/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 25 The \(100-\) -lb platform \(A\) ... [FREE SOLUTION] | 91Ó°ÊÓ

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The \(100-\) -lb platform \(A\) is attached to springs \(B\) and \(D,\) each of which has a constant \(k=120 \mathrm{lb} / \mathrm{ft}\). Knowing that the frequency of vibration of the platform is to remain unchanged when an \(80-\) -lb block is placed on it and a third spring \(C\) is added between springs \(B\) and \(D,\) determine the required constant of spring \(C .\)

Short Answer

Expert verified
The constant for spring C must be 200 lb/ft.

Step by step solution

01

Define Old System Parameters

Define the parameters for the old system with only springs \(B\) and \(D\). The total mass of the system is given as the platform's weight, divided by gravity to convert to mass: \(m = \frac{100 \text{ lb}}{32.2 \text{ ft/s}^2}\). The spring constants for both springs \(B\) and \(D\) are \(k = 120 \text{ lb/ft}\). Since the mass is in weight units, we consider the system to include spring and mass as \(m = \frac{100}{32.2} = 3.11 \text{ slugs}\).
02

Calculate Original Frequency

For the original system, the natural frequency \(\omega_n\) can be determined using \(\omega_n = \sqrt{\frac{k_{eq}}{m}}\), where \(k_{eq} = k_B + k_D = 240 \text{ lb/ft}\). Calculate \(\omega_n\):\[\omega_{n,\text{original}} = \sqrt{\frac{240}{3.11}} = 8.81 \ \text{rad/s}\].
03

Define New System Parameters

Now consider the new system where an 80 lb block is added, implying total weight \(180 \text{ lb}\), hence mass \(m = \frac{180}{32.2} = 5.59 \text{ slugs}\). The system remains under the influence of springs \(B, D,\) and the additional spring \(C\).
04

Calculate Required \(k_C\) for Same Frequency

To maintain the original frequency, the effective spring constant must match the modified mass. Use the equation for frequency:\[\omega_{n} = \sqrt{\frac{k_{eq}}{m}}, \]equating \(\omega_{n,\text{original}} = \omega_{n,\text{new}}\), we have \[8.81 = \sqrt{\frac{k_B + k_D + k_{C}}{5.59}}.\]Solving for \(k_C\):\[k_C = (5.59 \times 8.81^2) - 240 = 200 \text{ lb/ft}.\]
05

Conclusion

Thus, the required spring constant for spring \(C\) to maintain the same frequency when the block is added is \(k_C = 200 \text{ lb/ft}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Spring Constant
The spring constant, denoted as \( k \), measures how stiff a spring is. It is a crucial parameter in vibration analysis and is expressed in units of force per unit length, such as pounds per foot (\( \text{lb/ft} \)). A higher spring constant means the spring is stiffer, while a lower value indicates more flexibility. Understanding the spring constant helps predict how a spring behaves under load.
A spring's behavior in a mass-spring system is governed by Hooke's Law, which stipulates that the force \( F \) exerted by the spring is proportional to the displacement \( x \) from its equilibrium position: \( F = k \, x \). This relationship is linear for ideal, elastic springs, allowing engineers and scientists to accurately model and analyze systems like the platform in our exercise.
When multiple springs act together, their combined effect on the system can be considered by calculating the equivalent spring constant \( k_{eq} \). If springs are in series or parallel, their respective constants can be combined using specific formulas to determine \( k_{eq} \). This concept is pivotal in adjusting spring configurations, like adding an extra spring \( C \), to achieve desired vibration properties.
Natural Frequency
Natural frequency is a fundamental concept in vibration analysis. It is the specific frequency at which a system tends to oscillate in the absence of any external forces other than its inherent restoring force. For a mass-spring system, it depends on both the mass of the system and the spring constant. It is calculated using the formula \( \omega_n = \sqrt{\frac{k_{eq}}{m}} \), where \( k_{eq} \) is the effective spring constant, and \( m \) is the mass of the system.
The units of natural frequency are typically in radian per second (\( \text{rad/s} \)). In our scenario, maintaining the original natural frequency when the mass of the system is changed demands a corresponding adjustment in the spring configuration. This involves solving for the new spring constants, like determining the value of \( k_C \) in the added spring \( C \), to compensate for the increased mass without altering the desired frequency.
Understanding natural frequency helps designers avoid resonance, a scenario where external vibrations match the natural frequency, potentially causing large, damaging oscillations.
Mass-Spring System
A mass-spring system is a classic model used to understand and predict dynamic behavior in engineering. This system includes a mass attached to one or more springs and can undergo simple harmonic motion if displaced from its equilibrium position.
The fundamental parameters defining a mass-spring system are the mass \( m \) and the spring constant \( k \). In scenarios where multiple springs are involved, as in our exercise, calculating the equivalent spring constant \( k_{eq} \) becomes essential. This equivalent constant dictates the overall stiffness of the combined springs. When a mass-spring system is analyzed, the primary focus is usually on its natural frequency and how the system responds to forces.
In our exercise, the system initially has a platform mass with two springs but then experiences an added mass from the block. To keep the system's response unchanged, we adjust by introducing a third spring. Such modifications highlight the interplay between mass and spring configuration, a key aspect of vibration maintenance and analysis.
Frequency Maintenance
Frequency maintenance refers to ensuring that a system sustains a desired frequency of vibration despite changes in system parameters like mass or spring configuration. In the context of our exercise, adding an \(80\)-lb block alters the total mass of the system, potentially changing its natural frequency.
The concept involves strategic adjustment of spring constants or configurations to counterbalance changes in mass. By calculating the appropriate spring constant for the additional spring, \( k_C \), we are able to maintain the same vibration frequency as before, even with the added mass.
This task underscores the importance of understanding the underlying principles of vibration analysis. Proper frequency maintenance prevents undesired alterations in system behavior, ensuring stability and performance. This knowledge is vital in real-world applications such as designing stable structures or machinery that must endure varied operational conditions without succumbing to resonance or unwanted vibrations.

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Most popular questions from this chapter

A \(91-\) kg machine element supported by four springs, each of constant \(k=175 \mathrm{N} / \mathrm{m},\) is subjected to a periodic force of frequency \(0.8 \mathrm{Hz}\) and amplitude \(89 \mathrm{N}\). Determine the amplitude of the fluctuating force transmitted to the foundation if \((a)\) a dashpot with a coefficient of damping \(c=365 \mathrm{N} \cdot \mathrm{s} / \mathrm{m}\) is connected to the machine element and to the ground, \((b)\) the dashpot is removed.

A particle moves in simple harmonic motion. Knowing that the maximum velocity is \(200 \mathrm{mm} / \mathrm{s}\) and the maximum acceleration is \(4 \mathrm{m} / \mathrm{s}^{2},\) determine the amplitude and frequency of the motion.

The force-deflection equation for a nonlinear spring fixed at one end is \(F=1.5 x^{112}\) where \(F\) is the force, expressed in newtons, applied at the other end and \(x\) is the deflection expressed in meters. (a) Determine the deflection \(x_{0}\) if a 4 -oz block is suspended from the spring and is at rest. (b) Assuming that the slope of the force-deflection curve at the point corresponding to this loading can be used as an equivalent spring constant, determine the frequency of vibration of the block if it is given a very small downward displacement from its equilibrium position and released.

A 150 -kg electromagnet is at rest and is holding \(100 \mathrm{kg}\) of scrap steel when the current is turned off and the steel is dropped. Knowing that the cable and the supporting crane have a total stiffiness equivalent to a spring of constant \(200 \mathrm{kN} / \mathrm{m}\), determine \((a)\) the frequency, the amplitude, and the maximum velocity of the resulting motion, \((b)\) the minimum tension that will occur in the cable during the motion, \((c)\) the velocity of the magnet 0.03 s after the current is turned off.

A half section of a uniform cylinder of radius \(r\) and mass \(m\) rests on two casters \(A\) and \(B,\) each of which is a uniform cylinder of radius \(r / 4\) and mass \(m / 8\). Knowing that the half cylinder is rotated through a small angle and released and that no slipping occurs, determine the frequency of small oscillations.

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