Chapter 6: Problem 20
A set of scores measuring aggression is normally distributed with a mean equal to 23 and a standard deviation equal to \(2.5\). Find the proportion: a. To the left of \(x=19.0\) b. To the right of \(x=25.5\) c. Between the mean and \(x=19.0\) d. To the left of \(x=25.5\) e. To the right of \(x=19.0\)
Short Answer
Step by step solution
Identify the Given Parameters
Convert to z-scores
Find the Proportion to the Left of x = 19.0
Find the Proportion to the Right of x = 25.5
Find the Proportion Between the Mean and x = 19.0
Find the Proportion to the Left of x = 25.5
Find the Proportion to the Right of x = 19.0
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Z-Scores
- \( z = \frac{x - \mu}{\sigma} \)
Z-scores are particularly useful in the context of a normal distribution as they allow us to calculate the probability of a score occurring within our normal distribution. This conversion helps us understand the proportion of data lying beneath or beyond a certain score. For example, by calculating the z-score for a point, we can use z-tables or technology to determine the percentage of data lying to the left or right of that point.
Cumulative Probability
- For instance, if you find a z-score of -1.6, the cumulative probability (or area under the curve) to the left of this z-score is approximately 0.0548.
- This tells us that about 5.48% of the data falls to the left of this point.
In a symmetric normal distribution, the mean divides the data into two equal parts, resulting in a cumulative probability of 0.5.
Standard Deviation
- In our exercise, the standard deviation is 2.5, which informs us about the average distance of each score from the mean of 23.
- This information is crucial when converting a raw score to a z-score, as it normalizes the data.
It also plays a key role in determining probabilities, especially when calculating z-scores, as it provides the scale relative to the mean for adjustments.
Mean
- For the normal distribution in our exercise, the mean is given as 23.
- This serves as a benchmark for calculating z-scores and understanding the distribution.