant. The resulting F1 progeny are crossed with homozygous white oval plants, and 1,000 offspring plants are obtained. How many plants of each of the four phenotypes do you expect?

See all solutions

Recommended explanations on Biology Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.