/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 63 A horizontal platform \(P\) is h... [FREE SOLUTION] | 91Ó°ÊÓ

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A horizontal platform \(P\) is held by several rigid bars that are connected to a vertical wire. The period of oscillation of the platform is found to be 2.2 s when the platform is empty and 3.8 s when an object \(A\) of unknown moment of inertia is placed on the platform with its mass center directly above the center of the plate. Knowing that the wire has a torsional constant \(K=27 \mathrm{N} \cdot \mathrm{m} / \mathrm{rad}\), determine the centroidal moment of inertia of object \(A\).

Short Answer

Expert verified
The centroidal moment of inertia of object \( A \) is approximately 5.52 kg·m².

Step by step solution

01

Understanding the Problem

We are given the oscillation periods of the platform both empty and with an object. The task is to find the moment of inertia of the object. We know the torsional constant of the wire.
02

Oscillation Period Formula

The period of oscillation for a torsional system is given by the formula: \[ T = 2\pi \sqrt{\frac{I}{K}} \] where \( T \) is the period, \( I \) the moment of inertia, and \( K \) the torsional constant.
03

Calculating Platform's Moment of Inertia

Using the given period of 2.2 s for the empty platform, plug into the formula:\[ 2.2 = 2\pi \sqrt{\frac{I_{P}}{27}} \]Solve for \( I_{P} \):\[ I_{P} = \frac{27 \times (2.2)^2}{4\pi^2} \] Evaluating gives us \( I_{P} \approx 4.25 \) kg·m².
04

Calculating Combined Moment of Inertia

For the period of 3.8 s with the object, use the same formula:\[ 3.8 = 2\pi \sqrt{\frac{I_{P} + I_{A}}{27}} \]Solve for \( I_{P} + I_{A} \):\[ I_{P} + I_{A} = \frac{27 \times (3.8)^2}{4\pi^2} \] Evaluating gives us \( I_{P} + I_{A} \approx 9.77 \) kg·m².
05

Solve for Object's Moment of Inertia

Subtract the platform's moment of inertia from the combined moment of inertia to find the object's moment of inertia:\[ I_{A} = 9.77 - 4.25 \]Calculate to find \( I_{A} \approx 5.52 \) kg·m².

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Moment of Inertia
The moment of inertia is a key concept in rotational dynamics and it measures an object's resistance to changes in its rotation. Think of it as similar to mass in linear motion. It depends on the mass distribution of the object. An object further from the axis of rotation has a larger moment of inertia. This is why a figure skater can spin faster when pulling in their arms. In this exercise, we focus on an object placed on a platform, where its moment of inertia affects the torsional oscillation period of the system. A greater moment of inertia means the object requires more torque to achieve the same angular acceleration. It's calculated about a specific axis, often the axis around which the object rotates.
The Role of Torsional Constant
The torsional constant, denoted as \( K \), is crucial in determining how a material or wire twists under applied torque. It is similar to stiffness in linear systems, representing the wire's resistance to being twisted. The constant is measured in units like Newton meters per radian (N·m/rad).In our example, the constant is given as 27 N·m/rad for the wire involved. It helps us understand how much the wire will twist when a moment (or torque) is applied. Using the torsional constant, we can analyze the wire's behavior and predict the oscillation pattern when the object is added to or removed from the platform.
Explaining Oscillation Period
The oscillation period is the time it takes for a system to complete one full cycle of motion. In a torsional system, like the one in the exercise, it depends on both the torsional constant and the moment of inertia. The formula \( T = 2\pi \sqrt{\frac{I}{K}} \) comes into play here, where \( T \) is the oscillation period, \( I \) is the moment of inertia, and \( K \) is the torsional constant. Understandably, if the moment of inertia increases, the oscillation period also increases, which is observed when additional mass (or moment of inertia) is added to the platform. This relationship helps us calculate the unknown moment of inertia by measuring the change in period.
Centroidal Moment of Inertia Insights
The centroidal moment of inertia is specific to the axis passing through the centroid (center of mass) of the object and is fundamental in analyzing rotational dynamics. It reflects how the object's mass is distributed around its center. In the exercise, the object's mass center is directly above the platform's center. This means the computations use the centroidal moment of inertia in the formula for rotational systems. Finding this specific moment of inertia allows understanding how the object will behave rotationally when interacting with other components (such as the platform). It is key in numerous applications, from mechanical engineering to physics, enhancing our understanding of rotational behavior.

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Most popular questions from this chapter

The \(100-\) -lb platform \(A\) is attached to springs \(B\) and \(D,\) each of which has a constant \(k=120 \mathrm{lb} / \mathrm{ft}\). Knowing that the frequency of vibration of the platform is to remain unchanged when an \(80-\) -lb block is placed on it and a third spring \(C\) is added between springs \(B\) and \(D,\) determine the required constant of spring \(C .\)

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