/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 52 A \(1400-\mathrm{kg}\) automobil... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A \(1400-\mathrm{kg}\) automobile starts from rest and travels \(400 \mathrm{m}\) during a performance test. The motion of the automoile is defined by the relation \(a=3.6 e^{-0.0005 x}\), where \(a\) and \(x\) are expressed in \(\mathrm{m} / \mathrm{s}^{2}\) and meters, respectively. The magnitude of the aerodynamic drag is \(D=0.35 v^{2},\) where \(D\) and \(v\) are expressed in newtons and \(\mathrm{m} / \mathrm{s}\), respectively. Determine the power dissipated by the aerodynamic drag when ( \(a) x=200 \mathrm{m},(b) x=400 \mathrm{m} .\)

Short Answer

Expert verified
Power at \(x=200\,\mathrm{m}\) is \(276977.6\,\mathrm{W}\); at \(x=400\,\mathrm{m}\), \(186827.4\,\mathrm{W}\).

Step by step solution

01

Determine Acceleration Function

Given the relation \(a = 3.6 e^{-0.0005 x}\), it defines the acceleration of the vehicle as a function of the distance \(x\). We will use this relation to calculate the velocity function later on.
02

Find Velocity Function

To find velocity as a function of \(x\), we can use the relation between acceleration, velocity, and displacement. The velocity \(v\) is found by integrating the acceleration function:\[a = v \frac{dv}{dx} = 3.6 e^{-0.0005 x}\]Integrate both sides to get the velocity expression:\[\int v\ dv = \int 3.6 e^{-0.0005 x}\ dx\]This gives:\[\frac{v^2}{2} = -\frac{3.6}{0.0005} e^{-0.0005 x} + C\]Where \(C\) is the constant of integration. Given the initial condition \(v = 0\) at \(x = 0\), solve for \(C\):\[0 = -7200 e^{0} + C \Rightarrow C = 7200\] Therefore, the velocity function becomes:\[v^2 = 14400 - 7200 e^{-0.0005 x} \]
03

Solve for Velocity at Specific Points

Substitute \(x = 200\) and \(x = 400\) into the velocity equation:1. At \(x = 200\):\[v^2 = 14400 - 7200 e^{-0.0001} \Rightarrow v^2 = 14400 - 7200(0.8187) \approx 8559.6 \Rightarrow v \approx \sqrt{8559.6} \approx 92.52 \, \mathrm{m/s}\]2. At \(x = 400\):\[v^2 = 14400 - 7200 e^{-0.0002} \Rightarrow v^2 = 14400 - 7200(0.67032) \approx 6582.7 \Rightarrow v \approx \sqrt{6582.7} \approx 81.14 \, \mathrm{m/s}\]
04

Calculate Aerodynamic Drag

Drag force \(D\) is given by the equation \(D = 0.35 v^2\). Substitute the previously found velocities:1. At \(x = 200\):\[D = 0.35 \times 92.52^2 \approx 0.35 \times 8559.6 \approx 2995.86 \, \mathrm{N}\]2. At \(x = 400\):\[D = 0.35 \times 81.14^2 \approx 0.35 \times 6582.7 \approx 2303.95 \, \mathrm{N}\]
05

Calculate Power of Aerodynamic Drag

Power \(P\) dissipated by aerodynamic drag is given by the product of drag force and velocity: \(P = D \cdot v\).1. At \(x = 200\):\[P = 2995.86 \times 92.52 \approx 276977.6 \, \mathrm{W} \]2. At \(x = 400\):\[P = 2303.95 \times 81.14 \approx 186827.4 \, \mathrm{W}\]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Acceleration Function
Understanding the acceleration function is a foundational step in analyzing the dynamics of an automobile's movement. In our exercise, the acceleration function is given as \(a = 3.6 e^{-0.0005 x}\), where \(a\) represents acceleration in meters per second squared, and \(x\) is the distance in meters. This equation tells us how acceleration changes as the vehicle travels further.
This particular exponential relationship implies that the acceleration decreases with distance. It is efficient at the beginning of the journey when \(x\) is small. As distance increases, the influence of the exponential decay becomes more significant, reducing the acceleration.
Understanding this function is crucial for deriving other aspects, like velocity, as it serves as the rate of change of velocity with respect to distance.
Velocity Function
The velocity function is essential for determining how fast the vehicle moves at different positions along its path. We can find this function by integrating the acceleration function.
Given the differential relationship \(a = v \frac{dv}{dx} = 3.6 e^{-0.0005 x}\), we can derive the velocity function by solving:
  • Integrating both sides \(\int v\ dv = \int 3.6 e^{-0.0005 x}\ dx\).
  • This results in \(\frac{v^2}{2} = -\frac{3.6}{0.0005} e^{-0.0005 x} + C\), where \(C\) is a constant.
  • Using the initial condition \(v = 0\) when \(x = 0\), we solve for \(C\) and find \(C = 7200\).
  • Thus, \(v^2 = 14400 - 7200 e^{-0.0005 x}\).
This expression allows us to compute velocity at any point \(x\), giving insights into the car's speed dynamics throughout the test.
Power Dissipation
Power dissipation is a measure of how much energy is lost due to aerodynamic drag as the vehicle moves. Aerodynamic drag is calculated as \(D = 0.35 v^2\), and is dependent on the velocity of the automobile.
At specific points, we can calculate the drag force and then determine the power dissipated using the formula \(P = D \cdot v\). For instance:
  • At \(x = 200\) m: With a velocity \(v \approx 92.52 \) m/s, we find \(D \approx 2995.86 \) N and \(P \approx 276977.6 \) W.
  • At \(x = 400\) m: With a velocity \(v \approx 81.14 \) m/s, \(D \approx 2303.95 \) N and \(P \approx 186827.4 \) W.
This calculation highlights how aerodynamic drag significantly affects energy consumption, particularly at higher velocities.
Performance Test
A performance test evaluates and compares the various dynamics of a vehicle, such as speed, acceleration, and power efficiency. In our exercise, the focus is on understanding how different factors, especially aerodynamic drag, affect the automobile's performance.
Through this test:
  • We start by computing the acceleration function to understand initial capabilities.
  • We then derive the velocity function to ascertain speed dynamics over distance.
  • Finally, we evaluate power dissipation to grasp the energy loss due to aerodynamic drag.
Such tests are crucial for engineers to optimize designs, ensuring vehicles perform efficiently in real-world conditions. Understanding each element aids in anticipating and addressing potential issues before they arise.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A 5 -kg sphere is dropped from a height of \(y=2 \mathrm{m}\) to test newly designed spring floors used in gymnastics. The mass of the floor section is \(10 \mathrm{kg}\), and the effective stiffness of the floor is \(k=120 \mathrm{kN} / \mathrm{m}\). Knowing that the coefficient of restitution between the ball and the platform is \(0.6,\) detrmine \((a)\) the height \(h\) reached by the sphere after rebound, \((b)\) the maximum force in the springs.

A 4-lb collar can slide without friction along a horizontal rod and is released from rest at A. The undeformed lengths of springs BA and CA are 10 in. and 9 in., respectively, and the constant of each spring is 2800 lb/in. Determine the velocity of the collar when it has moved 1 in. to the right.

A 25 -ton railroad car moving at \(2.5 \mathrm{mi} / \mathrm{h}\) is to be coupled to a 50 -ton car that is at rest with locked wheels \(\left(\mu_{k}=0.30\right) .\) Determine \((a)\) the velocity of both cars after the coupling is completed, (b) the time it takes for both cars to come to rest.

A meteor starts from rest at a very great distance from the earth. Knowing that the radius of the earth is 6370 km and neglecting all forces except the gravitational attraction of the earth, determine the speed of the meteor (a) when it enters the ionosphere at an altitude of 1000 km, (b) when it enters the stratosphere at an altitude of 50 km, (c) when it strikes the earth’s surface.

A ballistic pendulum is used to measure the speed of high-speed projectiles. A \(6-\mathrm{g}\) bullet \(A\) is fired into a \(1-\mathrm{kg}\) wood block \(B\) suspended by a cord with a length of \(l=2.2 \mathrm{m}\). The block then swings through a maximum angle of \(\theta=60^{\circ} .\) Determine \((a)\) the initial speed of the bullet \(v_{0},(b)\) the impulse imparted by the bullet on the block, \((c)\) the force on the cord immediately after the impact.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.