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A researcher tested whether time of dyy could predict mood in a sample of 14 college students. If \(S S_{\text {residual }}=108\), then what is the standard error of estimate in this sample?

Short Answer

Expert verified
The standard error of estimate is 3.

Step by step solution

01

Understand the formula for Standard Error of Estimate

The standard error of estimate formula is used to measure the accuracy of predictions in a regression analysis. The formula is given by \( SE = \sqrt{\frac{SS_{\text{residual}}}{n-2}} \), where \( n \) is the number of observations, and \( SS_{\text{residual}} \) is the sum of squares of the residuals.
02

Identify the given values

In the exercise, you are given that \( SS_{\text{residual}} = 108 \) and the sample size \( n = 14 \). These values will be used in the formula to calculate the standard error of estimate.
03

Calculate the degrees of freedom

Before using the formula, compute the degrees of freedom (\( n - 2 \)). For this sample, \( n = 14 \), so \( n - 2 = 14 - 2 = 12 \).
04

Substitute the values into the formula

Substitute \( SS_{\text{residual}} = 108 \) and the degrees of freedom \( n - 2 = 12 \) into the formula: \[ SE = \sqrt{\frac{108}{12}} \]
05

Calculate the result

Complete the arithmetic to find the standard error: \( SE = \sqrt{9} = 3 \). Therefore, the standard error of estimate for the sample is 3.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Regression Analysis
Regression analysis is a powerful statistical method used to examine the relationship between two or more variables. It allows us to predict the value of one variable, known as the dependent variable or response, based on the value of one or more independent variables, which are the predictors. In the simplest form, linear regression, the relationship between variables is explored using a straight line, described by the equation:
  • \( Y = a + bX \)
Here, \( Y \) represents the dependent variable, \( X \) is the independent variable, \( a \) is the y-intercept, and \( b \) is the slope of the line.
Regression analysis is crucial when you want to understand and quantify the influence of one variable on another. It helps in making predictions, identifying trends, and testing hypotheses. By assessing the relationship this way, researchers gain insights into patterns and mechanisms that drive data changes.
Sum of Squares of Residuals
The sum of squares of residuals, often abbreviated as \( SS_{\text{residual}} \), is a key component in evaluating how well a regression model fits the data. Residuals are the differences between observed values and the values predicted by the regression model. The formula for these residuals is:
  • \( e = Y - \hat{Y} \)
where \( e \) represents the residual for each observation, \( Y \) is the actual observed value, and \( \hat{Y} \) is the predicted value.
  • The sum of squares of these residuals is calculated to assess the total deviation of data points from the regression line, given by:\[SS_{\text{residual}} = \sum (Y_i - \hat{Y}_i)^2\]
This metric is critical because it quantifies the variance that is not explained by the model, indicating how well the regression line actually fits the observed data. A smaller \( SS_{\text{residual}} \) value means better model fit, while a larger value indicates that the model needs improvement.
Degrees of Freedom
Degrees of freedom (df) in the context of regression analysis refer to the number of values in a calculation that are free to vary. This concept is crucial when calculating statistics like the standard error of estimate, as it adjusts for the constraints introduced by using estimated parameters. The formula for calculating degrees of freedom in a simple linear regression model is:
  • \( df = n - k \)
where \( n \) is the total number of data points, and \( k \) is the number of estimated parameters, which is usually 2 for simple linear regression (intercept and slope).
Degrees of freedom impact how we understand variability in data. They adjust calculations to prevent overfitting by acknowledging that more parameters in the model consume more of the 'freedom' in the data. The correct calculation of degrees of freedom ensures that statistical tests produce reliable inference from the data analysis.

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Most popular questions from this chapter

A forensic psychologist tests the extent to which the age of a criminal \((X)\) predicts the age of the victim ( \(Y\) for nonviolent crimes. The psychologist uses the case files to record the age of five criminals and the age of the victim in those cases. The hypothetical data are listed in the following table. a. Compute the merhod of least squares to find the equation of the regression line. b. Use the regression equation to determine the predicted age of a victim of a nomviolent crime when the criminal is 20 years old.

Measuring procrastination. Chen, Dai, and Dong (2008) measured the relationship between scores on a revised version of the Aitken Procrastination Inventory (API) and actual procrastination among college students. Higher scores on the APl indicate greater procrastination. They found that procrastination \((Y)\) among college students could be predicted by API scores \((X)\) using the following regression equation: \(\hat{Y}=0.146 X=2.922\). Fstimate procrastination when: a. \(X=30\) b. \(X=40\) c. \(X=50\)

Which is the predictor variable \((X)\) and which is the criterion variable \((Y)\) for each of the following examples? a. A researcher tests whether the sine of an audience can predict the number of mistakes a student makes during a classroom presentation. b. A military officer tests whether the duration of an overseas tour can predict the morale among troops averseas. c. A social prychologist tests whether the size of a toy in cereal boxes can predict preferences for thar cereal.

Explain why it is necessary to square the deviation of each data point from the regression line to compure the method of least squares.

For each of the following regression equations, explain how the crirerion variable \((Y)\) changes as the predictor variable \((X)\) increases. Hint: You can find the answer by looking at the equation. a. \(\hat{Y}=-3.02 X-0.90\) b. \(\hat{Y}=0.75 X-2.40\) c. \(\hat{Y}=2.10 X+10\) d. \(\hat{Y}=-3.14 X+12\)

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